Chapter 7: Problem 59
The standard enthalpies of combustion of graphite and diamond are \(-393.51 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\) and \(-395.41 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), respectively. Calculate the enthalpy of the graphite \(\rightarrow\) diamond transition.
Short Answer
Expert verified
-1.90 kJ/mol
Step by step solution
01
Define the Enthalpy Change for Graphite Combustion
Start by noting the standard enthalpy of combustion for graphite, which is the energy change when one mole of graphite is burned in oxygen to form carbon dioxide under standard conditions. It is given as -393.51 kJ/mol.
02
Define the Enthalpy Change for Diamond Combustion
Similarly, note the standard enthalpy of combustion for diamond, which is the energy change when one mole of diamond is burned in oxygen to form carbon dioxide under standard conditions. It is given as -395.41 kJ/mol.
03
Calculate the Enthalpy Change for the Graphite to Diamond Transition
Use Hess's Law, which states that the total enthalpy change for a chemical reaction is the same, no matter how the reaction occurs in a series of steps. The enthalpy of the graphite to diamond transition can therefore be calculated using the combustion enthalpy values of graphite and diamond as follows:Enthalpy change for graphite to diamond transition = enthalpy change for diamond combustion - enthalpy change for graphite combustion. Thus, plugging in the values, we get: equal to -395.41 kJ/mol - (-393.51 kJ/mol) = -1.90 kJ/mol.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Enthalpy of Combustion
Understanding the concept of standard enthalpy of combustion is essential when exploring thermochemical processes. It's a term used to describe the amount of heat energy released when one mole of substance combusts completely in oxygen under standard conditions, which include a pressure of 1 bar and a temperature of 298.15 K (25°C).
For substances like graphite and diamond, which are different forms of carbon, these values are crucial for computing reactions' thermal behaviors. For instance, the standard enthalpy of combustion of graphite is (-393.51 kJ/mol). This signifies that 393.51 kJ of energy is released when a mole of graphite combusts. A slightly higher amount of energy is released in the combustion of diamond, with its value being (-395.41 kJ/mol).
This distinction may seem minute but is significant when calculating enthalpy changes in chemical transformations, as it represents the different bonding structures in graphite and diamond that lead to different energy requirements for combustion.
For substances like graphite and diamond, which are different forms of carbon, these values are crucial for computing reactions' thermal behaviors. For instance, the standard enthalpy of combustion of graphite is (-393.51 kJ/mol). This signifies that 393.51 kJ of energy is released when a mole of graphite combusts. A slightly higher amount of energy is released in the combustion of diamond, with its value being (-395.41 kJ/mol).
This distinction may seem minute but is significant when calculating enthalpy changes in chemical transformations, as it represents the different bonding structures in graphite and diamond that lead to different energy requirements for combustion.
Hess's Law
When dealing with complex chemical reactions, Hess's Law is a powerful tool that offers a simplified approach to calculate enthalpy changes. Named after Germain Hess, this law states that the total enthalpy change for a chemical reaction is the same, no matter how the process is carried out as long as the initial and final conditions are the same.
Hess's Law is founded on the principle of energy conservation and allows us to calculate the enthalpy changes of reactions that may be difficult or impractical to measure directly. By breaking a reaction into a series of steps for which the enthalpies are known, we can sum these enthalpy changes to determine the overall reaction enthalpy. It's a method that underlines the fact that enthalpy is a state function—it depends only on the initial and final states of the system, and not on the path taken to get there.
In the context of our problem, Hess's Law allows us to find the enthalpy change for the graphite to diamond transition indirectly, using the known enthalpy values of their combustions.
Hess's Law is founded on the principle of energy conservation and allows us to calculate the enthalpy changes of reactions that may be difficult or impractical to measure directly. By breaking a reaction into a series of steps for which the enthalpies are known, we can sum these enthalpy changes to determine the overall reaction enthalpy. It's a method that underlines the fact that enthalpy is a state function—it depends only on the initial and final states of the system, and not on the path taken to get there.
In the context of our problem, Hess's Law allows us to find the enthalpy change for the graphite to diamond transition indirectly, using the known enthalpy values of their combustions.
Enthalpy Change Calculations
The process of enthalpy change calculations is a fundamental aspect of thermodynamics and entails determining the heat exchange in chemical reactions. These calculations often use known values, such as standard enthalpies of combustion, formation, or reaction, to compute unknown enthalpy changes for processes.
To calculate the enthalpy change for the transition from graphite to diamond, we use the standard enthalpies of combustion for both forms of carbon. The calculation is based on the following logic: if we know how much energy is released when graphite and diamond combust separately, we can infer the energy difference required to turn graphite into diamond, without directly inducing or measuring that transformation.
The calculation reflects the difference in energy between the two states of carbon and is simply the enthalpy of diamond's combustion subtracted from graphite's combustion enthalpy: (-395.41 kJ/mol) - (-393.51 kJ/mol) = -1.90 kJ/mol. This result indicates that converting graphite into diamond requires an input of 1.90 kJ of energy per mole at standard conditions.
To calculate the enthalpy change for the transition from graphite to diamond, we use the standard enthalpies of combustion for both forms of carbon. The calculation is based on the following logic: if we know how much energy is released when graphite and diamond combust separately, we can infer the energy difference required to turn graphite into diamond, without directly inducing or measuring that transformation.
The calculation reflects the difference in energy between the two states of carbon and is simply the enthalpy of diamond's combustion subtracted from graphite's combustion enthalpy: (-395.41 kJ/mol) - (-393.51 kJ/mol) = -1.90 kJ/mol. This result indicates that converting graphite into diamond requires an input of 1.90 kJ of energy per mole at standard conditions.