Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 18: Problem 19

As noted on page 556 , the galactose- 1 -phosphate uridylyltransferase reaction proceeds via a ping-pong mechanism. Consult Chapter 13 page \(406,\) to refresh your knowledge of ping-pong mechanisms, and draw a diagram to show how a ping-pong mechanism would proceed for the uridylyltransferase.

Short Answer

Expert verified
The ping-pong mechanism of the Galactose-1-phosphate Uridylyltransferase enzyme involves the enzyme binding to the first substrate (UTP), releasing a product (PPi), and forming an intermediate complex (enzyme-UMP). This enzyme-UMP intermediate then reacts with the second substrate (Galactose-1-phosphate) to form the final product, UDP-Galactose.

Step by step solution

01

Understand the Ping-Pong Mechanism

Start by revising the concept of the ping-pong mechanism from the suggested resource: Chapter 13, page 406. In this mechanism, the enzyme reacts with the first substrate to generate an enzyme-intermediate complex. This intermediate complex then reacts with the second substrate leading to the formation of the final product.
02

Identify the Substrates in Galactose-1-phosphate Uridylyltransferase Reaction

Understand that for the enzyme Galactose-1-phosphate Uridylyltransferase, the two substrates are the Galactose-1-phosphate and UTP (Uridine Triphosphate). The enzyme, in its active form, first interacts with UTP and releases Pyrophosphate (PPi). This produces a UMP-enriched enzyme intermediate.
03

Draw the Ping-Pong Mechanism Diagram

Now, draw the ping-pong mechanism using the information gathered so far. Start with the enzyme binding to UTP, then the release of PPi, the formation of the enzyme-UMP intermediate, the intermediate's reaction with Galactose-1-phosphate, and finally the release of UDP-Galactose.
04

Label the Diagram

Make sure to label all the elements of your diagram: the enzyme, the substrates, the intermediate, and the products.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Discuss the cycling of NADH and NAD \(^{+}\) in glycolysis and the related fermentation reactions.

Genetic defects in glycolytic enzymes can have serious consequences for humans. For example, defects in the gene for pyruvate kinase can result in a condition known as hemolytic anemia. Consult a reference to learn about hemolytic anemia, and discuss why such genetic defects lead to this condition.

What would be the consequences of a \(\mathrm{Mg}^{2+}\) ion deficiency for the reactions of glycolysis?

(Integrates with Chapter \(3 .)\) The standard free energy change \(\left(\Delta G^{\circ \prime}\right)\) for hydrolysis of fructose- 1,6 -bisphosphate (FBP) to fructose6-phosphate (F-6-P) and \(\mathrm{P}_{\mathrm{i}}\) is \(-16.7 \mathrm{kJ} / \mathrm{mol}\) \\[ \mathrm{FBP}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \text { fructose- } 6-\mathrm{P}+\mathrm{P}_{\mathrm{i}} \\] The standard free energy change \(\left(\Delta G^{\circ \prime}\right)\) for ATP hydrolysis is \(-30.5 \mathrm{kJ} / \mathrm{mol}\) \\[ \mathrm{ATP}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ADP}+\mathrm{P}_{\mathrm{i}} \\] a. What is the standard free energy change for the phosphofructokinase reaction: \\[ \text { ATP + fructose- } 6 \text { -P } \longrightarrow \mathrm{ADP}+\mathrm{FBP} \\] b. What is the equilibrium constant for this reaction? c. Assuming the intracellular concentrations of [ATP] and [ADP] are maintained constant at \(4 \mathrm{m}\) Mand \(1.6 \mathrm{m} M\), respectively, in a rat liver cell, what will be the ratio of [FBP]/[fructose-6-P] when the phosphofructokinase reaction reaches equilibrium?

Determine the anticipated location in pyruvate of labeled carbons if glucose molecules labeled (in separate experiments) with \(^{14} \mathrm{C}\) at each position of the carbon skeleton proceed through the glycolytic pathway
See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation

Kinetics

Read Explanation

Organic Chemistry

Read Explanation

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free