Three isomeric alkenes have the formula \(\mathrm{C}_{4} \mathrm{H}_{8}\) (see the following table). (a) Draw Lewis structures of these compounds. (b) Calculate \(\Delta G^{\circ}, \Delta H^{\circ}\), and \(\Delta S^{\circ}\) for the three reactions that interconvert each pair of compounds. (c) Which isomer is the most stable? (d) Rank the isomers in order of decreasing \(S_{m}{ }^{\circ}\). \(\begin{array}{lrc} \text { Compound } & \Delta \mathrm{H}_{\mathrm{f}}{ }^{\circ}\left(\mathrm{kJ} \cdot \mathrm{mol}^{-1}\right) & \Delta \mathrm{G}_{\mathrm{f}}^{\circ}\left(\mathrm{kJ} \cdot \mathrm{mol}^{-1}\right) \\ \hline \text { 2-methylpropene } & -16.90 & +58.07 \\ \text { cis-2-butene } & -6.99 & +65.86 \\ \text { trans-2-butene } & -11.17 & +62.97 \\ \hline \end{array}\)

Short Answer

Expert verified
Draw Lewis structures for each isomer, calculate thermodynamic changes for each pair using the provided standard heats of formation and Gibbs free energies of formation, determine stability based on lowest Gibbs free energy of formation, and rank isomers by decreasing standard molar entropy.

Step by step solution

01

Draw Lewis Structures of C4H8 Isomers

Identify the possible isomers based on the molecular formula C4H8. Since these are alkenes, they will contain a carbon-carbon double bond. The three isomers described are 2-methylpropene, cis-2-butene, and trans-2-butene. - For 2-methylpropene, draw three carbon atoms in a chain with a double bond between the first two carbons; attach a methyl group (CH3) to the second carbon. - For cis-2-butene, draw a four-carbon chain with a double bond between the second and third carbons; ensure that the two substituents on the double-bonded carbons are on the same side. - For trans-2-butene, draw a similar structure to cis-2-butene, but with the substituents on the double-bonded carbons on opposite sides.
02

Calculate the ΔG°, ΔH°, and ΔS° for each pair

Use the thermodynamic equations to calculate ΔG°, ΔH°, and ΔS° for each pair of isomers. The equations are: \(\Delta G^\circ = \Delta H^\circ - T \Delta S^\circ\), where T is the temperature in Kelvin (standard conditions use T=298 K). Since we are looking at the changes between pairs of compounds, we use the provided formation values to determine the differences between each pair. Calculate ΔH° and ΔG° for each reaction by subtracting the values for isomer 2 from isomer 1. Then, use the ΔH° and ΔG° calculated values to find ΔS° using the rearranged equation \(\Delta S^\circ = \frac{\Delta H^\circ - \Delta G^\circ}{T}\).
03

Stability of the Isomers

To find out which isomer is the most stable, compare their standard Gibbs free energy of formation \(\Delta G_{\text{f}}^\circ\). The isomer with the lowest \(\Delta G_{\text{f}}^\circ\) is considered to be the most stable under standard conditions.
04

Rank Isomers in Order of Decreasing Standard Molar Entropy (Sm°)

Using the ΔS° values obtained from the calculations in Step 2, rank the isomers in order of decreasing standard molar entropy. The isomer with the highest ΔS° value will have the highest entropy, followed by the one with the next highest value, and so forth.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures

Understanding the Lewis structures of molecules is the first step towards grasping their chemical properties and behavior. In the context of alkenes with the formula \(\mathrm{C}_{4}\mathrm{H}_{8}\), Lewis structures help us visualize the arrangement of atoms and the distribution of electrons among them. Drawing these structures involves representing the valence electrons as dots surrounding the atomic symbols and indicating chemical bonds as lines. For alkenes, one key feature to represent is the double bond, which signifies a shared pair of electrons between two carbon atoms. This visualization provides insight into the molecule's geometry and potential for isomerism, evidenced by the different possible arrangements for 2-methylpropene, cis-2-butene, and trans-2-butene. An understanding of the molecular structure is critical to predicting the physical and chemical properties of these compounds.

Thermodynamics in Chemistry

Thermodynamics in chemistry is a field that studies the energy and heat associated with chemical reactions and changes in states of matter. It examines the principles that govern the energy transfers and conversions, which are essential for understanding the spontaneity and feasibility of chemical reactions. At the heart of this discipline are the laws of thermodynamics that describe the conservation of energy and the increase in entropy. In the study of alkenes, thermodynamic parameters such as enthalpy (\(\Delta H^{\circ}\)) and entropy (\(\Delta S^{\circ}\)) provide invaluable information on the heat exchange during formation and the disorder within the molecules, respectively. These measures are crucial for assessing the stability and reactivity of different alkene isomers.

Gibbs Free Energy

Gibbs free energy (\(\Delta G^\circ\)) is a thermodynamic quantity that predicts the direction of a chemical reaction under constant temperature and pressure. It represents the balance between enthalpy and entropy within a system, with its value indicating whether a reaction is spontaneous. The formula \(\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ\), where \(T\) stands for the temperature in Kelvin, signifies that a reaction with a negative \(\Delta G^\circ\) is energetically favorable at a given temperature. For the isomeric alkenes in our exercise, calculating \(\Delta G^\circ\) allows us to assess which transition between isomers is most likely to occur spontaneously, and generally, a lower \(\Delta G_{\text{f}}^\circ\) value correlates with increased stability of a compound.

Standard Molar Entropy

Standard molar entropy (\(S_m{ }^\circ\)) is a measure of the randomness or disorder within a substance in its standard state. It reflects the various ways that the particles within a substance can be arranged while still preserving its macroscopic properties. Higher entropy values suggest greater disorder and higher energy dispersal in a substance's molecular structure. When comparing isomers of alkenes, differences in \(S_m{ }^\circ\) can arise due to variations in molecular symmetry, the presence of substituents, and the overall three-dimensional arrangement. Ranking isomers by decreasing entropy helps determine the relative freedom of molecular motion and can be indicative of physical properties like boiling points and melting points, which are related to the energy required to overcome these entropic contributions.

Stability of Chemical Compounds

The stability of chemical compounds is often gauged by their tendency to resist change or decomposition under standard conditions. In thermodynamics, stability can be linked to Gibbs free energy. Compounds with lower \(\Delta G_{\text{f}}^\circ\) values are generally more stable, as they require an input of energy to be converted to other forms. In the exercise's context, comparing the \(\Delta G_{\text{f}}^\circ\) of the three alkene isomers allows us to infer their relative stabilities. The most stable molecule under standard conditions will have the lowest free energy of formation. This inherent stability has implications in practical applications, influencing aspects such as reactivity, rate of reaction, and product distribution during chemical processes.

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Most popular questions from this chapter

Suppose that 100. J of energy is taken from a hot source at \(300 .{ }^{\circ} \mathrm{C}\), passes through a turbine that converts some of the energy into work, and then releases the rest of the energy as heat into a cold sink at \(20 .{ }^{\circ} \mathrm{C}\). What is the maximum amount of work that can be produced by this engine if overall it is to operate spontaneously? What is the efficiency of the engine, with work done divided by heat supplied expressed as a percentage? How could the efficiency be increased?

Suppose that you were able to design an engine without a cold sink, so that the energy from a hot object could be transferred to the surroundings entirely as work, with no heat exchanged. (a) What would be the entropy change of the surroundings? (b) Could such an engine operate spontaneously? Explain your answer.

Which would you expect to have a higher molar entropy at \(T=0\), single crystals of \(\mathrm{BF}_{3}\) or of \(\mathrm{COF}_{2}\) ? Why?

Assuming that the heat capacity of an ideal gas is independent of temperature, calculate the entropy change associated with lowering the temperature of \(2.92 \mathrm{~mol}\) of ideal gas atoms from \(107.35^{\circ} \mathrm{C}\) to \(-52.39^{\circ} \mathrm{C}\) at (a) constant pressure and (b) constant volume.

The molar entropy of electron spins in a magnetic field \(B\) is $$ S=R\left\\{\frac{\Delta E / k T}{\mathrm{e}^{\Delta E / k T}-1}-\ln \left(1-\mathrm{e}^{-\Delta E / k T}\right)\right\\} $$ where \(\Delta E=2 \mu_{\mathrm{B}} B\) is the separation in energy of the two spin states in a magnetic field, \(\mu_{B}\) is the Bohr magneton, \(\mu_{B}=9.274 \times 10^{-24}\) \(\mathrm{J} \mathrm{T}^{-1}\). Plot this function against temperature for the following values of B: \(0.1 \mathrm{~T}, 1 \mathrm{~T}, 10 \mathrm{~T}\), and \(100 \mathrm{~T}\). (See Box 8.1. Notice that the unit of magnetic induction, tesla, \(T\), where \(1 T=1 \mathrm{~kg} \mathrm{~s}^{-2} \mathrm{~A}^{-1}\), cancels.)

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