Of the following sets of four quantum numbers \(\left\\{n, l, m_{l}, m_{s}\right\\}\), identify the ones that are forbidden for an electron in an atom and explain why they are invalid: (a) \(\left\\{4,2,-1,+\frac{1}{2}\right\\}\); (b) \(\left\\{5,0,-1,+\frac{1}{2}\right\\}\); (c) \(\left\\{4,4,-1,+\frac{1}{2}\right\\}\).

Short Answer

Expert verified
The set (a) is allowed because all quantum numbers are within the allowed range. The sets (b) and (c) are forbidden; set (b) has an invalid magnetic quantum number for the given , and set (c) has an invalid azimuthal quantum number for the given .

Step by step solution

01

Understand the quantum numbers

The principal quantum number () can be any positive integer, and it determines the energy level of an electron. The azimuthal (or angular momentum) quantum number () can be any integer between 0 and - 1. The magnetic quantum number () can have values from to . The spin quantum number () can be either +1/2 or -1/2.
02

Check the validity of set (a)

Check if the values of set (a) are valid based on the rules. The value for is a positive integer and determines the possible values of , which are 0, 1, 2, or 3 for . Since the given value is 2, and the possible values for that can be -2, -1, 0, 1, or 2. Since is within this range, it is valid. The spin quantum number is valid as it's one of the allowed values. Therefore, the set is permissible.
03

Check the validity of set (b)

In set (b) , for , the only valid value is 0, since must be between 0 and - 1. However, the value which should range from - to includes 0 only since is 0. The provided value of -1 is not within this range and is therefore invalid. The set is forbidden.
04

Check the validity of set (c)

In set (c) , the given value of exceeds the range set by the value of (which would allow from 0 to 3). Therefore, the set does not comply with the quantum number rules and is not a permitted value for . Thus, the set is forbidden.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Quantum Number
The principal quantum number, denoted as n, plays a vital role in the quantum mechanics of atoms. It is a positive integer (1,2,3,...) and is the first of the four quantum numbers that define the state that an electron can be in. Think of it as the main address for electrons in an atom, determining the energy level or shell in which an electron resides. The higher the value of n, the further the electron is from the nucleus, and it also represents higher energy states.

For every principal quantum number, there are n possible values for the azimuthal quantum number, which relates to the shape of the electron's orbit, ranging from 0 to n - 1. This concept is a fundamental one for students to grasp as it lays the groundwork for understanding the more complex quantum numbers and is critical for proper electron configuration.
Azimuthal Quantum Number
Closely following the principal quantum number is the azimuthal quantum number, l, which also goes by the name angular momentum quantum number. The possible values of l are integers ranging from 0 up to n - 1, where n is the principal quantum number.

This quantum number gives the shape of the orbital, often associated with subshells designated as s (l=0), p (l=1), d (l=2), and f (l=3). Understanding l is crucial because it helps in pinpointing the exact subshell in which an electron is located within an energy level. Incorrect values of l that do not align with the principal quantum number are not permissible, which explains why certain sets of quantum numbers can be invalid.
Magnetic Quantum Number
Within each subshell denoted by the azimuthal quantum number, there are multiple orientations in space that an orbital can have, and these orientations are specified by the magnetic quantum number, ml. It is dependent on the value of l and can range from -l to +l, including zero.

This means for a p-orbital where l=1, the ml can be -1, 0, or +1, corresponding to the three different p-orbitals oriented in space. The wrong assignment of ml outside this range is a common mistake for students, leading to invalid quantum numbers. For instance, if l=0 for an s-orbital, there can only be a single value for ml, which is 0.
Spin Quantum Number
The final piece of the quantum number puzzle is the spin quantum number, ms, which represents the intrinsic angular momentum of an electron. Unlike the other quantum numbers, ms has only two possible values: +1/2 or -1/2. These values signify the two possible spin orientations of the electron: 'spin-up' or 'spin-down'.

An important note for students to remember is that no two electrons in the same atom can have the exact same set of four quantum numbers due to Pauli's Exclusion Principle. Hence, the spin quantum number allows two electrons (with opposite spins) to share the same orbital, as they will have different ms values.
Electron Configuration
After understanding the quantum numbers, the next step is to talk about electron configuration. This is the arrangement of electrons in an atom's orbitals, represented by notations that indicate the principal and azimuthal quantum numbers, followed by the number of electrons in those orbitals.

For example, the electron configuration notation '2s2' indicates two electrons in the s subshell of the second energy level. This notation provides a map of how electrons are distributed in an atom and are dictated by the rules established through the quantum numbers. Students must remember that electrons fill the lowest energy orbitals first (Aufbau principle), can only double up in orbitals if they have opposite spins (Pauli), and prefer to fill orbitals singly before pairing up (Hund's rule). The grasp on these concepts ensures a full understanding of how atoms are constructed in the microscopic world.

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Most popular questions from this chapter

Francium is thought to be the most reactive of the alkali metals. Because it is radioactive and available in only very small amounts it is difficult to study. However, we can predict its properties based on its location in Group 1 of the periodic table. Estimate the following properties of francium: (a) atomic radius; (b) ionic radius of the \(+1\) cation; (c) ionization energy.

At what distance from the nucleus is the electron most likely to be found if it occupies (a) a 3d-orbital or (b) a 4s-orbital in a hydrogen atom?

Which elements are predicted to have the following groundstate electron configurations: (a) \([\mathrm{Kr}] 4 \mathrm{~d}^{10} 5 \mathrm{~s}^{2} 5 \mathrm{p}^{4} ;\) (b) \([\mathrm{Ar}] 3 \mathrm{~d}^{3} 4 \mathrm{~s}^{2}\); (c) \([\mathrm{He}] 2 \mathrm{~s}^{2} 2 \mathrm{p}^{2}\); (d) \([\mathrm{Rn}] 7 \mathrm{~s}^{2} 6 \mathrm{~d}^{2}\) ?

Ionization energies usually increase on going from left to right across the periodic table. The ionization energy for oxygen, however, is lower than that of either nitrogen or fluorine. Explain this anomaly.

Atomic orbitals may be combined to form molecular orbitals. In such orbitals, there is a nonzero probability of finding an electron on any of the atoms that contribute to that molecular orbital. Consider an electron that is confined in a molecular orbital that extends over two adjacent carbon atoms. The electron can move freely between the two atoms. The C-C distance is \(139 \mathrm{pm}\). (a) Using the one-dimensional particle-in-the-box model, calculate the energy required to promote an electron from the \(n=1\) to the \(n=2\) level, assuming that the length of the box is determined by the distance between two carbon atoms. (b) To what wavelength of radiation does this correspond? (c) Repeat the calculation for a linear chain of 1000 carbon atoms. (d) What can you conclude about the energy separation between energy levels as the size of the atom chain increases?

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