An intravenous solution of mannitol is used as a diuretic to increase the loss of sodium and chloride by a patient. If a patient receives 30.0mLof a 25%(m/v)mannitol solution, how many grams of mannitol were given?

Short Answer

Expert verified

As an outcome, the patient's necessary mannitol mass is 7.5g.

Step by step solution

01

Introduction.

Every diuretic works on a separate portion of your kidneys. Some drugs contain and over one kind of diuretic or a diuretics in concert with some other heart rate drug.

02

Given data.

Using the mass by volume percent equation, determine the mass of mannitol.

Massvolumepercent(m/v)=massofsolutevolumeofsolution×100%

Volume of injectable mannitol liquid delivered to the patient30.0mL. Mass /volume percent of mannitol solution 25%(m/v), which equals 25mL, as per the problem.

03

Explanation.

In the provided phrase, substitute the above values.

Massvolumepercent(m/v)=massofsolutevolumeofsolution×100%

25%=massofsolute30mL×100%

Massofsolute=7.5g

As a result, the patient needs 7.5gof mannitol.

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