Chapter 1: Problem 111
Ionization energies usually increase on going from left to right across the periodic table. The ionization energy for oxygen, however, is lower than that of either nitrogen or fluorine. Explain this anomaly.
Short Answer
Expert verified
Oxygen's lower ionization energy compared to nitrogen and fluorine is due to increased electron-electron repulsion in its p orbital, where there is a paired electron.
Step by step solution
01
Understanding Ionization Energies
Ionization energy refers to the energy required to remove the most loosely bound electron from an isolated gaseous atom to form a cation. Generally, ionization energies increase across a period from left to right due to the increase in effective nuclear charge, which attracts the electrons more strongly and increases the energy required to remove an electron.
02
Considering Subshell Configurations
To understand the anomaly, consider the electronic configurations of nitrogen (N), oxygen (O), and fluorine (F). Nitrogen has the electronic configuration of 1s2 2s2 2p3, meaning it has half-filled p orbitals which are relatively stable. Oxygen, with the configuration 1s2 2s2 2p4, has one of the p orbitals with a paired electron, which leads to increased electron-electron repulsion.
03
Comparing Oxygen with Nitrogen and Fluorine
Oxygen's configuration makes it easier to remove an electron compared to nitrogen because of the repulsion caused by the paired electron in one of the p orbitals. Likewise, fluorine, with the configuration 1s2 2s2 2p5, is more stable than oxygen due to fewer electron-electron repulsions and a higher effective nuclear charge, thus it has a higher ionization energy than oxygen despite being to the right of oxygen on the periodic table.
04
Explaining the Anomaly
The anomaly in oxygen's ionization energy, being lower than that of nitrogen and fluorine, is therefore explained by its electron-electron repulsion in the partially filled p subshell, which makes removing an electron from oxygen less energy-intensive compared to the relatively stable half-filled p subshell of nitrogen or the nearly filled p subshell of fluorine.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Periodic Table Trends
When learning about the periodic table trends, it's essential to note how properties like ionization energy change as we move across the table. Typically, ionization energy increases from left to right across a period. This is because the atoms become smaller, and the valence electrons are closer to the nucleus, experiencing a stronger pull.
However, there are exceptions to this trend, which are often tied to the unique electronic configurations of elements. The unexpected case of oxygen having a lower ionization energy than nitrogen, despite being further to the right, is a perfect example. By understanding these nuances, you gain insight into the fascinating behavior of elements and the forces at play within atoms.
However, there are exceptions to this trend, which are often tied to the unique electronic configurations of elements. The unexpected case of oxygen having a lower ionization energy than nitrogen, despite being further to the right, is a perfect example. By understanding these nuances, you gain insight into the fascinating behavior of elements and the forces at play within atoms.
Electron Configuration
To comprehend the exception in ionization energy trends, grasp the basics of electron configuration. This configuration details how electrons are distributed within an atom. Electrons fill orbitals in a way that minimizes repulsion and maximizes stability.
Nitrogen, for instance, has a half-filled p subshell, which is symmetrical and thus energetically favorable. Oxygen, on the other hand, piles an extra electron onto one of these p orbitals, disrupting the balance and creating a repulsive force that makes it easier to remove an electron. This interplay between electron arrangement and stability is central to explaining various atomic properties.
Nitrogen, for instance, has a half-filled p subshell, which is symmetrical and thus energetically favorable. Oxygen, on the other hand, piles an extra electron onto one of these p orbitals, disrupting the balance and creating a repulsive force that makes it easier to remove an electron. This interplay between electron arrangement and stability is central to explaining various atomic properties.
Effective Nuclear Charge
The effective nuclear charge (Zeff) is the net positive charge experienced by an electron in a multi-electron atom. The concept is vital as it helps explain why electrons are held more tightly—and thus require more energy to remove—as we move from left to right on the periodic table.
As the number of protons in the nucleus increases with each element, the effective nuclear charge does as well, assuming electron shielding doesn't significantly counteract it. This increasing Zeff contributes to the general rise in ionization energy across a period but must be considered alongside electron configuration to understand anomalies like the one observed with oxygen's ionization energy.
As the number of protons in the nucleus increases with each element, the effective nuclear charge does as well, assuming electron shielding doesn't significantly counteract it. This increasing Zeff contributes to the general rise in ionization energy across a period but must be considered alongside electron configuration to understand anomalies like the one observed with oxygen's ionization energy.
Electron-Electron Repulsion
The principle of electron-electron repulsion states that electrons, which have like-charges, repel each other. This repulsion can impact an atom's ionization energy. In a simplified model, when an atom has paired electrons in an orbital, the repulsion between those electrons can make it easier to remove one, resulting in a lower ionization energy.
Understanding this concept illuminates why oxygen, with its 2p4 configuration, has a lower ionization energy than might be expected. The paired electrons in one of the p orbitals push against each other, making it easier for the atom to lose an electron compared to an atom like nitrogen, where such repulsions are minimized due to its half-filled orbitals.
Understanding this concept illuminates why oxygen, with its 2p4 configuration, has a lower ionization energy than might be expected. The paired electrons in one of the p orbitals push against each other, making it easier for the atom to lose an electron compared to an atom like nitrogen, where such repulsions are minimized due to its half-filled orbitals.