(Integrates with Chapter \(3 .)\) Triose phosphate isomerase catalyzes the conversion of dihydroxyacetone-P to glyceraldehyde-3-P. The standard free energy change, \(\Delta G^{\circ}\) ', for this reaction is \(+7.6 \mathrm{kJ} / \mathrm{mol}\). However, the observed free energy change \((\Delta G)\) for this reaction in erythrocytes is \(+2.4 \mathrm{kJ} / \mathrm{mol}\) a. Calculate the ratio of [dihydroxyacetone-P]/ [glyceraldehyde-3-P] in erythrocytes from \(\Delta G\) b. If [dihydroxyacetone-P] \(=0.2 \mathrm{m} M\), what is [glyceraldehyde-3-P]?

Short Answer

Expert verified
a. The ratio [glyceraldehyde-3-P]/ [dihydroxyacetone-P] in erythrocytes from \(\Delta G\) is approximately \(e^{-5200/(8.314x298)}\).b. The concentration of glyceraldehyde-3-P when [dihydroxyacetone-P] = 0.2 mM is 0.2 mM x \(e^{-5200/(8.314x298)}\).

Step by step solution

01

Equation Setup

The relationship between the Gibbs free energy change and the ratio of products/reactants concentration at equilibrium is given by the equation: \(\Delta G = \Delta G^{\circ}\) ' + \(RTln[\text{{Products}]/\text{{Reactants}}]\). According to the question, the reaction we are considering is dihydroxyacetone-P converting to glyceraldehyde-3-P. So the products become glyceraldehyde-3-P and reactants become dihydroxyacetone-P in the equation.
02

Inserting given values into the free energy change equation

Firstly, convert the given \(\Delta G\) and \(\Delta G^{\circ}\) ' values from kJ to J (1 kJ = 1000 J) and insert them into the equation: \(2400 = 7600 + 8.314 \times 298 \times ln[\text{{glyceraldehyde-3-P}]/\text{{dihydroxyacetone-P}}]\)
03

Solve the equation for the ratio

Next, rearrange the equation to solve for the ratio of [glyceraldehyde-3-P]/ [dihydroxyacetone-P]: \(-5200/ (8.314 x 298) = ln[\text{{glyceraldehyde-3-P}]/\text{{dihydroxyacetone-P}}]\)
04

Convert from natural logarithm to ratio

Finally, convert the natural logarithm to the ratio using the exponential function: \([\text{{glyceraldehyde-3-P}}]/ [\text{{dihydroxyacetone-P}}] = e^{-5200/(8.314x298)}\).
05

Calculate the concentration of glyceraldehyde-3-P

Using the formula, if [dihydroxyacetone-P] = 0.2 mM, then [glyceraldehyde-3-P] = 0.2 mM x \(e^{-5200/(8.314x298)}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy Change
Gibbs Free Energy, denoted as \( \Delta G \), is a thermodynamic quantity that measures the amount of work that can be performed by a chemical reaction at constant temperature and pressure. Understanding \( \Delta G \) is crucial for analyzing biochemical reactions, as it helps determine whether a reaction can occur spontaneously.

A \( \Delta G \) value that is negative indicates a reaction that can proceed without the input of energy, known as an exergonic reaction. Conversely, a positive \( \Delta G \) suggests that additional energy is needed for the reaction to take place, and such reactions are termed endergonic.

In the case of triose phosphate isomerase reaction, the standard free energy change, \( \Delta G^{\circ} \) ', is given as +7.6 kJ/mol. This positive value suggests that the conversion from dihydroxyacetone-P to glyceraldehyde-3-P is not spontaneous under standard conditions. However, the actual free energy change \( \Delta G \) in erythrocytes is different because it depends on the concentrations of reactants and products in the cell, illustrating the importance of cellular context in biochemical energetics.
Equilibrium Constant Calculation
The equilibrium constant, denoted as \( K_{eq} \), is a dimensionless value that represents the ratio of products to reactants at equilibrium for a reversible reaction. It is derived from the relationship \( \Delta G = \Delta G^{\circ} \) ' + RTln[Products]/[Reactants], where R is the universal gas constant and T is the temperature in Kelvin. The natural logarithm of \( K_{eq} \) is directly proportional to the standard free energy change, \( \Delta G^{\circ} \) '.

Calculating \( K_{eq} \) allows one to predict the concentrations of reactants and products when the reaction has reached equilibrium.

Applying Equilibrium Concepts

In the erythrocyte example, the observed \( \Delta G \) is used to calculate the ratio [dihydroxyacetone-P]/[glyceraldehyde-3-P], which can then be employed to determine the individual concentrations at equilibrium. This process highlights how the energetics of a biochemistry reaction can inform and predict cellular chemical composition.
Biochemical Reaction Energetics
The energetics of a biochemical reaction encompass the energy changes associated with the conversion of reactants to products. Understanding these energetics requires consideration of both enthalpy changes and the entropy contribution to the free energy, as described by the Gibbs Free Energy equation.

In biochemistry, the energy content of molecules and how it changes during a reaction provides insights into how likely a reaction is to proceed and with what efficiency. For the triose phosphate isomerase reaction, the difference between the standard free energy change \( \Delta G^{\circ} \) ' under standard conditions and the actual free energy change \( \Delta G \) in erythrocytes reflects how cellular environments alter reaction energetics.

Factors like reactant and product concentrations, pH, and the presence of other cellular components can significantly influence the energy profile of a reaction.

Practical Considerations in Metabolism

The insights gleaned from studying the energetics of triose phosphate isomerase illustrate the importance of understanding enzymatic roles in metabolic pathways, which in turn affect biological processes like energy production and utilization.

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