Samples consisting of \(1 \mathrm{~mol} \mathrm{~N}\) and \(1 \mathrm{~mol} \mathrm{} \mathrm{CH}_{4}\) are in identical but separate containers, with initial temperatures of 500. K. Both gases gain 1200 . J of heat at constant volume. Do the gases have the same final temperature? If not, which gas has the higher final temperature? Justify your reasoning.

Short Answer

Expert verified
No, the gases do not have the same final temperature. Methane (CH4), with the smaller heat capacity, will have the higher final temperature.

Step by step solution

01

Identify the Known Variables

Firstly, identify what is given: both gases have initial temperatures of 500 K, both receive 1200 J of heat, and both samples consist of 1 mol of substance.
02

Apply the Formula for Heat Transfer at Constant Volume

Use the equation for heat transfer at constant volume, which is given by: \( q = n C_v \Delta T \). Here, \( q \) is the heat transferred, \( n \) is the number of moles, \( C_v \) is the molar heat capacity at constant volume, and \( \Delta T \) is the change in temperature.
03

Calculate the Heat Capacity for Nitrogen (N2)

For 1 mol of a diatomic gas like nitrogen at constant volume, the heat capacity (Cv) is \( \frac{5}{2}R \), where R is the ideal gas constant with a value of 8.314 J/(mol K).
04

Calculate the Change in Temperature for Nitrogen (N2)

Using the heat transfer equation for nitrogen, rearrange to find the change in temperature: \( \Delta T = \frac{q}{nC_v} = \frac{1200 J}{1 mol \times \frac{5}{2} \times 8.314 J/(mol \cdot K)} \). Calculate the value to find the change in temperature for nitrogen.
05

Determine the Final Temperature for Nitrogen (N2)

Add the initial temperature to the change in temperature to find the final temperature: \( T_{final} = T_{initial} + \Delta T \).
06

Calculate the Heat Capacity for Methane (CH4)

The heat capacity at constant volume for methane (a non-linear triatomic gas) can be approximated as \( \frac{3}{2}R \).
07

Calculate the Change in Temperature for Methane (CH4)

Using the heat transfer equation for methane, calculate the change in temperature in a similar way to nitrogen: \( \Delta T = \frac{q}{nC_v} = \frac{1200 J}{1 mol \times \frac{3}{2} \times 8.314 J/(mol \cdot K)} \).
08

Determine the Final Temperature for Methane (CH4)

Similarly, add the initial temperature to the change in temperature to find the final temperature for methane: \( T_{final} = T_{initial} + \Delta T \).
09

Compare Final Temperatures and Conclude

Now we compare the calculated final temperatures of nitrogen and methane to determine which one has the higher final temperature. The one with the smaller heat capacity (methane, in this case) will show a larger temperature change for the same amount of heat added, thus resulting in a higher final temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constant Volume Heat Capacity
When we talk about constant volume heat capacity (\( C_v \)), we're discussing how much heat energy is required to raise the temperature of a substance by 1 degree Celsius (or 1 Kelvin) when the volume remains unchanged. In a more technical sense, it's a measure of the energy storage of a gas per unit temperature change under the condition of constant volume.

For example, diatomic gases like nitrogen (\( N_2 \)) have a constant volume heat capacity of approximately \( \frac{5}{2}R \) (where \( R \) is the ideal gas constant). This is due to their molecular structure, which influences how they store energy. Similarly, more complex molecules like methane (\( CH_4 \)) have different heat capacities, typically \( \frac{3}{2}R \) for non-linear triatomic gases. This difference is crucial for understanding how different gases respond to heat addition in closed systems.

Key takeaway:
  • \( C_v \) is an intrinsic property of a substance that can help us predict how the temperature of a gas will change when energy is added or removed.
Temperature Change Calculation
How do we calculate the change in temperature of a gas when it's heated at constant volume? The formula to determine this is quite straightforward:\[ \Delta T = \frac{q}{nC_v} \]where \( \Delta T \) is the temperature change, \( q \) is the amount of heat transferred, \( n \) is the number of moles of gas, and \( C_v \) is the constant volume heat capacity.

In the exercise, we apply this equation to find out how much the temperature of the gas rises after adding 1200 J of heat to 1 mole of nitrogen and methane respectively. Since the gases have different heat capacities, the calculated temperature changes (\( \Delta T \)) will also be different, leading to different final temperatures even though the initial temperatures and heat added were the same.

Essential to remember:
  • The heat capacity of the gas influences the outcome of the temperature change calculation, underscoring the importance of knowing this property to predict the behavior of gases.
Thermodynamics of Gases
The thermodynamics of gases is a vast and crucial area in physics that explains the behavior of gases under various conditions like temperature, volume, and pressure changes. It draws on concepts from the kinetic theory of gases and the laws of thermodynamics. In our context, we're mostly interested in how these concepts apply to heat transfer.

The exercise demonstrates a scenario in the thermodynamic study of gases where we consider the energy (heat) input to a system at a constant volume. It allows students to engage with such fundamental principles as the conservation of energy, relationship between heat and temperature, and the molecular properties of gases.

Integrating knowledge:
  • Understanding the thermodynamics of gases, including constant volume processes, is fundamental in predicting how they will behave when subjected to thermal processes in closed systems.
  • It ties together the microscopic molecular structure of gases with macroscopic observable quantities like temperature change, which can be particularly insightful in fields that span from engineering to meteorology.

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Most popular questions from this chapter

The ABC cereal company is developing a new type of breakfast cereal to compete with a rival product that they call Brand X. You are asked to compare the energy content of the two cereals to see if the new \(A B C\) product is lower in calories; so you burn \(1.00-g\) samples of the cereals in oxygen in a calorimeter with a heat capacity of \(600 . \mathrm{J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1}\). When the Brand \(\mathrm{X}\) cereal sample burned, the temperature rose from \(300.2 \mathrm{~K}\) to \(309.0 \mathrm{~K}\). When the ABC cereal sample burned, the temperature rose from \(299.0 \mathrm{~K}\) to \(307.5 \mathrm{~K}\). (a) What is the heat output of each sample? (b) One serving of each cereal is \(30.0 \mathrm{~g}\). How would you label the packages of the two cereals to indicate the fuel value per \(30.0-\mathrm{g}\) serving in joules? in nutritional Calories (kilocalories)?

Which molecular substance do you expect to have the higher molar heat capacity, \(\mathrm{NO}\) or \(\mathrm{NO}_{2}\) ? Why?

(a) At its boiling point, the vaporization of \(0.579 \mathrm{~mol} \mathrm{CH}_{4}(\mathrm{l})\) requires \(4.76 \mathrm{~kJ}\) of heat. What is the enthalpy of vaporization of methane? (b) An electric heater was immersed in a flask of boiling ethanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), and \(22.45 \mathrm{~g}\) of ethanol was vaporized when \(21.2 \mathrm{~kJ}\) of energy was supplied. What is the enthalpy of vaporization of ethanol?

Identify the following systems as open, closed, or isolated: (a) coffee in a very high quality thermos bottle; (b) coolant in a refrigerator coil; (c) a bomb calorimeter in which benzene is burned; (d) gasoline burning in an automobile engine; (e) mercury in a thermometer; (f) a living plant.

(a) Calculate the work associated with the isothermal, reversible expansion of \(1.000 \mathrm{~mol}\) of an ideal gas from \(7.00 \mathrm{~L}\) to \(15.50 \mathrm{~L}\) at \(25.0^{\circ} \mathrm{C}\). (b) Calculate the work associated with the irreversible adiabatic expansion of the sample of gas described in part (a) against a constant atmospheric pressure of 760 . Torr. (c) How will the temperature of the gas in part (b) compare with that in part (a) after the expansion?

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