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Chapter 12: Problem 4

Yeast (Saccharomyces cerevisiae) has a genome size of \(1.21 \times 10^{7}\) bp. If a genomic library of yeast DNA was constructed in a vector capable of carrying 16 -kbp inserts, how many individual clones would have to be screened to have a \(99 \%\) probability of finding a particular fragment?

Short Answer

Expert verified
Approximately 3493 clones need to be screened to find a particular fragment with 99% probability.

Step by step solution

01

Determine Total Number of Fragments

Firstly, calculate the total number of 16-kbp fragments (clones) in the yeast genome. This can be calculated as the total number of base pairs divided by the base pairs that each clone can carry. Calculation: Total fragments, \(N = \frac{total\ genome\ size}{size\ of\ each\ fragment} = \frac{1.21 \times 10^{7}}{16 \times 10^{3}} = 756.25. Always round up to the nearest whole as you cannot have .25 of a DNA fragment. So you would have 757 fragments.
02

Probability Calculation

To calculate the number of clones needed to screen to have a guaranteed \(99\%\) chance of finding a specific fragment of yeast DNA, use the formula for successive probability: \[1 - (1 - \frac{1}{N})^n = p\]Where:N is the total number of fragments,n is the number of clones that need to be screened,p is the desired probability (here, \(0.99\)).Rearrange this function for n, giving \[ n = \log_{(1-\frac{1}{N})} (1-p) \] and then plug in the values to get \(n\).
03

Plug in Values

Replace \(N\) with 757 and \(p\) with \(0.99\) in \[ n = \log_{(1-\frac{1}{757})} (1-0.99) \]After calculating this, you will end up with approximately n ≈ 3493. Therefore, you would need to screen around 3493 clones to have a 99% probability of finding a particular yeast DNA fragment.

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Most popular questions from this chapter

A vector has a polylinker containing restriction sites in the following order: Hind III, SacI, XhoI, BglII, XbaI, and ClaI. a. Give a possible nucleotide sequence for the polylinker. b. The vector is digested with Hind III and ClaI. A DNA segment contains a Hind III restriction site fragment 650 bases upstream from a ClaI site. This DNA fragment is digested with Hind III and \(C l a I,\) and the resulting Hind III-ClaI fragment is directionally cloned into the Hind III-Clal-digested vector. Give the nucleotide sequence at each end of the vector and the insert and show that the insert can be cloned into the vector in only one orientation.

Search the National Center for Biotechnology Information (NCBI) website at http://www. nchi.nlm. nih.gov/sites/entrez?db=Genome to discover the number of organisms whose genome sequences have been completed. Explore the rich depository of sequence information available here by selecting one organism from the list and browsing through the contents available.

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