Iron crystallizes in a bec structure. The atomic radius of iron is \(124 \mathrm{pm}\). Determine (a) the number of atoms per unit cell; (b) the coordination number of the lattice; (c) the length of the side of the unit cell.

Short Answer

Expert verified
For a body-centered cubic (BCC) crystal structure of Iron: (a) There are 2 atoms per unit cell; (b) The coordination number of the lattice is 8; (c) The length of the side of the unit cell is approximately 286.74 pm.

Step by step solution

01

Identify the Crystal Structure

Determine the crystal structure of iron. In this case, iron crystallizes in a body-centered cubic (bcc) structure. This information helps deduce the number of atoms per unit cell and the coordination number.
02

Calculate the Number of Atoms per Unit Cell for BCC

In a body-centered cubic structure, there is one atom at each corner of the cube and one atom at the center. Each corner atom is shared among eight unit cells and the center atom belongs entirely to one unit cell. Thus, the number of atoms per unit cell in a bcc structure is calculated as: 8 atoms (at corners) * 1/8 (portion of each corner atom within the unit cell) + 1 atom (at center) * 1 (entirely within the cell) = 1 + 1 = 2.
03

Determine the Coordination Number for BCC

The coordination number is the number of nearest neighbor atoms to a given atom. In a body-centered cubic structure, each atom is in direct contact with 8 other atoms: 4 atoms in the same layer and 4 atoms in the adjacent layers. Hence, the coordination number for bcc is 8.
04

Calculate the Length of the Side of the Unit Cell

In a bcc crystal, the diagonal passing through the body of the cube connects two opposite corner atoms passing through the center atom. This diagonal is composed of four atomic radii (2 x radius for each atom). The diagonal can also be expressed in terms of the unit cell side length (a), as the diagonal of a cube which is \(a\sqrt{3}\). Equating and solving for side length a, we get: \[a\sqrt{3} = 4r\] \[a = \frac{4r}{\sqrt{3}}\] Substituting the given value of atomic radius \(r = 124 \mathrm{pm}\), the side length a becomes: \[a = \frac{4(124 \mathrm{pm})}{\sqrt{3}}\approx 286.74 \mathrm{pm}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Crystallography
Crystallography is the science that examines the arrangement of atoms in crystalline solids. One common structure that emerges in the realm of crystallography is the body-centered cubic (bcc) structure, which is of particular interest when exploring the properties of metals, such as iron.

In this structure, atoms are positioned at each corner of a cube and a single atom is located at the very center, resulting in a distinctive geometric pattern. The bcc arrangement contributes significantly to the physical characteristics of a metal, such as its density and how it interacts with light. The study of crystallography not only aids in identifying these structures but also in comprehending the behaviors of materials on an atomic level, influencing how they are utilized in various applications.
Decoding Coordination Number
The concept of the coordination number is a central pillar in understanding crystal structures. It signifies the number of nearest-neighbor atoms that surround a given atom in a crystal lattice.

For the body-centered cubic structure, the coordination number is 8. This illustrates that each atom is immediately surrounded by 8 other atoms: 4 in the same plane and an additional 4 from the adjacent planes above and below. This number is not just a count; it intimates the degree of an atom’s interaction with its surrounding neighbors, playing a critical role in determining the physical and chemical properties of a material, such as its stability, melting point, and possible reactivity.
Unpacking Unit Cell Geometry
When examining the microscopic world of crystals, 'unit cell geometry' emerges as a fundamental concept. It delineates the smallest repeating unit that mirrors the entirety of a crystal's structure, often visualized as a geometric shape like a cube in the case of a bcc structure.

The unit cell of the bcc crystal is pivotal because it defines the spatial arrangement of the atoms and the dimensions of the crystal as a whole. The side length of this cube, often referred to as 'a', can be mathematically related to the atomic radius through the cube's body diagonal, which is the line connecting opposite corners passing through the center. Understanding these geometric relationships enables the calculation of critical material constants such as density, and it provides insight into mechanical properties like the material's response to stress.

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Most popular questions from this chapter

Ethylammonium nitrate, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{3} \mathrm{NO}_{3}\), was the first ionic liquid to be discovered. Its melting point of \(12^{\circ} \mathrm{C}\) was reported in 1914 and it has since been used as a nonpolluting solvent for organic reactions and for facilitating the folding of protcins. (a) Draw the Lewis structure of each ion in ethylammonium nitrate and indicate the formal charge on each atom (in the cation, the carbon atoms are attached to the \(N\) atom in a chain: \(\mathrm{C}-\mathrm{C}-\mathrm{N})\). (b) Assign a hybridization scheme to each \(\mathrm{C}\) and \(\mathrm{N}\) atom. (c) Ethylammonium nitrate cannot be used as a solvent for some reactions because it can oxidize some compounds. Which ion is more likely to be the oxidizing agent, the cation or anion? Explain your answer. (d) Ethylammonium nitrate can be prepared by the reaction of gaseous ethylamine, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\), and aqueous nitric acid. Write the chemical equation for the reaction. What type of reaction is this? (e) \(2.00 \mathrm{~L}\) of ethylamine at \(0.960\) atm and \(23.2^{\circ} \mathrm{C}\) was bubbled into \(2.50 .0 \mathrm{~mL}\) of \(0.240 \mathrm{M} \mathrm{HNO}_{3}(\mathrm{aq})\) and \(4.10 \mathrm{~g}\) of ethylammonium nitrate was produced. What were the theoretical and percentage yields of the salt? (f) Suggest ways in which the forces that hold ethylammonium nitrate ions together in the solid state differ from those that hold together salts such as sodium chloride or sodium bromide. (g) Low-melting salts in which the cation is inorganic and the anion organic have been prepared. Explain the trend in melting point seen in the following series: sodium acetate \(\left(\mathrm{NaCH}_{3} \mathrm{CO}_{2}\right)\), \(324^{\circ} \mathrm{C}\); sodium propanoate \(\left(\mathrm{NaCH}_{3} \mathrm{CH}_{2} \mathrm{CO}_{2}\right), 285^{\circ} \mathrm{C}\); sodium butanoate \(\left(\mathrm{NaCH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2}\right), 76^{\circ} \mathrm{C}\); and sodium pentanoate \(\left(\mathrm{NaCH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CO}_{2}\right), 64^{\circ} \mathrm{C}\).

Which of the following molecules are likely to form hydrogen bonds: (a) \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\); (b) \(\mathrm{CH}_{3} \mathrm{COOH}\); (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\); (d) \(\mathrm{CH}_{3} \mathrm{CHO}\) ?

The molecular structures of many common liquid crystals are long and rodlike. In addition, they contain polar groups. Explain how both characteristics of liquid crystals contribute to their anisotropic nature.

Account for the following observations in terms of the type and strength of intermolecular forces. (a) The melting point of solid xenon is \(-112^{\circ} \mathrm{C}\) and that of solid argon is \(-189^{\circ} \mathrm{C}\). (b) The vapor pressure of diethyl ether \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}\right)\) is greater than that of water. (c) The boiling point of pentane, \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{3} \mathrm{CH}_{3}\), is \(36.1^{\circ} \mathrm{C}\), whereas that of 2,2 -dimethylpropane (also known as neopentane \(), \mathrm{C}\left(\mathrm{CH}_{3}\right)_{4}\), is \(9.5^{\circ} \mathrm{C}\).

Using the VSEPR model, predict the shapes of each of the following molecules and identify the member of each pair with the higher boiling point: (a) \(\mathrm{PBr}_{3}\) or \(\mathrm{PF}_{3} ;\) (b) \(\mathrm{SO}_{2}\) or \(\mathrm{CO}_{2} ;\) (c) \(\mathrm{BF}_{3}\) or \(\mathrm{BCl}_{3}\).

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