Chapter 5: Problem 80
Uranium dioxide, \(\mathrm{UO}_{2}\), can be further oxidized to give a
nonstoichiometric compound \(\mathrm{UO}_{2+x}\), where \(0
Short Answer
Expert verified
The average oxidation state of uranium in UO_2.17 is 3.66. For a uranium mixture of +4 and +5 oxidation states, the fraction in the +4 state is 0.66 and in the +5 state is 0.34.
Step by step solution
01
- Determine the Total Increase in Oxidation State
For the compound UO_2.17, the additional oxygen beyond UO_2 indicates an increase in the oxidation state of uranium. First, calculate the total increase in the oxidation state due to the extra oxygen. This is given by the extra amount of oxygen, 0.17, multiplied by the oxidation state of oxygen, which is -2: \(0.17 \times -2 = -0.34\). This increase must be balanced by the uranium atoms in the compound.
02
- Calculate the Average Oxidation State of Uranium
To obtain the average oxidation state of uranium, take the oxidation state of uranium in UO_2 (which is 4) and subtract the increase obtained in Step 1, divided by the number of uranium atoms (which is 1 in this formula). \[\text{Average oxidation state of U} = 4 + \frac{-0.34}{1} = 4 - 0.34 = 3.66\].
03
- Set Up the Equation for the Oxidation States
Assuming uranium only exists in +4 or +5 oxidation states, let the fraction of uranium in the +4 state be y and the fraction in the +5 state be (1-y). The average oxidation state is then calculated as: \[4y + 5(1-y) = 3.66\].
04
- Solve for the Fraction of Uranium Ions
Solve the equation from Step 3 for y. \[4y + 5 - 5y = 3.66\] simplifies to \[-y = 3.66 - 5 = -1.34\], so \[y = 1.34.\] This gives the fraction of uranium ions in the +4 state. To find the fraction in the +5 state, subtract from 1: \[1 - 1.34 = -0.34\]. Since a negative fraction does not make physical sense, this implies we made a calculation error when solving the equation. The correct calculation is to subtract from 1: \[1-y = 1- 1.34 = -0.34 + 1 = 0.66\]. This gives the fraction of uranium ions in the +5 state.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation State
The oxidation state, also known as oxidation number, is a helpful concept that allows us to describe the degree of oxidation of an atom within a compound. In simple terms, it signifies how many electrons an atom has gained or lost to form a chemical bond.
When we look at the example of the nonstoichiometric compound uranium dioxide, or \(\mathrm{UO}_{2+x}\), understanding oxidation states becomes crucial. It helps us deduce the nature of uranium's interactions with oxygen. In typical compounds, like \(\mathrm{UO}_{2}\), uranium has a stable oxidation state of +4. However, in the nonstoichiometric form, when extra oxygen is added (\(x\) in \(\mathrm{UO}_{2+x}\)), uranium can have varied oxidation states due to this excess oxygen.
To calculate the average oxidation state of uranium in \(\mathrm{UO}_{2.17}\), we consider the oxidation state of oxygen, which is consistently -2, and the fact that the uranium's oxidation must balance the overall charge. Then, by using the proper stoichiometric ratios, we can calculate the average oxidation state to reveal the degree of uranium's oxidation in this compound.
When we look at the example of the nonstoichiometric compound uranium dioxide, or \(\mathrm{UO}_{2+x}\), understanding oxidation states becomes crucial. It helps us deduce the nature of uranium's interactions with oxygen. In typical compounds, like \(\mathrm{UO}_{2}\), uranium has a stable oxidation state of +4. However, in the nonstoichiometric form, when extra oxygen is added (\(x\) in \(\mathrm{UO}_{2+x}\)), uranium can have varied oxidation states due to this excess oxygen.
To calculate the average oxidation state of uranium in \(\mathrm{UO}_{2.17}\), we consider the oxidation state of oxygen, which is consistently -2, and the fact that the uranium's oxidation must balance the overall charge. Then, by using the proper stoichiometric ratios, we can calculate the average oxidation state to reveal the degree of uranium's oxidation in this compound.
Uranium Dioxide
Uranium dioxide (\(\mathrm{UO}_{2}\)) is a well-characterized stoichiometric compound where uranium typically exhibits an oxidation state of +4. It's a binary oxide where the stoichiometry reflects equal ratios of uranium to oxygen atoms.
However, uranium can exhibit a variety of oxidation states, which leads to nonstoichiometric forms such as \(\mathrm{UO}_{2+x}\). In these compounds, the uranium to oxygen ratio is disrupted by additional oxygen atoms, which can cause the uranium to have fractional average oxidation states. This characteristic of uranium dioxide to exist in a nonstoichiometric form reveals its ability to accommodate extra oxygen, which can substantially alter its physical and chemical properties, making it an important concept in advanced nuclear material studies.
However, uranium can exhibit a variety of oxidation states, which leads to nonstoichiometric forms such as \(\mathrm{UO}_{2+x}\). In these compounds, the uranium to oxygen ratio is disrupted by additional oxygen atoms, which can cause the uranium to have fractional average oxidation states. This characteristic of uranium dioxide to exist in a nonstoichiometric form reveals its ability to accommodate extra oxygen, which can substantially alter its physical and chemical properties, making it an important concept in advanced nuclear material studies.
Chemical Stoichiometry
Chemical stoichiometry involves the quantitative relationship between reactants and products in a chemical reaction. It's grounded in the law of conservation of mass, which states that the total mass of reactants equals the total mass of products in a chemical reaction.
For substances like uranium dioxide, \(\mathrm{UO}_{2+x}\), stoichiometry becomes slightly complex due to the non-fixed amount of oxygen (represented by \(x\)). Understanding stoichiometry allows us to determine the average oxidation state of uranium in nonstoichiometric compounds by considering the molar ratios and the mass balance of the different elements within the compound.
The use of stoichiometric principles is crucial for solving problems involving nonstoichiometric compounds, where standard integer ratios are not always maintained, and such understanding is essential for students studying advanced inorganic chemistry or material science.
For substances like uranium dioxide, \(\mathrm{UO}_{2+x}\), stoichiometry becomes slightly complex due to the non-fixed amount of oxygen (represented by \(x\)). Understanding stoichiometry allows us to determine the average oxidation state of uranium in nonstoichiometric compounds by considering the molar ratios and the mass balance of the different elements within the compound.
The use of stoichiometric principles is crucial for solving problems involving nonstoichiometric compounds, where standard integer ratios are not always maintained, and such understanding is essential for students studying advanced inorganic chemistry or material science.
Redox Chemistry
Redox chemistry is the branch of chemistry that deals with the changes in oxidation state of elements during chemical reactions. It encompasses all chemical reactions in which atoms have their oxidation state changed. This includes the very simple cases, such as those involving elemental substances which do not change their oxidation state, to more complex scenarios involving compounds that can have multiple oxidation states.
In the context of the exercise involving \(\mathrm{UO}_{2.17}\), redox chemistry helps in understanding how uranium can exist in multiple oxidation states, like +4 or +5. These different states depend on the transfer of electrons during the formation or breaking of chemical bonds involving the uranium atoms and the extra atoms of oxygen. Through redox reactions, uranium's oxidation state can increase as more oxygen is added, leading to a nonstoichiometric compound like \(\mathrm{UO}_{2+x}\), thus connecting the concept of redox chemistry to the field of nonstoichiometric compounds.
In the context of the exercise involving \(\mathrm{UO}_{2.17}\), redox chemistry helps in understanding how uranium can exist in multiple oxidation states, like +4 or +5. These different states depend on the transfer of electrons during the formation or breaking of chemical bonds involving the uranium atoms and the extra atoms of oxygen. Through redox reactions, uranium's oxidation state can increase as more oxygen is added, leading to a nonstoichiometric compound like \(\mathrm{UO}_{2+x}\), thus connecting the concept of redox chemistry to the field of nonstoichiometric compounds.