Predict the number of valence electrons present in each of the following atoms (include the outermost d-electrons): (a) Bi; (b) Ba; (c) \(\mathrm{Mn}\); (d) Zn.

Short Answer

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(a) Bi: 15 valence electrons (5s^2 5p^3 5d^10), (b) Ba: 2 valence electrons (6s^2), (c) Mn: 7 valence electrons (4s^2 3d^5), (d) Zn: 12 valence electrons (4s^2 3d^10)

Step by step solution

01

Understanding Valence Electrons

Valence electrons are the electrons in the outermost shell (energy level) of an atom. They are important because they are the electrons involved in bonding. The number of valence electrons can be predicted based on an element's group number in the periodic table for representative elements, while for transition elements, the outermost s- and d-electrons from the last two shells can be counted as valence electrons.
02

Determining Valence Electrons for Bismuth (Bi)

Bismuth (Bi) is in group 15 and period 6 of the periodic table. It has 5 valence electrons (3 from the p-orbital and 2 from the s-orbital). Note that the d-electrons from the (n-1)d orbital (where n is the period number) are not considered valence for main group elements, but are included for the transition metals and post-transition metals like Bi. Bismuth is considered to have the following valence electrons in its configuration (6s^2 6p^3 5d^10).
03

Determining Valence Electrons for Barium (Ba)

Barium (Ba) is in group 2 and period 6 of the periodic table. The outermost shell has 2 electrons from the s-orbital. Barium has 2 valence electrons which can be shown with the configuration (6s^2).
04

Determining Valence Electrons for Manganese (Mn)

Manganese (Mn) is a transition metal in group 7 and period 4. The valence electrons include the 2 electrons in the 4s subshell and the 5 electrons in the 3d subshell, for a total of 7 valence electrons. Its valence electrons can be represented by the configuration (4s^2 3d^5).
05

Determining Valence Electrons for Zinc (Zn)

Zinc (Zn) is a transition metal in group 12 and period 4. It has a complete d subshell in its penultimate shell and 2 electrons in the outermost s subshell. Thus, it has 2 valence electrons from the 4s subshell and 10 d-electrons from the 3d subshell, totaling 12 valence electrons, represented by the configuration (4s^2 3d^10).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metals
Transition metals are elements that occupy groups 3 to 12 on the periodic table. These metals are characterized by their unique ability to use the electrons in their d-orbital for bonding, which is not commonly observed in other elements. When calculating the number of valence electrons for transition metals, both the electrons in the outermost s subshell and the d-electrons from the penultimate shell are considered. This inclusion of d-electrons gives transition metals a variety of oxidation states and the capacity for complex chemical bonding.

For example, manganese (Mn), a transition metal, has a total of 7 valence electrons — 2 from the 4s subshell and 5 from the 3d subshell. The d-electrons play a vital role in forming metallic bonds and allow transition metals to act as catalysts in many chemical reactions due to their variable oxidation states.
Periodic Table
The periodic table is a chart that organizes all known chemical elements based on their atomic number, electron configuration, and recurring chemical properties. Elements are listed in order of increasing atomic number in rows called periods. Columns, known as groups or families, contain elements with similar chemical behaviors due to their similar valence electron configurations.

Understanding the periodic table is crucial when predicting valence electrons. For main group elements, the group number can indicate the number of valence electrons. However, this rule does not always apply to transition metals. The periodic table also reveals trends in electronegativity, atomic size, and several other important chemical properties that are essential for understanding chemical bonding and reactions.
Electron Configuration
Electron configuration refers to the distribution of electrons in an atom's orbitals. Electrons fill subshells (s, p, d, f) in a manner that minimizes the energy of the atom. The way electrons are distributed among the orbitals of an atom explains the atom's chemical properties, including the types of bonds it can form and its reactivity.

For example, the electron configuration of zinc (Zn) is written as (4s2 3d10). The '4s' and '3d' describe quantum numbers that indicate the shell and subshell. The superscript shows that there are two electrons in the 4s subshell and ten electrons in the 3d subshell. When discussing valence electrons, these are the exterior and partially filled subshells that get involved in chemical bonding.
Chemical Bonding
Chemical bonding is the force that holds atoms together in compounds. This bonding allows for the creation of stable molecules from atoms. The type and number of bonds that an atom can form largely depend on its valence electrons. The main types of chemical bonds include ionic, covalent, and metallic bonds.

Covalent bonding occurs when atoms share valence electrons, ionic bonding arises from the electrical attraction between positively and negatively charged ions, and metallic bonding is characterized by a 'sea' of shared electrons amongst metal cations. The valence electrons in transition metals, including both their s and d electrons, allow these elements to form a variety of bond types, leading to the vast array of compounds and materials we see around us.

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Most popular questions from this chapter

Which ion of each of the following pairs has the larger radius: (a) \(\mathrm{Ca}^{2+}, \mathrm{Ba}^{2+} ;\) (b) \(\mathrm{As}^{3-}, \mathrm{Se}^{2-} ;\) (c) \(\mathrm{Sn}^{2+}, \mathrm{Sn}^{4+}\) ?

Place the following ions in order of increasing ionic radius: \(\mathrm{S}^{2-}, \mathrm{Cl}^{-}, \mathrm{P}^{3-}\).

Atomic orbitals may be combined to form molecular orbitals. In such orbitals, there is a nonzero probability of finding an electron on any of the atoms that contribute to that molecular orbital. Consider an electron that is confined in a molecular orbital that extends over two adjacent carbon atoms. The electron can move freely between the two atoms. The C-C distance is \(139 \mathrm{pm}\). (a) Using the one-dimensional particle-in-the-box model, calculate the energy required to promote an electron from the \(n=1\) to the \(n=2\) level, assuming that the length of the box is determined by the distance between two carbon atoms. (b) To what wavelength of radiation does this correspond? (c) Repeat the calculation for a linear chain of 1000 carbon atoms. (d) What can you conclude about the energy separation between energy levels as the size of the atom chain increases?

Which member of each pair has the smaller first ionization energy: (a) \(\mathrm{Ca}\) or \(\mathrm{Mg}\); (b) \(\mathrm{Mg}\) or \(\mathrm{Na}\); (c) \(\mathrm{Al}\) or \(\mathrm{Na}\) ?

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