A technical handbook contains tables of thermodynamic quantities for common reactions. If you want to know whether a certain cell reaction has a positive standard potential, which of the following properties would give you that information directly (on inspection)? Which would not? Explain your answer. (a) \(\Delta G^{\circ}\); (b) \(\Delta H^{\circ}\); (c) \(\Delta S^{\circ}\); (d) \(\Delta U^{\circ}\); (e) \(K\).

Short Answer

Expert verified
To directly know if a cell reaction has a positive standard potential, check delta G^: a negative value implies a positive standard potential. Properties such as delta H^, delta S^, delta U^, and K do not provide this information directly; they require additional calculations to deduce the standard potential.

Step by step solution

01

Understanding the Relationship Between Standard Potential and Gibbs Free Energy

The Gibbs free energy change (G^) for a reaction at standard conditions is directly related to the electrical work possible by a cell reaction and thus, to the standard potential (E^). The relationship is given by the equation G^ = -nFE^, where F is the Faraday constant and n is the number of moles of electrons transferred. A negative G^ indicates that the standard potential is positive, meaning the reaction is spontaneous under standard conditions.
02

Recognizing Properties Not Directly Related to Standard Potential

Standard enthalpy change (H^), standard entropy change (S^), and the change in internal energy (U^) are state functions that relate to thermodynamic properties of a system. However, they do not directly give the standard potential of a cell reaction on inspection. While H^ and S^ can be used to calculate G^, and therefore potentially E^ through further calculation, they do not give us the standard potential straightforwardly. Similarly, U^ does not provide direct information about the standard potential.
03

Identifying Equilibrium Constant as an Indirect Indicator

The equilibrium constant (K) is related to the Gibbs free energy change by the equation G^ = -RTlnK, where R is the universal gas constant and T is the temperature in Kelvin. A large equilibrium constant (K > 1) implies a negative G^, and thus a positive standard potential. However, the value of K is an indirect indicator, as the actual G^ value would still need to be calculated to determine E^ directly.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy (\text{Δ}G^{\text{o}})
Gibbs Free Energy, often represented as \text{\(\Delta G^\circ\)}, is a thermodynamic quantity that is extremely useful in predicting the spontaneity of chemical reactions. It effectively determines whether a reaction is capable of occurring without the input of additional energy. The 'standard' refers to standard conditions, which is typically 1 bar of pressure for gases and 1 molar concentrations for solutions.

\text{\(\Delta G^\circ\)} is related to the standard cell potential (\(E^\circ\)) through the equation \(\Delta G^\circ = -nFE^\circ\), where \(n\) is the number of moles of electrons transferred in the reaction and \(F\) is the Faraday constant, approximately \(96,485\) coulombs per mole of electrons. A negative value of \(\Delta G^\circ\) suggests that the reaction can occur spontaneously under standard conditions, leading to a positive standard potential. This useful interrelation allows you to directly determine the standard potential of an electrochemical reaction by knowing its Gibbs Free Energy.
Equilibrium Constant (K)
The equilibrium constant, represented as \(K\), is a dimensionless value that provides insight into the position of equilibrium for a reversible chemical reaction. The larger the value of \(K\), the more the reaction favors the formation of products at equilibrium. In the context of electrochemistry, \(K\) and the Gibbs free energy change (\text{\(\Delta G^\circ\)}) are related by the equation \(\Delta G^\circ = -RT\ln K\), where \(R\) is the universal gas constant and \(T\) is the temperature in Kelvin.

Although knowing \(K\) provides an indirect sense of the spontaneity of a reaction (with higher values suggesting a negative \(\Delta G^\circ\) and thus a positive standard potential), it doesn't provide a direct indication of the standard potential. It must be used in conjunction with the equation above to calculate \(\Delta G^\circ\) first, before you can infer the standard potential.
Thermodynamic Properties
Thermodynamic properties such as standard enthalpy (\text{\(\Delta H^\circ\)}), standard entropy (\text{\(\Delta S^\circ\)}), and change in internal energy (\text{\(\Delta U^\circ\)}) are state functions describing a system's energy changes during a process. Enthalpy is the heat exchanged at constant pressure, entropy measures disorder or randomness, and internal energy is the total energy contained within a system. Although these properties relate to the energetics and dynamics of chemical reactions, they do not directly reveal a cell's standard potential.

For instance, a reaction with a negative \(\Delta H^\circ\) and positive \(\Delta S^\circ\) may suggest that it is spontaneous, thus potentially having a positive standard potential, but these values alone do not offer definitive insight without calculating \(\Delta G^\circ\). Similarly, \(\Delta U^\circ\) reflects a different aspect of energy change and is not directly tied to electrochemical cell potential.
Electrochemistry
Electrochemistry is the branch of chemistry that deals with the relationship between electricity and chemical reactions. In the context of cells and batteries, it focuses on the conversion between chemical energy and electrical energy. The standard cell potential (\(E^\circ\)) is a key concept in electrochemistry, as it indicates whether an electrochemical cell will spontaneously generate an electric current under standard conditions.

The standard cell potential can be found using the Gibbs free energy equation or through experimental measurement. Knowing the standard cell potential allows us to predict the flow of electrons in the cell and the cell's ability to do work, turning chemical reactions into useful electrical power. Understanding the fundamental principles of electrochemistry is crucial to mastering concepts such as battery design, corrosion, and the development of new energy storage technologies.

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Most popular questions from this chapter

The following redox reaction is used to prepare orthotelluric acid: $$ \mathrm{Te}(\mathrm{s})+\mathrm{ClO}_{3}^{-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \longrightarrow \mathrm{H}_{6} \mathrm{TeO}_{6}(\mathrm{aq})+\mathrm{Cl}_{2}(\mathrm{~g}) $$ (a) Identify the elements undergoing changes in oxidation state and indicate the initial and final oxidation numbers for these elements. (b) Write and balance the oxidation half-reaction. (c) Write and balance the reduction half-reaction. (d) Combine the half-reactions to produce a balanced redox equation.

Calculate the standard reaction Gibbs free energy for the following cell reactions: (a) \(2 \mathrm{Ce}^{++}(\mathrm{aq})+3 \mathrm{I}^{-}(\mathrm{aq}) \longrightarrow 2 \mathrm{Ce}^{3+}(\mathrm{aq})+\mathrm{I}_{3}^{-}(\mathrm{aq})\) \(E_{\mathrm{cell}^{\circ}}=+1.08 \mathrm{~V}\) (b) \(6 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{Cr}^{3+}(\mathrm{aq})+7 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \longrightarrow 6 \mathrm{Fe}^{2+}(\mathrm{aq})+\) \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq})+14 \mathrm{H}^{+}(\mathrm{aq}), E_{\text {cell }}{ }^{\circ}=-1.29 \mathrm{~V}\)

(a) Suggest two metals that could be used for the cathodic protection of a titanium pipeline. (b) What factors other than relative positions in the electrochemical series need to be considered in practice? (c) Often copper piping is connected to iron pipes in household plumbing systems. What is a possible effect of the copper on the iron pipes?

Balance each of the following skeletal equations by using oxidation and reduction half-reactions. All the reactions take place in acidic solution. Identify the oxidizing agent and reducing agent in cach reaction. (a) Reaction of the selenite ion with chlorate ion: $$ \mathrm{SeO}_{3}{ }^{2-}(\mathrm{s})+\mathrm{ClO}_{3}{ }^{-}(\mathrm{aq}) \longrightarrow \mathrm{SeO}_{4}{ }^{2-}(\mathrm{aq})+\mathrm{Cl}_{2}(\mathrm{~g}) $$ (b) Formation of propanone (acetone), which is used in nail polish remover, from isopropanol (rubbing alcohol) by the action of dichromate ion: $$ \mathrm{C}_{3} \mathrm{H}_{7} \mathrm{OH}(\mathrm{aq})+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(\mathrm{aq}) \rightarrow \mathrm{Cr}^{3+}(\mathrm{aq})+\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}(\mathrm{aq}) $$ (c) Reaction of gold with selenic acid: \(\mathrm{Au}(\mathrm{s})+\mathrm{SeO}_{4}{ }^{2-}(\mathrm{aq}) \longrightarrow \mathrm{Au}^{3+}(\mathrm{aq})+\mathrm{SeO}_{3}{ }^{2-}\) (aq) (d) Preparation of stibnine from antimonic acid: \(\mathrm{H}_{2} \mathrm{SbO}_{3}{ }^{2-}(\mathrm{s})+\mathrm{Zn}(\mathrm{s}) \longrightarrow \mathrm{SbH}_{3}(\mathrm{aq})+\mathrm{Zn}^{2+}(\mathrm{aq})\)

Calculate \(E\) for each of the following concentration cells: (a) \(\mathrm{Cu}(\mathrm{s})\left|\mathrm{Cu}^{2+}\left(\mathrm{aq}, 0.0010 \mathrm{~mol} \cdot \mathrm{L}^{-1}\right)\right|\left|\mathrm{Cu}^{2+}\left(\mathrm{aq}, 0.010 \mathrm{~mol} \cdot \mathrm{L}^{-1}\right)\right| \mathrm{Cu}(\mathrm{s})\) (b) \(\mathrm{Pt}(\mathrm{s}) \mid \mathrm{H}_{2}(\mathrm{~g}, 1\) bar \() \mid \mathrm{H}^{+}(\mathrm{aq}, \mathrm{pH}=4.0\rangle \| \mathrm{H}^{+}(\mathrm{aq}, \mathrm{pH}=3.0)\left[\mathrm{H}_{2}\right.\) (g, 1 bar \() \mid \operatorname{Pt}(\mathrm{s})\)

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