Arrange the anions \(\mathrm{Cl}^{-}, \mathrm{Br}^{-}, \mathrm{N}^{3-}\), and \(\mathrm{O}^{2-}\) in order of increasing polarizability and give reasons for your decisions.

Short Answer

Expert verified
\(\mathrm{Cl}^{-} < \mathrm{Br}^{-} < \mathrm{N}^{3-} < \mathrm{O}^{2-}\) in order of increasing polarizability, attributed to increasing ionic size and electron cloud diffuseness.

Step by step solution

01

Understanding Polarizability

Polarizability refers to how easily an anion's electron cloud can be distorted by an electric field or by the positive charge of a nearby cation. Generally, the larger the anion and the more diffuse its electron cloud, the more polarizable it is.
02

Consideration of Ionic Size

The sizes of the anions typically increase with increasing atomic radius and with a decrease in the nuclear charge experienced by the valence electrons. This tends to make larger anions more easily polarizable because their valence electrons are farther from the nucleus and more loosely held.
03

Arrange Anions by Size

Based on periodic trends, the ionic radii increase going down the group in the periodic table. Thus, among halides, we can expect \(\mathrm{Cl}^{-}\) to be smaller than \(\mathrm{Br}^{-}\). For nonmetals in the same period, the size increases with an increase in negative charge due to greater electron-electron repulsion. Therefore, \(\mathrm{O}^{2-}\) is larger than \(\mathrm{N}^{3-}\) despite being in the same period.
04

Final Arrangement

Taking into account the size and electronic configurations, we can arrange the anions in order of increasing polarizability as follows: \(\mathrm{Cl}^{-} < \mathrm{Br}^{-} < \mathrm{N}^{3-} < \mathrm{O}^{2-}\). This is because \(\mathrm{Cl}^{-}\) and \(\mathrm{Br}^{-}\) are smaller and less polarizable than \(\mathrm{N}^{3-}\) and \(\mathrm{O}^{2-}\), and \(\mathrm{N}^{3-}\), being smaller in size compared to \(\mathrm{O}^{2-}\), is less polarizable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Anion Electron Cloud Distortion
When discussing the polarizability of an anion, we are essentially talking about its susceptibility to distortion under the influence of an electric field, often created by a nearby cation. This distortion occurs because the negatively charged electron cloud that surrounds the nucleus is attracted to the positive charge of the cation. Consequently, the shape and distribution of the electron cloud change, with more electron density shifting towards the cation.

The ease with which this distortion happens is critical for understanding many chemical phenomena. For instance, polarizable anions tend to enhance the strength of ionic bonds by allowing for greater interaction with cations. This has implications in solubility, reactivity, and even the physical properties of ionic compounds. As an educator, ensuring students can visualize this 'push and pull' effect on electron clouds can deepen their conceptual grasp of intermolecular forces and perceptive chemical reasoning.
Ionic Size and Polarizability
Delving into the link between ionic size and polarizability unveils why certain anions are more easily distorted than others. As ions increase in size, their outer electrons become more distant from the positively charged nucleus. This results in a weaker electrostatic attraction in those larger anions, making it less difficult for an external electric field, like that of an adjacent cation, to warp the electron cloud.

Moreover, ions with a greater volume also possess a more diffuse electron cloud. It's much like a loosely held balloon filled with air; it is easier to change its shape compared to a tightly inflated one. In chemical terms, more loosely held electron clouds on larger anions translate to higher polarizability. In teaching such concepts, using vivid analogies helps students to 'picture' the physical nature of ions, thereby fostering a practical sense of how size and polarizability are intertwined.
Periodic Trends in Ionic Radii
The periodic table is not just a simple chart of elements; it's a roadmap of trends and patterns that govern an element's characteristics. Regarding ionic radii, there is a general trend observed: as one moves down a group, the ions tend to get larger due to the addition of electron shells. Conversely, going across a period, the size decreases as the effective nuclear charge drawing in the electron cloud increases.

Thus, these periodic trends provide a scaffold to predict polarizability. Ions down a group are generally more polarizable owing to their larger size and more extensive electron clouds. A good pedagogical approach is to have students regularly analyze and predict properties like polarizability using periodic trends, instilling in them the coherence and logic underpinning the periodic table. Not only is this essential for honing problem-solving skills, but it also reinforces the interconnected nature of chemical properties.

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Most popular questions from this chapter

Draw resonance structures for the trimethylenemethane anion \(\mathrm{C}\left(\mathrm{CH}_{2}\right)_{3}{ }^{2-}\) in which a central carbon atom is attached to three \(\mathrm{CH}_{2}\) groups ( \(\mathrm{CH}_{2}\) groups are referred to as methylene).

Which of the following species are radicals? (a) \(\mathrm{NO}_{2}{ }^{-}\); (b) \(\mathrm{CH}_{3}\); (c) \(\mathrm{OH}\); (d) \(\mathrm{CH}_{2} \mathrm{O}\).

The perchlorate ion, \(\mathrm{ClO}_{4}^{-}\), is described by resonance structures. (a) Draw the Lewis structures that contribute to the resonance hyhrid and identify the most plawsible Lewis structures by using formal charge arguments. (b) The average length of a single \(\mathrm{Cl}-\mathrm{O}\) bond is 172 pm and that of a double \(\mathrm{Cl}=\mathrm{O}\) bond can be estimated at \(140 \mathrm{pm}\). The Cl-O bond length in the perchlorate ion is found experimentally to be \(144 \mathrm{pm}\) for all four bonds. Identify the most plausible Lewis structures of the perchlorate ion from these experimental data. (c) What is the oxidation mumber of chlorine in the perchlorate ion? Identify the most plausible Lewis structure by using the coxidation number, assuming that lone pairs belong to the atom to which they are attached but that all electrons shared in a bond helong to the atom of the more negative element. (d) Are these three approaches consistent? Explain why or why not.

Arrange the cations \(\mathrm{Rb}^{+}, \mathrm{Be}^{2+}\), and \(\mathrm{Sr}^{2+}\) in order of increasing polarizing power. Give an explanation of your arrangement.

Write the Lewis structure, including resonance structures where appropriate, for (a) the oxalate ion, \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\) (there is a \(\mathrm{C}-\mathrm{C}\) bond with two oxygen atoms attached to each carbon atom); (b) \(\mathrm{BrO}^{+}\); (c) the acetylide ion, \(\mathrm{C}_{2}{ }^{2-}\). Assign formal charges to each atom.

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