When the rate of the reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow\) \(2 \mathrm{NO}_{2}(\mathrm{~g})\) was studied, the rate was found to double when the \(\mathrm{O}_{2}\) concentration alone was doubled but to quadruple when the NO concentration alone was doubled. Which of the following mechanisms accounts for these observations? Explain your reasoning. (a) Step \(1 \mathrm{NO}+\mathrm{O}_{2} \longrightarrow \mathrm{NO}_{3}\) and its reverse (both fast, equilibrium) Step \(2 \mathrm{NO}+\mathrm{NO}_{3} \rightarrow \mathrm{NO}_{2}+\mathrm{NO}_{2}\) (slow) (b) Step \(1 \mathrm{NO}+\mathrm{NO} \rightarrow \mathrm{N}_{2} \mathrm{O}_{2}\) (slow) Step \(2 \mathrm{O}_{2}+\mathrm{N}_{2} \mathrm{O}_{2} \rightarrow \mathrm{N}_{2} \mathrm{O}_{4}\) (fast) Step \(3 \mathrm{~N}_{2} \mathrm{O}_{4} \rightarrow \mathrm{NO}_{2}+\mathrm{NO}_{2}\) (fast)

Short Answer

Expert verified
Mechanism (b) is consistent with the experimental observations as it has a slow step with second-order dependence on NO and first-order dependence on O2.

Step by step solution

01

- Understanding the Rate Dependence

Examine how the rate of the reaction changes with concentration. The rate doubles with a doubling of O2, indicating first-order dependence on O2. It quadruples with NO doubling, suggesting a second-order dependence on NO.
02

- Analyzing Mechanism (a)

Consider if mechanism (a) is consistent with the observed rate dependencies. Since the first step involves NO and O2 and is at equilibrium, the rate-determining step (RDS) would involve NO3 reacting with NO. The overall rate would only depend on the concentration of NO3, and NO in the RDS, not directly on O2. This does not fit the rate dependence on O2.
03

- Analyzing Mechanism (b)

Consider if mechanism (b) is consistent with the observed rate dependencies. The slow step involves two NO molecules, which would imply a second-order dependence on NO. The subsequent fast steps involve O2 reacting with N2O2. This mechanism indicates that the rate could be directly proportional to O2 (if N2O2 is in excess), which is consistent with first-order dependence on O2 concentration.
04

- Conclusion

Conclude that mechanism (b) correctly accounts for the observed rate changes because it includes a slow step with second-order dependence on NO and a step with first-order dependence on O2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Rate Dependence
Understanding how a reaction rate is influenced by the concentration of reactants is fundamental in the study of chemical kinetics. A reaction's rate often depends on the concentration of its reactants in a predictable way. In the provided example, the rate of the formation of \( \mathrm{NO}_{2} \) gas doubles when the concentration of \( \mathrm{O}_{2} \) is doubled, suggesting a direct, first-order relationship for \( \mathrm{O}_{2} \) in the reaction. Conversely, when the concentration of \( \mathrm{NO} \) gas is doubled, the rate of the reaction quadruples, indicating a second-order relationship for \( \mathrm{NO} \) in the reaction.

This information is particularly valuable for predicting how changes in concentrations will affect the speed at which the reaction proceeds. It's important to note that the overall reaction rate can be determined by the rates of the individual steps in a multi-step reaction, which leads us to consider the concept of the rate-determining step.
Rate-Determining Step (RDS)
In a multi-step chemical reaction, one step typically limits the overall rate of the reaction. This is known as the rate-determining step (RDS). The RDS has a higher activation energy than the other steps, and therefore, it proceeds more slowly. As a result, the overall reaction cannot proceed faster than this slowest step.

In the exercise at hand, the rate dependence on \( \mathrm{NO} \) and \( \mathrm{O}_{2} \) suggests that the mechanism we choose must include a slow step that is consistent with the observed order of reaction. Only the mechanism that accurately reflects the dependence of the reaction rate on the concentrations of the reactants can be correct. Hence, the RDS for the correct mechanism should show a second-order dependence on \( \mathrm{NO} \) and a first-order dependence on \( \mathrm{O}_{2} \) to match the experimental observations.
Reaction Order
Reaction order is a term used to express how the rate of a chemical reaction depends on the concentration of one or more reactants. It is determined by summing the powers of the concentration terms in the rate law of the reaction. For example, a reaction that is first-order with respect to \( \mathrm{NO} \) would imply that if the concentration of \( \mathrm{NO} \) is doubled, the rate of the reaction would double as well.

In the provided exercise, we observed that the reaction is of the first-order in \( \mathrm{O}_{2} \) and second-order in \( \mathrm{NO} \) because the rate of reaction changes in direct proportion to the concentration changes of these reactants. The overall reaction order is the sum of the individual orders with respect to each reactant involved in the rate-determining step.
Chemical Kinetics
Chemical kinetics is the branch of chemistry that concerns the rates of chemical reactions and the mechanisms by which they occur. By studying the factors that affect reaction rates, such as reactant concentrations, temperature, and catalysts, chemists can understand the sequence of steps, or the reaction mechanism, that leads from reactants to products.

Understanding kinetics is crucial in a number of practical settings, including the development of new reactions in industrial processes, understanding metabolic pathways in biochemistry, and even predicting how quickly a medication will be metabolized in the body. The principles of kinetics allow scientists and engineers to design and optimize reactions for a wide variety of applications.
Equilibrium Reactions
Equilibrium reactions are chemical reactions that proceed in both the forward and reverse directions. At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, resulting in no net change in the concentration of reactants and products over time. Unlike reactions that go to completion, equilibrium reactions are characterized by constant, stable concentrations of all the reactants and products involved.

Understanding equilibrium is important when examining reaction mechanisms, as some mechanisms involve fast, reversible steps that establish an equilibrium before the rate-determining step. In the exercise, mechanism (a) proposes such an equilibrium in the first step. When analyzing such mechanisms, the concentrations of intermediates at equilibrium can significantly influence the overall reaction rate, as they may be involved in the slowest step of the reaction.

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Most popular questions from this chapter

Write the overall reaction for the mechanism proposed below and identify any reaction intermediates. $$ \begin{aligned} &\text { Step } 1 \mathrm{AC}+\mathrm{B} \longrightarrow \mathrm{AB}+\mathrm{C} \\ &\text { Step } 2 \mathrm{AC}+\mathrm{AB} \longrightarrow \mathrm{A}_{2} \mathrm{~B}+\mathrm{C} \end{aligned} $$

A reaction was believed to occur by the following mechanism. Step \(1 \mathrm{~A}_{2} \longrightarrow \mathrm{A}+\mathrm{A}\) Step \(2 \mathrm{~A}+\mathrm{A}+\mathrm{B} \longrightarrow \mathrm{A}_{2} \mathrm{~B}\) Step \(3 \mathrm{~A}_{2} \mathrm{~B}+\mathrm{C} \longrightarrow \mathrm{A}_{2}+\mathrm{BC}\) (a) Write the overall reaction. (b) Write the rate law for each step and indicate its molecularity. (c) What are the reaction intermediates? (d) A catalyst is a substance that accelerates the rate of a reaction and is regenerated in the process. What is the catalyst in the reaction?

Manganate ions, \(\mathrm{MnO}_{4}^{2-}\), react at \(2.0 \mathrm{~mol} \cdot \mathrm{L}^{-1} \cdot \mathrm{min}^{-1}\) in acidic solution to form permanganate ions and manganese(IV) oxide: \(3 \mathrm{MnO}_{4}{ }^{2-}(\mathrm{aq})+4 \mathrm{H}^{+}(\mathrm{aq}) \rightarrow 2 \mathrm{MnO}_{4}{ }^{-}(\mathrm{aq})+\mathrm{MnO}_{2}(\mathrm{~s})+\) \(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) What is the rate of formation of permanganate ions? (b) What is the rate of reaction of \(\mathrm{H}^{+}(\mathrm{aq})\) ? (c) What is the unique rate of the reaction?

The following mechanism has been proposed for the reaction between nitric oxide and bromine: Step \(1 \mathrm{NO}+\mathrm{Br}_{2} \longrightarrow \mathrm{NOBr}_{2}\) (slow) Step \(2 \mathrm{NOBr}_{2}+\mathrm{NO} \longrightarrow \mathrm{NOBr}+\mathrm{NOBr}\) (fast) Write the rate law for the formation of NOBr implied by this mechanism.

An organic compound A can decompose by either of two kinetically controlled pathways to form products B or C (see Exercis 14.79). The activation energy for the formation of \(B\) is greater than that for the formation of \(\mathrm{C}\). Will the ratio \([\mathrm{B}] /[\mathrm{C}]\) increase or decrease as the temperature is increased? Explain your answer.

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