Calculate the \(\mathrm{pH}\) of the following. a. \(5 \times 10^{-4} \mathrm{MHCl}\) d. \(3 \times 10^{-2}\) M KOH b. \(7 \times 10^{-5} M\) NaOH e. \(0.04 \mathrm{m} M \mathrm{HCl}\) c. \(2 \mu M\) HCl f. \(6 \times 10^{-9}\) M HCl

Short Answer

Expert verified
a. pH = 3.3, d. pH = 12.52, b. pH = 11.15, e. pH = 1.4, c. pH = 6.7, f. pH = 8.22. Remember that these values are approximate and can vary depending on the temperature of the solution.

Step by step solution

01

Calculate the concentrations of H+ and OH-

For HCl solutions a, e and f, the [H+] is equal to the given concentration of HCl. For basic solutions d and b, the [OH-] equals the concentration of the base.
02

Convert concentrations to pH or pOH

Use the formula for pH = -log10[H+] to calculate pH for acidic solutions. For basic solutions, use pOH = -log10[OH-] to convert OH- concentrations to pOH.
03

Convert pOH to pH for Basic Solutions

For basic solutions, use the formula pH = 14 - pOH to convert pOH values to pH.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Acid-Base Equilibrium
The science of acids and bases plays a critical role in understanding chemical reactions and biological processes. At the core of this topic is the concept of acid-base equilibrium, a state where the concentrations of acids (H+ ions) and bases (OH- ions) in a solution are stable.

To dive deeper into this equilibrium, we consider the ionization of acids and bases in water. Strong acids like HCl completely dissociate in water, contributing to an increase in H+ ion concentration. On the other hand, strong bases such as NaOH and KOH completely dissociate to yield OH- ions. The dissociation plays a pivotal role in determining the acidity or basicity of a solution.

This equilibrium is quantified by the equilibrium constant for water, known as the ion-product constant (Kw), which at 25°C is equal to 1.0 x 10-14. Understanding this constant helps us link the concentrations of H+ and OH- ions in a solution. It's essential to make these concepts clear because they lay the groundwork for pH calculations and subsequent problem-solving.
Decoding Molar Concentration in Solutions
When solving problems involving pH, it's important to understand molar concentration, a measure of the amount of a substance in a given volume of solution. It's represented by Molarity (M) and calculated as moles of solute per liter of solution.

In the context of our exercise, concentration is given directly for each substance, for instance,• 5 x 10-4 M HCl refers to 5 x 10-4 moles of HCl in one liter of solution.

This concept is crucial because the acid or base's molarity is directly used to determine the pH or pOH of the solution. For example, a 2 μM HCl solution indicates a highly dilute solution and consequently, a pH value closer to neutral. Remember that the unit μM stands for micromolar, which is equal to 10-6 M, and mM stands for millimolar, equal to 10-3 M. Correctly interpreting these units and converting them if necessary is imperative for accurate pH calculations.
The Interconnected pH and pOH Scale
The pH and pOH relationship is a central concept in understanding the acidity or basicity of solutions. pH stands for the 'power of hydrogen' and gives a measure of the acidity of a solution, while pOH gives a measure of its basicity.

The pH and pOH scales are inversely related and follow a simple mathematical relationship:
• pH + pOH = 14
This relationship is valid at 25°C, which is considered standard temperature for these calculations. In the given exercises, after calculating the [OH-] for basic solutions, we can find the pOH by taking the negative logarithm base 10 of the [OH-]. Then, by subtracting the pOH from 14, we get the pH of the solution. For example, if we have a pOH of 2, the pH would be 14 - 2 = 12, indicating a basic solution. Understanding the pH and pOH relationship is vital for effectively interpreting the results of acid-base reactions and making educated predictions about the behavior of solutions.

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Most popular questions from this chapter

Bicine is a compound containing a tertiary amino group whose relevant \(\mathrm{p} K_{\mathrm{a}}\) is 8.3 (Figure 2.17 ). Given \(1 \mathrm{L}\) of \(0.05 \mathrm{M}\) Bicine with its tertiary amino group in the unprotonated form, how much \(0.1 N \mathrm{HCl}\) must be added to have a Bicine buffer solution of \(\mathrm{pH} 7.5 ?\) What is the molarity of Bicine in the final buffer? What is the concentration of the protonated form of Bicine in this final buffer?

Shown here is the structure of triethanolamine in its fully protonated form: Its \(\mathrm{p} K_{\mathrm{a}}\) is \(7.8 .\) You have available at your lab bench \(0.1 \mathrm{M}\) solutions of \(\mathrm{HCl}, \mathrm{NaOH}\), and the uncharged (free base) form of triethanolamine, as well as ample distilled water. Describe the preparation of a 1 L solution of 0.05 M triethanolamine buffer, pH 7.6.

Given \(0.1 \mathrm{M}\) solutions of acetic acid and sodium acetate, describe the preparation of \(1 \mathrm{L}\) of \(0.1 \mathrm{M}\) acetate buffer at a pH of 5.4.

Tris-hydroxymethyl aminomethane (TRIS) is widely used for the preparation of buffers in biochemical research. Shown here is the structure of TRIS in its protonated form: Its acid dissociation constant, \(K_{\mathrm{a}},\) is \(8.32 \times 10^{-9} M .\) You have available at your lab bench a \(0.1 \mathrm{M}\) solution of TRIS in its protonated form, 0.1 \(M\) solutions of \(\mathrm{HCl}\) and \(\mathrm{NaOH}\), and ample distilled water. Describe the preparation of a 1 L solution of 0.02 M TRIS buffer, pH 7.8.

Given a solution of \(0.1 \mathrm{M}\) HEPES in its fully protonated form, and ready access to \(0.1 \mathrm{M} \mathrm{HCl}, 0.1 \mathrm{M} \mathrm{NaOH}\) and distilled water, describe the preparation of 1 L of 0.025 M HEPES buffer solution, \(\mathrm{pH} 7.8\)

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