Chapter 6: Problem 16
Consider a chemostat. You wish to know the number of cells in the reactor and the fraction of the cells that are viable (i.e., alive as determined by ability to divide). a. Write an equation for viable cell number \(\left(n_{v}\right)\). Assume that $$ \mu_{\text {met,rep. }}=\frac{\mu_{\mathrm{m}, \mathrm{rep}} S}{K_{\text {s,rep }}+S}-k_{d}^{\prime} $$ where \(\mu_{\text {net,rep }}=\) net specific replication rate, \(\mu_{m, r e p}=\) maximum specific replication rate, and \(K_{d}=\) death rate. \(K_{s, \text { rep }}\) is the saturation parameter. b. Derive an expression for the value of \(S\) at steady state. c. Write the number balance in the chemostat on dead cells \(\left(n_{d}\right)\). d. Derive an expression for the fraction of the total population which are dead cells.
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.