Explain the effect that an increase in temperature has on each of the following properties: (a) viscosity; (b) surface tension; (c) vapor pressure; (d) evaporation rate.

Short Answer

Expert verified
An increase in temperature will typically decrease viscosity and surface tension, while increasing vapor pressure and the evaporation rate of a substance.

Step by step solution

01

Effect on Viscosity

Understand that viscosity is a measure of a fluid's resistance to flow. With an increase in temperature, the kinetic energy of the molecules increases, causing them to move faster and more freely, thus reducing intermolecular attraction. This results in a decrease in viscosity, making the fluid flow more easily.
02

Effect on Surface Tension

Know that surface tension is the energy or force at the surface of a liquid that holds its molecules together. As temperature rises, the increased molecular motion disrupts the cohesive forces at the surface, reducing surface tension.
03

Effect on Vapor Pressure

Recognize that vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. When temperature goes up, more molecules have enough energy to escape into the vapor phase which increases the vapor pressure.
04

Effect on Evaporation Rate

Note that the evaporation rate is the rate at which a material changes from a liquid to a gas. Higher temperatures provide more energy to overcome the forces holding the molecules in the liquid, leading to an increase in the evaporation rate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Viscosity and Temperature
Viscosity describes how thick or thin a fluid is and its resistance to flow. Imagine honey and water; honey has a higher viscosity than water because it flows more slowly. As the temperature rises, fluids tend to behave more like water than honey—their viscosity decreases. This happens because heat gives energy to the molecule, encouraging them to move more quickly and reducing the forces that keep them stuck together.

For example, when you warm up syrup, it pours more easily over your pancakes. This is because the heat has lowered the syrup's viscosity. In industrial processes, understanding this relationship is crucial for equipment design and energy consumption, as fluids with lower viscosity require less energy to pump or move through pipes.
Surface Tension and Temperature
Surface tension is like a skin on the surface of a liquid, where the molecules are attracted to each other and stick close together. Think about water droplets on a waxed car—they hold a round shape because of surface tension. As you increase the temperature, the bonds between these surface molecules get weaker. Why? Because the heat causes molecules to move faster and they don't cling to each other as tightly, reducing the surface tension.

This reduced surface tension has practical applications, like in detergents that lower water's surface tension to clean better at higher temperatures. Understanding this concept helps explain phenomena such as the flattening of a water droplet as it warms up.
Vapor Pressure and Temperature
Vapor pressure is not as easily visualized as some other concepts, but think of it as the 'escape tendency' of a substance's molecules. It's the force that molecules exert when they turn into vapor. At higher temperatures, molecules have more energy to escape the liquid, which in turn increases the vapor pressure.

A common illustration of this is when a pot of water is heated: as the temperature goes up, the water boils more vigorously due to the increased vapor pressure. In the context of weather, higher vapor pressure can indicate more humidity, which is why it feels muggier on hot days. Understanding vapor pressure can be essential in fields ranging from meteorology to cooking!
Evaporation Rate and Temperature
The rate of evaporation is all about how quickly a liquid turns into a gas, and it speeds up with an increase in temperature. This is because, at higher temperatures, more liquid molecules have the energy to break free into a gaseous state. This is why clothes dry faster on a warm day than on a cool one.

The higher the temperature, the greater the number of energetic molecules that can escape, which increases the evaporation rate. The concept of evaporation rate is important in everyday life, as well as in industries like meteorology, where it can affect local climate and weather forecasting, and in environmental sciences, especially when dealing with the water cycle and the drying of wetlands.

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Most popular questions from this chapter

Lithium sulfate dissolves exothermically in water. (a) Is the enthalpy of solution for \(\mathrm{Li}_{2} \mathrm{SO}_{4}\) positive or negative? (b) Write the chemical equation for the dissolving process. (c) Which is larger for lithium sulfate, the lattice enthalpy or the enthalpy of hydration?

Calculate (a) the molality of \(\mathrm{KOH}\) in a solution prepared from \(4.25 \mathrm{~g}\) of \(\mathrm{KOH}\) and \(55.0 \mathrm{~g}\) of water; (b) the mass (in grams) of ethylene glycol, \(\mathrm{HOC}{ }_{2} \mathrm{H}_{4} \mathrm{OH}\), that should be added to \(0.85 \mathrm{~kg}\) of water to prepare \(0.35 \mathrm{~m} \mathrm{HOC} 2 \mathrm{H}_{4} \mathrm{OH}(\mathrm{aq}) ;\) (c) the molality of an aqueous \(4.12 \%\) by mass \(\mathrm{HCl}\) solution.

The carbon dioxide gas dissolved in a sample of water in a partly filled, sealed container has reached equilibrium with irs partial pressure in the air above the solution. Explain what happens to the solubility of the \(\mathrm{CO}_{2}\) if (a) the partial pressure of the \(\mathrm{CO}_{2}\) gas is doubled by the addition of more \(\mathrm{CO}_{2}\); (b) the total pressure of the gas above the liquid is doubled by the addirion of nitrogen.

Consider an apparatus in which \(A\) and B are two \(1.00-\mathrm{L}\) flasks joined by a stopcock \(\mathrm{C}\). The volume of the stopcock is negligible. Initially, \(\mathrm{A}\) and \(\mathrm{B}\) are evacuated, the stopcock \(\mathrm{C}\) is dosed, and \(1.50 \mathrm{~g}\) of diethyl ether, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}\), is introduced into flask A. The vapor pressure of diethyl ether is 57 Torr at \(-45^{\circ} \mathrm{C}\), 185 Torr at \(0 .{ }^{\circ} \mathrm{C}, 534\) Torr at \(25^{\circ} \mathrm{C}\), and negligible below \(-86^{\circ} \mathrm{C}\). (a) If the stopcock is left closed and the flask is brought to equilibrium at \(-45^{\circ} \mathrm{C}\), what will be the pressure of diethyl ether in flask A? (b) If the temperature is raised to \(25^{\circ} \mathrm{C}\), what will be the pressure of diethyl ether in the flask? (c) If the temperature of the assembly is returned to \(-45^{\circ} \mathrm{C}\) and the stopcock \(\mathrm{C}\) is opened, what will be the pressure of diethyl ether in the apparatus? (d) If flask \(\mathrm{A}\) is maintained at \(-45^{\circ} \mathrm{C}\) and flask B is cooled with liquid nitrogen (boiling point, \(-196^{\circ} \mathrm{C}\) ) with the stopcock open, what changes will take place in the apparatus? Assume ideal behavior.

Calculate the osmotic pressure at \(20^{\circ} \mathrm{C}\) of each of the following solutions; assume complete dissociation of ionic compounds: (a) \(3.0 \times 10^{-3} \mathrm{M}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{aq}) ;\) (b) \(2.0 \times 10^{-3} \mathrm{M}\) \(\mathrm{CaCl}_{2}(\mathrm{aq}) ;\) (c) \(0.010 \mathrm{M} \mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq})\).

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