a. If \(50 \mathrm{mL}\) of \(0.01 \mathrm{MHCl}\) is added to \(100 \mathrm{mL}\) of \(0.05 \mathrm{M}\) phosphate buffer at \(\mathrm{pH} 7.2,\) what is the resultant \(\mathrm{pH}\) ? What are the concentrations of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) and \(\mathrm{HPO}_{4}^{2-}\) in the final solution? b. If \(50 \mathrm{mL}\) of \(0.01 \mathrm{MNaOH}\) is added to \(100 \mathrm{mL}\) of \(0.05 \mathrm{M}\) phosphate buffer at \(\mathrm{pH} 7.2,\) what is the resultant \(\mathrm{pH}\) ? What are the concentrations of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) and \(\mathrm{HPO}_{4}^{2-}\) in this final solution?

Short Answer

Expert verified
The step by step method described above leads to the calculation of the final pH and concentrations of \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\) and \( \mathrm{HPO}_{4}^{2-}\) after the addition of an acid or a base to a phosphate buffer. The buffers resist changes in pH upon addition of acid or base due to their ability to consume or produce \(\mathrm{H}^{+}\) and \(\mathrm{OH}^{-}\) ions, thus maintaining a relatively constant pH.

Step by step solution

01

Calculation of final concentrations upon addition of \(0.01 \mathrm{MHCl}\)

Start by finding the mmols of \(\mathrm{HCl}\), \( \mathrm{HPO}_{4}^{2-}\), and \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\). From there calculate the mmols of \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\) and \( \mathrm{HPO}_{4}^{2-}\) after reactions, and divide by the total volume to get their new concentrations. Use the Henderson-Hasselbalch equation to get the new pH of the solution. Considering the reactions: \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-} + \mathrm{OH}^{-} -> \mathrm{H}_{2}\mathrm{O} + \mathrm{HPO}_{4}^{2-} \) and \( \mathrm{H}_{2}\mathrm{PO}_{4}^{-} + \mathrm{H}^{+} -> \mathrm{H}_{3}\mathrm{O}^{+} + \mathrm{H}_{2}\mathrm{PO}_{4}^{-} \)
02

Calculation of final concentrations upon addition of \(0.01 \mathrm{MNaOH}\)

Repeat the process of Step 1, but consider the mmols of \(\mathrm{NaOH}\) instead of \(\mathrm{HCl}\). Use the reactions: \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-} + \mathrm{OH}^{-} -> \mathrm{H}_{2}\mathrm{O} + \mathrm{HPO}_{4}^{2-} \) and \( \mathrm{HPO}_{4}^{2-} + \mathrm{H}^{+} -> \mathrm{H}_{2}\mathrm{O} + \mathrm{H}_{2}\mathrm{PO}_{4}^{-} \) to calculate the new mmols of \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\) and \( \mathrm{HPO}_{4}^{2-}\). Divide by total volume to get the new concentrations.
03

Calculation of new pH

Now that the final concentrations of \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\) and \( \mathrm{HPO}_{4}^{2-}\) are known after the addition of \(\mathrm{NaOH}\), use the Henderson-Hasselbalch equation to calculate the new pH of the solution.

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