Chapter 9: Q. 9.112 (page 318)

What is the final volume, in milliliters, when $5.00 mL$ of each of the following solutions is diluted to provide the given concentration? $(9.5)$
a. localid="1653294892486" $20.0 % (m / v) NaOH$ solution to give a $4.00 % (m / v) NaOH$ solution
b. $0.600 M NaOH$ the solution to give a $0.100 M NaOH$ solution
c. $16.0 % (m / v) NaOH$ solution to give a $2.00 % (m / v) NaOH$ solution

Short Answer

Expert verified

a. The final volume of $20.0 % (m / v) NaOH$ solution to give a $4.00 % (m / v) NaOH$ solution is $25.0 mL$ .

b. The final volume of $0.600 M NaOH$ solution to give a $0.100 M NaOH$ solution is $30.0 mL$ .

c. The final volume of $16.0 % (m / v) NaOH$ solution to give a $2.00 % (m / v) NaOH$ solution is $40.0 mL$ .

Step by step solution

Part (a) Step 1: Given Information

$20.0 % (m / v) NaOH$ solution to give a $4.00 % (m / v) NaOH$ solution.

Part (a) Step 2: Explanation

Now,

Using the concentration formula-

$C_{1} V_{1} = C_{2} V_{2} V_{2} = \frac{C_{1} V_{1}}{C_{2}} V_{2} = \frac{(20.0 % (m / v) NaOH solution) (5.00 mL)}{4.00 % (m / v) NaOH sloution} V_{2} = 25.0 mL$

Hence the final volume is $25 m l$

Part (b) Step 1: Given Information

$0.600 M NaOH$ solution to give a $0.100 M NaOH$ solution.

Part (b) Step 2: Explanation

Now,

Using the concentration formula-

$C_{1} V_{1} = C_{2} V_{2} V_{2} = \frac{C_{1} V_{1}}{C_{2}} V_{2} = \frac{(0.600 M HCl solution) (5.00 mL)}{0.100 M HCl sloution} V_{2} = 30.0 mL$

Hence the final volume is $30 m l$

Part (c) Step 1: Given Information

$16.0 % (m / v) NaOH$ solution to give a $2.00 % (m / v) NaOH$ solution.

Part (c) Step 2: Explanation

Now,

Using the concentration formula-

$C_{1} V_{1} = C_{2} V_{2} V_{2} = \frac{C_{1} V_{1}}{C_{2}} V_{2} = \frac{(16.0 % (m / v) NaOH solution) (5.00 mL)}{2.00 % (m / v) NaOH sloution} V_{2} = 40.0 mL$