Determine whether each of the following statements is true or false. If a statement is false, explain why. (a) The equilibrium constant for a reaction equals the rate constant for the forward reaction divided by the rate constant for the reverse reaction. (b) In a reaction that is a series of equilibrium steps, the overall equilibrium constant is equal to the product of all the forward rate constants divided by the product of all the reverse rate constants. (c) Increasing the concentration of a product increases the rate of the reverse reaction, and so the rate of the forward reaction must then increase, too.

Short Answer

Expert verified
Statement (a) is true, as the equilibrium constant is the ratio of rate constants for the forward and reverse reactions. Statement (b) is false because the overall equilibrium constant is not directly the product of forward rate constants divided by product of reverse rate constants but rather the ratio of equilibrium constants for each step. Statement (c) is false, as an increase in product concentration increases the reverse reaction rate but does not obligate an increase in the forward reaction rate.

Step by step solution

01

Evaluating Statement (a)

Determine if the equilibrium constant for a reaction is indeed the rate constant for the forward reaction divided by the rate constant for the reverse reaction. The equilibrium constant (\( K_{eq} \) for a reaction is defined as the ratio of the concentration of the products raised to their stoichiometric coefficients to the concentration of the reactants raised to their stoichiometric coefficients at equilibrium. The statement correctly reflects the relationship between the equilibrium constant and the rate constants of the forward and reverse reactions.
02

Evaluating Statement (b)

Assess if the overall equilibrium constant is the product of all the forward rate constants divided by the product of all the reverse rate constants in a reaction that is a series of equilibrium steps. The overall equilibrium constant for such a reaction is indeed the product of the equilibrium constants for each step, which reflects the statement made. However, it is not directly related to the rates of the forward and reverse reactions but rather the ratio of product to reactant concentrations at equilibrium for each step.
03

Evaluating Statement (c)

Analyze if increasing the concentration of a product increases the rate of the reverse reaction, and therefore, the rate of the forward reaction must increase as well. The increase in the concentration of a product will indeed favor the reverse reaction due to Le Chatelier's principle, but it does not necessarily mean that the rate of the forward reaction will increase. The forward reaction rate depends on the reactant concentrations, not the product concentrations.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Equilibrium Constant and Rate Constants
Understanding the relationship between the equilibrium constant and the rate constants of a chemical reaction is pivotal to mastering chemical equilibrium. The equilibrium constant, represented as \( K_{eq} \), is a reflection of the ratio of the concentrations of the products to the reactants, each raised to the power of their respective stoichiometric coefficients when the system is at equilibrium.

The rate constants, on the other hand, define the speed at which the reaction moves towards equilibrium. The rate constant for the forward reaction, \( k_f \), and the rate constant for the reverse reaction, \( k_r \), are unique to each reaction and dictate how quickly reactants are converted into products and vice versa.

It is a common misconception to directly equate the equilibrium constant with the rate of the forward reaction divided by the rate of the reverse reaction. While the equilibrium constant does encompass the relation between the forward and reverse reactions at equilibrium, it considers the concentration of the reactants and products but does not necessarily dictate the speeds at which these reactions take place.
Le Chatelier's Principle
Le Chatelier's principle is a fundamental concept in chemical equilibrium that predicts how a system at equilibrium responds to disturbance. According to this principle, if an external change is applied to a system in equilibrium, the system adjusts to counteract the change and restore a new equilibrium.

For instance, an increase in the concentration of a product of a reaction will cause the equilibrium to shift in the direction that tends to reduce the concentration of that product, often meaning an increased rate of the reverse reaction. Conversely, reducing the concentration of a reactant will favor the forward reaction to produce more product.

However, the principle does not necessarily imply that the rate of the forward reaction will increase when the rate of the reverse reaction increases. Rates are dependent on the concentrations of the reacting species and the presence of catalysts, if any, rather than on the position of equilibrium itself.
Reaction Kinetics
Reaction kinetics is the study of the rates of chemical reactions and the factors that affect these rates. It focuses on understanding how different conditions such as concentration, temperature, and catalysts influence the speed at which reactants are converted into products.

A detailed kinetic analysis allows chemists to decipher the rate law for a reaction, which mathematically relates the rate of reaction to the concentrations of reactants. Each reactant in the rate law is assigned an order, which is not necessarily the same as its stoichiometric coefficient in the balanced equation.

It's important to remember that while equilibrium considerations tell us about the final concentration distribution of reactants and products, kinetics provides insights into how fast the equilibrium will be reached. Therefore, a complete understanding of a chemical reaction requires both thermodynamic and kinetic considerations.
Stoichiometric Coefficients
Stoichiometric coefficients play an integral role in chemical equations, as they represent the proportions in which reactants combine and products form. These coefficients are essential for balancing chemical reactions and for calculating the equilibrium constant.

When writing the expression for the equilibrium constant, the concentrations of the reactants and products are raised to the power of their respective stoichiometric coefficients in the balanced equation. This ensures that the law of mass action, the foundation for describing a system at equilibrium, is satisfied.

While stoichiometric coefficients indicate the ratio of the amounts of substances involved in a reaction, they are not indicators of the rate at which reactants will convert into products. Kinetics, on the other hand, considers the dynamic aspects of reaction rates and is concerned with factors that influence how quickly a reaction proceeds toward equilibrium.

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Most popular questions from this chapter

An organic compound A can decompose by either of two kinetically controlled pathways to form products B or C (see Exercis 14.79). The activation energy for the formation of \(B\) is greater than that for the formation of \(\mathrm{C}\). Will the ratio \([\mathrm{B}] /[\mathrm{C}]\) increase or decrease as the temperature is increased? Explain your answer.

Ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\), forms \(\cdot \mathrm{CH}_{3}\) radicals at \(700 .^{\circ} \mathrm{C}\) in a firstorder reaction, for which \(k=1.98 \mathrm{~h}^{-1}\). (a) What is the half-life for the reaction? (b) Calculate the time needed for the amount of ethane to fall from \(1.15 \times 10^{-3} \mathrm{~mol}\) to \(2.35 \times 10^{-4} \mathrm{~mol}\) in a 500.-mL reaction vessel at \(700 .{ }^{\circ} \mathrm{C}\). (c) How much of a 6.88-mg sample of ethane in a \(500 .-\mathrm{mL}\) reaction vessel at \(700 .{ }^{\circ} \mathrm{C}\) will remain after \(45 \mathrm{~min}\) ?

Consider the reaction \(\mathrm{A} \rightleftarrows \mathrm{B}\), which is first order in each direction with rate constants \(k\) and \(k^{\prime}\). Initially, only A is present. Show that the concentrations approach their equilibrium values at a rate that depends on \(k\) and \(k^{\prime}\).

The decomposition of A has the rate law Rate \(=k[\mathrm{~A}]^{a}\). Show that for this reaction the ratio \(t_{1 / 2} / t_{3 / 4}\), where \(t_{1 / 2}\) is the halflife and \(t_{3 / 4}\) is the time for the concentration of A to decrease to \(\frac{3}{4}\) of its initial concentration, can be written as a function of \(a\) alone and can therefore be used to make a quick assessment of the order of the reaction in A.

The Michaelis constant \(\left(K_{M}\right)\) is an index of the stability of an enzyme-substrate complex. Does a high Michaelis constant indicate a stable or an unstable enzyme-substrate complex? Explain your reasoning.

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