(a) Which substance would you expect to have the highest molar entropy in the liquid phase, benzene, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\), or 1-propanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) ? (b) Would your answer be different if these substances were in the gas phase?

Short Answer

Expert verified
In the liquid phase, benzene is expected to have the highest molar entropy because it lacks hydrogen bonds. In the gas phase, 1-propanol would likely have the highest molar entropy due to its greater molecular complexity.

Step by step solution

01

- Understanding Molar Entropy

Molar entropy is a measure of the randomness or disorder within a substance. In general, larger molecules with more complex structures and more degrees of freedom (ways in which the atoms can move/vibrate) will have higher molar entropies because they have more ways to disperse energy.
02

- Comparing Molecules in Liquid Phase

In the liquid phase, intermolecular forces significantly affect molar entropy. Benzene (C6H6) is a compact, nonpolar molecule with relatively weak London dispersion forces. Methanol (CH3OH) has stronger hydrogen bonds due to the -OH group, which decreases its entropy compared to nonpolar molecules. 1-Propanol (CH3CH2CH2OH) has an even larger structure than methanol, with stronger London dispersion forces, but its ability to form hydrogen bonds also reduces entropy. Among the three, benzene, which lacks hydrogen bonding, is expected to have the highest molar entropy in its liquid form.
03

- Considering Molecular Structures and Intermolecular Forces

Among these three, the substance with the least amount of hydrogen bonding and higher molecular complexity will have the higher molar entropy. In the liquid phase, benzene would likely have the highest molar entropy because it can't form hydrogen bonds and has more vibrational modes than methanol and 1-propanol.
04

- Comparing Molecules in Gas Phase

In the gas phase, molecules have more freedom of movement and intermolecular forces are less significant. Therefore, molar entropy in the gas phase is more dependent on the molecular complexity and number of atoms. 1-Propanol (C3H8O) has more atoms and therefore more possible microstates than benzene (C6H6) or methanol (CH4O). As a result, one would expect 1-propanol to have the highest molar entropy in the gas phase due to its increased complexity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intermolecular Forces
Intermolecular forces are the forces that mediate interaction between molecules, including attractions and repulsions. These forces significantly influence the physical properties of a compound, such as boiling point, melting point, and crucial for our discussion, molar entropy. There are several types of intermolecular forces, but the most relevant to consider in the context of molar entropy are London dispersion forces, dipole-dipole interactions, and hydrogen bonding.

London dispersion forces are weak and arise due to the momentary fluctuations in electron density within otherwise nonpolar molecules. Molecules with larger surface areas and higher molar masses typically exhibit stronger London dispersion forces. Dipole-dipole interactions occur between molecules that have a permanent dipole moment, which means that there is an uneven distribution of electron density within the molecule. Lastly, hydrogen bonding is a strong type of dipole-dipole interaction that occurs when hydrogen is bound to a highly electronegative atom like oxygen, nitrogen, or fluorine.

The strength of these intermolecular forces is inversely related to molar entropy. Stronger intermolecular forces, as seen in hydrogen bonding, tend to reduce molar entropy because the molecules are more ordered and have less freedom of movement. In contrast, weaker forces, like London dispersion forces, result in higher molar entropy due to increased disorder and a greater number of accessible microstates for the molecules.
Liquid Phase Entropy
In the liquid phase, the entropy of a substance is heavily influenced by intermolecular forces. Stronger intermolecular forces in liquids lead to more structured and ordered systems, which decreases the entropy. The ability of molecules to move relative to one another is restrained and energy distribution becomes more restricted compared to the gas phase.

For substances like benzene, methanol, and 1-propanol, this principle translates into varying entropy values based on their molecular interactions. Benzene, being nonpolar, has weaker London dispersion forces and therefore the highest entropy among the three because its molecules are comparatively less ordered. Methanol and 1-propanol can engage in hydrogen bonding due to their -OH groups, causing them to be more ordered and consequently possess lower entropy. As such, in a liquid state, any substance that can form hydrogen bonds is likely to have reduced entropy relative to a substance that cannot, given similar molecular sizes and complexities.

Impact of Molecular Size

Molecular size also plays a role in liquid phase entropy. Larger molecules have more ways in which their atoms can move or vibrate, which can increase entropy. However, if increased size also leads to stronger intermolecular forces, the net impact on entropy will depend on which factor is more dominant.
Gas Phase Entropy
When considering the gas phase, the entropy difference among substances becomes more pronounced due to the increased freedom of movement of the molecules. In this phase, intermolecular forces are less of a concern because the distances between gas particles are much greater, and the attractions between them are significantly weaker than in liquids. Consequently, the intrinsic properties of the molecules themselves, such as molecular complexity and the number of atoms, become the primary factors influencing molar entropy.

A key point is that gas phase entropy increases with molecular complexity. This is because complex molecules have a greater number of vibrational modes and rotational freedoms, allowing for more microstates where energy can be distributed (i.e., more ways to achieve a particular energy level). Therefore, a molecule like 1-propanol, with its larger size and more complex structure compared to benzene and methanol, typically exhibits the highest molar entropy in the gas phase. Its increased number of atoms allows for more vibrational modes and possible microstates, which is directly related to higher entropy.

Relevance of Molecular Complexity

Understanding the concept of molecular complexity is valuable not only when comparing molar entropy between substances in a similar phase but also when trying to determine the entropy of a substance as it changes state. The transition from liquid to gas invariably results in a significant increase in entropy due to the liberation from intermolecular forces and the increase in accessible microstates for the substance.

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Most popular questions from this chapter

The standard entropy of vaporization of benzene is approximately \(85 \mathrm{~J} \cdot \mathrm{K}^{-1} \cdot \mathrm{mol}^{-1}\) at its boiling point. (a) Estimate the standard enthalpy of vaporization of benzene at its normal boiling point of \(80 .^{\circ} \mathrm{C}\). (b) What is the standard entropy change of the surroundings when \(10 . \mathrm{g}\) of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), vaporizes at its normal boiling point?

Propose the argument that, for any liquid at atmospheric pressure (that is, a liquid that boils above room temperature when the external pressure is \(1 \mathrm{~atm}\) ), the numerical value of \(\Delta H_{\text {vap }}\) in joules per mole is greater than the numerical value of \(\Delta S_{\text {vap }}\) in joules per kelvin per mole. (Explain and justify each step and any assumptions.)

Calculate the change in entropy when the pressure of \(70.9 \mathrm{~g}\) of methane gas is increased isothermally from \(7.00 \mathrm{kPa}\) to \(350.0 \mathrm{kPa}\). Assume ideal behavior.

Suppose that you create two tiny systems consisting of four atoms each, and each atom can accept energy in quanta of the same magnitude. (a) How many distinguishable arrangements are there of two quanta of energy distributed among the four atoms in one of these systems? (b) You now bring the two tiny systems together. How many distinguishable arrangements are there if the two quanta of energy are distributed among the eight atoms? (c) Which state is more disordered, that in part (a) or that in part (b)?

Which substance in each of the following pairs has the higher molar entropy at \(298 \mathrm{~K}\) : (a) \(\mathrm{HBr}(\mathrm{g})\) or \(\mathrm{HF}(\mathrm{g})\); (b) \(\mathrm{NH}_{3}(\mathrm{~g})\) or \(\mathrm{Ne}(\mathrm{g})\); (c) \(\mathrm{I}_{2}(\mathrm{~s})\) or \(\mathrm{I}_{2}(\mathrm{l})\); (d) \(1.0 \mathrm{~mol} \mathrm{Ar}(\mathrm{g})\) at \(1.00 \mathrm{~atm}\) or \(1.0 \mathrm{~mol} \mathrm{} \operatorname{Ar}(\mathrm{g})\) at \(2.00 \mathrm{~atm}\) ?

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