Chapter 17: Problem 59
Calculate the energy in joules that is equivalent to (a) \(1.0 \mathrm{~g}\) of matter; (b) one electron; (c) \(1.0 \mathrm{pg}\) of matter; (d) one proton.
Short Answer
Expert verified
The energy equivalent is (a) \(9.00 \times 10^{13}\) joules for 1.0 g of matter, (b) approximately \(8.2 \times 10^{-14}\) joules for one electron, (c) \(9.00 \times 10^{4}\) joules for 1.0 pg of matter, and (d) approximately \(1.5 \times 10^{-10}\) joules for one proton.
Step by step solution
01
Identify the energy-mass equivalence formula
The energy equivalent of a mass m can be calculated using Albert Einstein's energy-mass equivalence formula, which is given by: \( E = mc^2 \), where \(E\) is the energy in joules, \(m\) is the mass in kilograms, and \(c\) is the speed of light in vacuum, approximately \(3.00 \times 10^8 \text{ m/s} \).
02
Convert the mass from grams to kilograms
For part (a), convert the given mass from grams to kilograms by dividing by \(1000\), because there are \(1000\) grams in a kilogram. So, \(1.0\) gram is \(1.0 \times 10^{-3}\) kilograms.
03
Calculate the energy for 1.0 gram of matter
Using the formula and the converted mass, calculate the energy for \(1.0 \mathrm{~g}\) of matter by substituting the values into the formula, \(E = (1.0 \times 10^{-3}) \times (3.00 \times 10^8)^2\).
04
Convert picograms to kilograms
For part (c), convert the given mass from picograms to kilograms. Since there are \(1.0 \times 10^{12}\) picograms in a gram, and \(1000\) grams in a kilogram, \(1.0 \mathrm{pg} = 1.0 \times 10^{-15}\) kilograms.
05
Calculate the energy for 1.0 picogram of matter
Now, calculate the energy for \(1.0 \mathrm{pg}\) of matter using the formula with the converted picogram mass, \(E = (1.0 \times 10^{-15}) \times (3.00 \times 10^8)^2\).
06
Obtain mass and energy equivalence for one electron
For part (b), use the known rest mass of an electron, which is about \(9.11 \times 10^{-31}\) kilograms, and apply it in the equation \(E = mc^2\) to find the energy equivalent.
07
Obtain mass and energy equivalence for one proton
For part (d), use the known rest mass of a proton, which is about \(1.67 \times 10^{-27}\) kilograms, and apply it in the equation \(E = mc^2\) to find the energy equivalent.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Einstein's Energy-Mass Equivalence Formula
Albert Einstein's landmark energy-mass equivalence formula, represented as \( E = mc^2 \), establishes that energy (\( E \)) and mass (\( m \)) are interconvertible. This principle forms the backbone of modern physics, profoundly demonstrating that mass can be converted into tremendous amounts of energy, alluding to the boundless potential tucked within even the smallest measures of matter.
The speed of light (\( c \)), approximately \( 3.00 \times 10^8 \text{ m/s} \) , is a crucial constant in this formula, reflecting its significance in the realm of physics as a fundamental natural speed limit. The equation implies that even a minuscule amount of mass can generate a significant amount of energy, underlining the exponential nature of the relationship facilitated by the square of the speed of light.
Understanding this formula is essential, as it sets the stage for various applications, from understanding the principles behind nuclear power to grasping the implications of particle physics. Einstein's insight that mass and energy are but two sides of the same coin has revolutionized our perception of the universe.
The speed of light (\( c \)), approximately \( 3.00 \times 10^8 \text{ m/s} \) , is a crucial constant in this formula, reflecting its significance in the realm of physics as a fundamental natural speed limit. The equation implies that even a minuscule amount of mass can generate a significant amount of energy, underlining the exponential nature of the relationship facilitated by the square of the speed of light.
Understanding this formula is essential, as it sets the stage for various applications, from understanding the principles behind nuclear power to grasping the implications of particle physics. Einstein's insight that mass and energy are but two sides of the same coin has revolutionized our perception of the universe.
Converting Mass Units
The process of converting mass units is a fundamental skill in physics and chemistry. The International System of Units (SI) standard unit of mass is the kilogram (\( \text{kg} \)), whereas mass may also be expressed in grams (\( \text{g} \)) or picograms (\( \text{pg} \)), among others.
To calculate energy using Einstein's formula, converting mass into kilograms is imperative. Here’s a quick reference for converting mass units:
These conversions ensure that mass is accurately translated into the SI unit so that it can be properly utilized in the energy-mass equivalence equation. Being conversant with unit conversions is crucial for precision in scientific calculations, and failing to convert correctly can result in significant errors in the measurement of energy.
To calculate energy using Einstein's formula, converting mass into kilograms is imperative. Here’s a quick reference for converting mass units:
- 1 gram (\( \text{g} \)) = \( 10^{-3} \text{ kg} \)
- 1 picogram (\( \text{pg} \)) = \( 10^{-12} \text{ g} \) or \( 10^{-15} \text{ kg} \)
These conversions ensure that mass is accurately translated into the SI unit so that it can be properly utilized in the energy-mass equivalence equation. Being conversant with unit conversions is crucial for precision in scientific calculations, and failing to convert correctly can result in significant errors in the measurement of energy.
Calculating Energy for Mass
When it comes to calculating the energy equivalent of a given mass using Einstein’s formula, accurate unit conversion is only the first step. Once mass is expressed in kilograms, it becomes straightforward to insert it into the formula \(E = mc^2\) to calculate energy in joules (J).
To illustrate, for an amount of mass like \(1.0 \text{g}\), which is \(1.0 \times 10^{-3} \text{kg}\), the energy calculation would be \(E = (1.0 \times 10^{-3} \text{kg}) \times (3.00 \times 10^8 \text{ m/s})^2\). This demonstrates not only the conversion from grams to kilograms but also the insertion of known values into Einstein's equation to compute energy.
For students dealing with various mass units, such as picograms or the rest mass of subatomic particles like electrons and protons, remembering to use the equivalent kilogram values is crucial. Demonstrating these calculations for different units helps solidify the understanding of the energy-mass relationship and allows students to appreciate the universality of Einstein's equation across different scales of mass.
To illustrate, for an amount of mass like \(1.0 \text{g}\), which is \(1.0 \times 10^{-3} \text{kg}\), the energy calculation would be \(E = (1.0 \times 10^{-3} \text{kg}) \times (3.00 \times 10^8 \text{ m/s})^2\). This demonstrates not only the conversion from grams to kilograms but also the insertion of known values into Einstein's equation to compute energy.
For students dealing with various mass units, such as picograms or the rest mass of subatomic particles like electrons and protons, remembering to use the equivalent kilogram values is crucial. Demonstrating these calculations for different units helps solidify the understanding of the energy-mass relationship and allows students to appreciate the universality of Einstein's equation across different scales of mass.