Amino acid analysis of an octapeptide revealed the following composition: \(\begin{array}{llllll}\text { 2 Arg } & \text { 1 Gly } & \text { 1 Met } & \text { 1 Trp } & \text { 1 Tyr } & \text { 1 Phe } & \text { 1 Lys }\end{array}\) The following facts were observed: a. Edman degradation gave b. CNBr treatment yielded a pentapeptide and a tripeptide containing phenylalanine. c. Chymotrypsin treatment yielded a tetrapeptide containing a C-terminal indole amino acid and two dipeptides. d. Trypsin treatment yielded a tetrapeptide, a dipeptide, and free Lys and Phe. e. Clostripain yielded a pentapeptide, a dipeptide, and free Phe. What is the amino acid sequence of this octapeptide?

Short Answer

Expert verified
The amino acid sequence of the octapeptide is Trp-Arg-Gly-Lys-Met-Phe-Tyr-Arg

Step by step solution

01

Identify Protein Breakpoints

Identify where each treatment breaks the peptide chain. Edman degradation sequences a protein from the N-terminus, CNBr cleaves at Met, Trypsin cleaves at the C-term of Lys/Arg, Chymotrypsin cleaves at the C-term of Trp/Tyr/Phe, and Clostripain cleaves at the C-term of Arg.
02

Analyze CNBr Result

CNBr treatment results in a pentapeptide and a tripeptide containing Phe. It cleaves on the C-term of Met. So, Met separates a pentapeptide and a tripeptide in the sequence. We still do not know where these sequences are located in relation to each other, or their order within their respective peptides.
03

Analyze Trypsin Result

Trypsin treatment yielded a tetrapeptide, a dipeptide, and Lys and Phe as free amino acids. Trypsin cleaves at the C-term of Lys/Arg. This tells us that Lys is a C-term of a peptide, and one of Arg's is too. Since CNBr did not include Phe in the tripeptide, Phe must be located in the pentapeptide portion.
04

Analyze Chymotrypsin Result

Chymotrypsin treatment yields a tetrapeptide containing a C-term indole amino acid (Trp) and two dipeptides. This tells us Trp can't be in the tripeptide because it's too small. So, Trp is part of the N-term tetrapeptide.
05

Analyze Clostripain Result

Clostripain yielded a pentapeptide, a dipeptide, and free Phe. This tells us that the other Arg must be at the end of a pentapeptide. So the pentapeptide starts with Phe and ends with Arg.
06

Reconstruct Entire Sequence

Now piece together the information and order the peptides. The sequence starts with a tetrapeptide, split by Met, and ending with a tripeptide. Trp must be within the first four amino acids. Phe is in the fifth position, the pentapeptide ends with Arg, and the octapeptide ends with Lys. Noticing that Tyr and Gly haven't been placed yet, Tyr must be the only remaining position in the pentapeptide and Gly in the tripeptide. Therefore, the sequence is Trp-Arg-Gly-Lys-Met-Phe-Tyr-Arg.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Edman Degradation
Understanding the Edman Degradation process is essential when trying to determine the sequence of amino acids in a peptide. This method, developed by Pehr Edman, is used to sequentially remove one residue at a time from the amino (N-) terminus of a peptide chain. Through a chemical reaction, the N-terminal amino acid is converted to a phenylthiohydantoin (PTH) derivative, which can then be identified by chromatographic techniques.

Each cycle of Edman degradation provides the identity of the next amino acid, which allows us to sequentially build the amino acid sequence of the peptide. This is particularly useful for relatively short peptides and requires only a very small amount of the peptide to determine its sequence. However, it becomes less efficient for peptides longer than about 30 amino acids. Additionally, the information from Edman degradation often complements other peptide fragmentation methods to obtain a complete sequence.
Peptide Fragmentation
Peptide fragmentation is a cornerstone of protein sequencing. When an entire polypeptide sequence cannot be determined through direct methods, it is often necessary to break the peptide into smaller fragments. These fragments can be produced using various chemical and enzymatic treatments, each targeting specific amino acid residues.

For instance, in the given problem, Cyanogen bromide (CNBr) is used to cleave the peptide at methionine (Met) residues. Similarly, the enzymes trypsin and chymotrypsin specifically cleave at the C-terminal side of certain amino acids: trypsin targets arginine (Arg) and lysine (Lys), while chymotrypsin cleaves at tryptophan (Trp), tyrosine (Tyr), and phenylalanine (Phe). Knowing where these enzymes cut allows researchers to deduce the order of amino acids in a protein sequence.

These facts can help to locate different amino acids within a peptide sequence. Such enzymatic and chemical cleavage techniques are vital because they help to simplify the complex problem of amino acid sequencing into smaller, more manageable pieces, paving the way for a full reconstruction of the sequence.
Enzyme Specificity
Enzyme specificity is a fundamental concept in biochemistry, referring to the ability of an enzyme to choose its substrate from a pool of similar molecules. In the context of peptide sequencing, this specificity is invaluable as it dictates which bonds within a protein will be cut by an enzyme.

As demonstrated by the problem, trypsin and chymotrypsin have specific cleavage patterns. Trypsin cuts next to the C-terminal side of lysine and arginine residues, except when followed by proline. Chymotrypsin prefers to cleave next to the aromatic residues like tryptophan, tyrosine, and phenylalanine. Clostripain, another enzyme used in the exercise, behaves similarly to trypsin but is more restrictive and cleaves primarily at the C-terminal side of arginines.

Each enzyme's specificity can be exploited to create a 'map' of the protein's structure. By understanding which amino acids are released and which remain bonded after treatment with specific enzymes, a scientist can infer sequences and positions of amino acids, progressively piecing together the complete structure of the peptide.

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Most popular questions from this chapter

The human insulin receptor substrate- 1 (IRS-1) is designated protein \(\mathrm{P} 35568\) in the protein knowledge base on the ExPASy Web site (http://us.expasy.org/). Go to the PeptideMass tool on this Web site and use it to see the results of trypsin digestion of IRS-1. How many amino acids does IRS-1 have? What is the average molecular mass of IRS-1? What is the amino acid sequence of the tryptic peptide of IRS-1 that has a mass of \(1741.9629 ?\)

Phosphoproteins are formed when a phosphate group is esterified to an - OH group of a Ser, Thr, or Tyr side chain. At typical cellular \(\mathrm{pH}\) values, this phosphate group bears two negative charges \(-\mathrm{OPO}_{3}^{2-} .\) Compare this side-chain modification to the 20 side chains of the common amino acids found in proteins and comment on the novel properties that it introduces into side-chain possibilities.

A quantitative study of the interaction of a protein with its ligand yielded the following results: Ligand concentration \(1 \quad 2 \quad 3 \quad 4 \quad 5 \quad 6 \quad 9 \quad 12\) \((m M)\) \(\nu\) (moles of ligand \(\begin{array}{lllllll}0.28 & 0.45 & 0.56 & 0.60 & 0.71 & 0.75 & 0.79 & 0.83\end{array}\) bound per mole of protein Plot a graph of [L] versus \(\nu .\) Determine \(K_{\mathrm{D}},\) the dissociation constant for the interaction between the protein and its ligand, from the graph.

Describe the synthesis of the dipeptide Lys-Ala by Merrifield's solidphase chemical method of peptide synthesis. What pitfalls might be encountered if you attempted to add a leucine residue to Lys-Ala to make a tripeptide?

Amino acid analysis of an oligopeptide 7 residues long gave \(\begin{array}{lllll}\text { Asp } & \text { Leu } & \text { Lys } & \text { Met } & \text { Phe } & \text { Tyr }\end{array}\) The following facts were observed: a. Trypsin treatment had no apparent effect. b. The phenylthiohydantoin released by Edman degradation was c. Brief chymotrypsin treatment yielded several products, including a dipeptide and a tetrapeptide. The amino acid composition of the tetrapeptide was Leu, Lys, and Met. d. Cyanogen bromide treatment yielded a dipeptide, a tetrapeptide, and free Lys. What is the amino acid sequence of this heptapeptide?

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