Chapter 7: Problem 55
The enthalpy of formation of trinitrotoluene (TNT) is \(-67 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), and the density of TNT is \(1.65 \mathrm{~g}^{-3} \mathrm{~cm}^{-3}\). In principle, it could be used as a rocket fuel, with the gases resulting from its decomposition streaming out of the rocket to give the required thrust. In practice, of course, it would be extremely dangerous as a fuel because it is sensitive to shock. Explore its potential as a rocket fuel by calculating its enthalpy density (enthalpy released per liter) for the reaction $$ \begin{aligned} 4 \mathrm{C}_{7} \mathrm{H}_{5} \mathrm{~N}_{3} \mathrm{O}_{6}(\mathrm{~s})+21 \mathrm{O}_{2}(\mathrm{~g}) & \longrightarrow \\ 28 \mathrm{CO}_{2}(\mathrm{~g})+10 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})+6 \mathrm{~N}_{2}(\mathrm{~g}) \end{aligned} $$
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