Write simple reaction mechanisms for the formation of cAMP from ATP by adenylyl cyclase and for the breakdown of cAMP to \(5^{\prime}\) -AMP by phosphodiesterases.

Short Answer

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ATP is converted to cAMP by the enzyme adenylyl cyclase through the removal and cyclization of a diphosphate group, resulting in cAMP and inorganic diphosphate (PPi). cAMP is then converted to 5'-AMP by the enzyme phosphodiesterase through the hydrolysis of the 3',5'-cyclic phosphate ester bond, resulting in 5'-AMP and a water molecule (H2O).

Step by step solution

01

Reaction Mechanism of ATP to cAMP by Adenylyl Cyclase

Adenylyl cyclase catalyzes the conversion of ATP to cAMP. ATP consists of an adenine ring, a ribose sugar, and three phosphate groups. Adenylyl cyclase acts by cleaving the bond between the second and third phosphate group of ATP. It then cyclizes the remaining diphosphate group on the ribose sugar, forming a cyclic phosphate ester to produce cAMP.
02

Illustration of the reaction

This can be illustrated in the following way: ATP \( \xrightarrow{{Adenylyl \, Cyclase}} \) cAMP + PPi, where PPi represents the released inorganic diphosphate.
03

Reaction Mechanism of cAMP to 5'-AMP by Phosphodiesterases

Phosphodiesterases catalyze the conversion of cAMP to 5'-AMP. They work by hydrolyzing the 3',5'-cyclic phosphate ester bond in cAMP to yield 5'-AMP.
04

Illustration of the reaction

This process can be illustrated as follows: cAMP \( \xrightarrow{{Phosphodiesterase}} \) 5'-AMP + H2O, where H2O is the water molecule used in the hydrolysis reaction.

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