Given a solution of \(0.1 \mathrm{M}\) HEPES in its fully protonated form, and ready access to \(0.1 \mathrm{M} \mathrm{HCl}, 0.1 \mathrm{M} \mathrm{NaOH}\) and distilled water, describe the preparation of 1 L of 0.025 M HEPES buffer solution, \(\mathrm{pH} 7.8\)

Short Answer

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Approximately 6 g of HEPES is needed to prepare 1 L of 0.025 M solution. Adjust the pH to 7.8 by adding 0.1M HCl or 0.1 M NaOH until reaching the desired pH. Then, adjust the final volume of the solution to 1 L using distilled water.

Step by step solution

01

Understanding the Concepts Involved

A buffer solution is a solution that can resist pH change upon the addition of an acidic or basic components. It has a significant ability to maintain stable pH levels. pH is a measure of hydrogen ion concentration and it is inversely proportional to the amount of H+ ions present. In addition, molarity indicates the concentration of a solution and it is defined as the number of moles of solute per liter of solution.
02

Calculation of the Amount of HEPES Required

In order to prepare 1 L of 0.025 M HEPES solution, the amount of HEPES required can be calculated using the formula: (Desired concentration/Volumetric flask size) * Molecular weight of HEPES = (0.025 mol/L / 1 L ) * 238.30 g/mol (molecular weight of HEPES) = 5.9575 g. Thus, approximately 6 g of HEPES is required.
03

Adjustment of pH

Since buffers resist changes in pH, we need to carefully adjust the pH to the required level of 7.8. This can be done by slowly adding 0.1 M HCl or 0.1 M NaOH and frequently monitoring the pH until it reaches the desired level. Which solution (HCl to lower pH or NaOH to increase pH) to add would typically depend on the initial pH of the solution, which isn't specified in this problem. In practice, this adjustment should be performed ensuring that the pH does not change drastically, if it does, distilled water should be added.
04

Adjustment of Volume

After the pH reaches the desired level, the final volume of the solution must be adjusted to 1 liter (or the intended final volume) using distilled water. It's important to add water slowly and mix well to ensure an evenly distributed concentration of the buffer throughout the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Buffer Solutions
A buffer solution plays a crucial role in numerous biological and chemical processes. It's essentially a water-based solution with a stable pH, rendering it impervious to slight pH changes despite the addition of moderate amounts of acidic or basic substances. To understand how it works, imagine a buffer as a sort of pH security guard: it 'absorbs' the excess hydrogen (H+) or hydroxide (OH-) ions, preventing drastic shifts in the environment's acidity or alkalinity. This is essential for processes sensitive to pH changes, such as enzymatic reactions in biological systems.

The efficacy of a buffer is hinged on its components: a weak acid and its conjugate base, or a weak base and its conjugate acid. HEPES, used in our exercise, is a zwitterionic buffering agent frequently utilized in biological and biochemical research due to its negligible metal ion binding, high chemical stability, and optimal buffering range (pH 6.8 to 8.2). To prepare a buffer, we need to understand and apply the concept of molarity and pH adjustment—integral parts of the buffer creation process.
The Process of pH Adjustment
Achieving the desired pH is a meticulous process that requires both precision and patience. When preparing a HEPES buffer, or any buffer for that matter, your goal is to create a solution with a specific pH value which, in this case, is 7.8.

To start, you'd need to measure the initial pH of the solution. If it's higher than desired, you'll add a strong acid like HCl. If it's lower, you'll introduce a strong base such as NaOH. The trick is to do it little by little—adding drop by drop and constantly stirring while monitoring the pH. It's like seasoning food to taste; you wouldn't pour the entire salt shaker in at once, right? Similarly, you adjust pH gradually to prevent 'overseasoning' your buffer. And if you do happen to go too far with the pH adjustment, distilled water is your best friend. It dilutes the solution, effectively bringing the pH closer to that sweet spot you're aiming for.
Molarity Calculation Made Simple
Molarity is a measurement of concentration that signifies the moles of a solute present in one liter of solution. It's indicated by the symbol 'M' and is calculated by the formula: \[ \text{Molarity (M)} = \frac{\text{Moles of solute}}{\text{Liters of solution}} \].

Let's apply this to our HEPES buffer example. With a desired final molarity of 0.025 M for a 1 L solution, we first identify how many moles of HEPES are needed using the formula:\[ \text{Moles} = \text{Molarity} \times \text{Liters}\]. Multiplying 0.025 M by 1 L yields 0.025 moles of HEPES. Then, to find the mass of HEPES required, we multiply the moles by the molar mass of HEPES (238.30 g/mol): \[ \text{Mass} = 0.025 \text{ moles} \times 238.30 \text{ g/mol}\], which gives us approximately 6 g of HEPES.

It is essential to perform these calculations correctly to ensure that the concentration of the buffer matches the specified molarity, which will ensure the buffer's effectiveness in maintaining the desired pH level.

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Most popular questions from this chapter

a. Draw the titration curve for Bicine, assuming the \(\mathrm{p} K_{\mathrm{a}}\) for its free COOH group is 2.3 and the \(\mathrm{p} K_{\mathrm{a}}\) for its tertiary amino group is 8.3 b. Draw the structure of the fully deprotonated form (completely dissociated form) of bicine. c. You have available a \(0.1 ~ M\) solution of Bicine at its isoelectric point \(\left(\mathrm{pH}_{\mathrm{I}}\right), 0.1 \mathrm{M}\) solutions of \(\mathrm{HCl}\) and \(\mathrm{NaOH}\), and ample distilled \(\mathrm{H}_{2} \mathrm{O}\) Describe the preparation of 1 L of 0.04 M Bicine buffer, pH 7.5 d. What is the concentration of fully protonated form of Bicine in your final buffer solution?

Bicine is a compound containing a tertiary amino group whose relevant \(\mathrm{p} K_{\mathrm{a}}\) is 8.3 (Figure 2.17 ). Given \(1 \mathrm{L}\) of \(0.05 \mathrm{M}\) Bicine with its tertiary amino group in the unprotonated form, how much \(0.1 N \mathrm{HCl}\) must be added to have a Bicine buffer solution of \(\mathrm{pH} 7.5 ?\) What is the molarity of Bicine in the final buffer? What is the concentration of the protonated form of Bicine in this final buffer?

Tris-hydroxymethyl aminomethane (TRIS) is widely used for the preparation of buffers in biochemical research. Shown here is the structure of TRIS in its protonated form: Its acid dissociation constant, \(K_{\mathrm{a}},\) is \(8.32 \times 10^{-9} M .\) You have available at your lab bench a \(0.1 \mathrm{M}\) solution of TRIS in its protonated form, 0.1 \(M\) solutions of \(\mathrm{HCl}\) and \(\mathrm{NaOH}\), and ample distilled water. Describe the preparation of a 1 L solution of 0.02 M TRIS buffer, pH 7.8.

When a \(0.1 \mathrm{M}\) solution of a weak acid was titrated with base, the following results were obtained: $$\begin{array}{cc}\begin{array}{c}\text { Equivalents of } \\\\\text { base added }\end{array} & \text { pH observed } \\\\\hline 0.05 & 3.4 \\\0.15 & 3.9 \\\0.25 & 4.2 \\\0.40 & 4.5 \\\0.60 & 4.9 \\\0.75 & 5.2 \\\0.85 & 5.4 \\\0.95 & 6.0\end{array}$$ Plot the results of this titration and determine the \(\mathrm{p} K_{\mathrm{a}}\) of the weak acid from your graph.

Given \(0.1 \mathrm{M}\) solutions of acetic acid and sodium acetate, describe the preparation of \(1 \mathrm{L}\) of \(0.1 \mathrm{M}\) acetate buffer at a pH of 5.4.

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