Complete and write the overall equation, the complete ionic equation, and the net ionic equation for the following acid-base reactions. If the substance is a weak acid or base, leave it in its molecular form in writing the equations. (a) \(\mathrm{HCl}\) (aq) \(+\mathrm{NaOH}\) (aq) \(\rightarrow\) (b) \(\mathrm{NH}_{3}\) (aq) \(+\mathrm{HNO}_{3}\) (aq) \(\rightarrow\) (c) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) (aq) \(+\mathrm{Hl}\) (aq) \(\rightarrow\)

Short Answer

Expert verified
For (a) Overall: \(\mathrm{HCl_{(aq)}} + \mathrm{NaOH_{(aq)}} \rightarrow \mathrm{H_2O_{(l)}} + \mathrm{NaCl_{(aq)}}\) Net Ionic: \(\mathrm{H^+_{(aq)}} + \mathrm{OH^-_{(aq)}} \rightarrow \mathrm{H_2O_{(l)}}\) For (b) Overall: \(\mathrm{NH_3_{(aq)}} + \mathrm{HNO_3_{(aq)}} \rightarrow \mathrm{NH_4NO_3_{(aq)}}\) Net Ionic: \(\mathrm{NH_3_{(aq)}} + \mathrm{H^+_{(aq)}} \rightarrow \mathrm{NH_4^+_{(aq)}}\) For (c) Overall: \(\mathrm{CH_3NH_2_{(aq)}} + \mathrm{HI_{(aq)}} \rightarrow \mathrm{CH_3NH_3I_{(aq)}}\) Net Ionic: \(\mathrm{CH_3NH_2_{(aq)}} + \mathrm{H^+_{(aq)}} \rightarrow \mathrm{CH_3NH_3^+_{(aq)}}\)

Step by step solution

01

- Write the Overall Reaction for (a)

The reaction between HCl, a strong acid, and NaOH, a strong base, produces water and a salt (in this case, sodium chloride). The overall balanced equation is: \[ \mathrm{HCl_{(aq)}} + \mathrm{NaOH_{(aq)}} \rightarrow \mathrm{H_2O_{(l)}} + \mathrm{NaCl_{(aq)}} \]
02

- Write the Complete Ionic Equation for (a)

Both HCl and NaOH are strong electrolytes and dissociate completely in water. Thus, the complete ionic equation is: \[ \mathrm{H^+_{(aq)}} + \mathrm{Cl^-_{(aq)}} + \mathrm{Na^+_{(aq)}} + \mathrm{OH^-_{(aq)}} \rightarrow \mathrm{H_2O_{(l)}} + \mathrm{Na^+_{(aq)}} + \mathrm{Cl^-_{(aq)}} \]
03

- Write the Net Ionic Equation for (a)

Spectator ions, which are ions that do not participate in the chemical reaction, are omitted to obtain the net ionic equation. For this reaction, sodium and chloride ions are spectator ions. The net ionic equation is therefore: \[ \mathrm{H^+_{(aq)}} + \mathrm{OH^-_{(aq)}} \rightarrow \mathrm{H_2O_{(l)}} \]
04

- Write the Overall Reaction for (b)

NH3 is a weak base and HNO3 is a strong acid. The reaction between them forms the ammonium ion and water. The molecular form of ammonia should be left intact, and the balanced equation is: \[ \mathrm{NH_3_{(aq)}} + \mathrm{HNO_3_{(aq)}} \rightarrow \mathrm{NH_4NO_3_{(aq)}} \]
05

- Write the Net Ionic Equation for (b)

Since NH3 is a weak base, it remains in its molecular form. The nitric acid (HNO3), a strong acid, dissociates completely. However, because ammonium nitrate also dissociates completely, this reduces the net ionic equation to: \[ \mathrm{NH_3_{(aq)}} + \mathrm{H^+_{(aq)}} \rightarrow \mathrm{NH_4^+_{(aq)}} \]
06

- Write the Overall Reaction for (c)

Like NH3, CH3NH2 is a weak base. It reacts with HI, a strong acid, to form methylammonium iodide. The overall equation is: \[ \mathrm{CH_3NH_2_{(aq)}} + \mathrm{HI_{(aq)}} \rightarrow \mathrm{CH_3NH_3I_{(aq)}} \]
07

- Write the Net Ionic Equation for (c)

CH3NH2 is in its molecular form as a weak base, and HI dissociates completely. Again, since the product also dissociates completely, the net ionic equation is simply: \[ \mathrm{CH_3NH_2_{(aq)}} + \mathrm{H^+_{(aq)}} \rightarrow \mathrm{CH_3NH_3^+_{(aq)}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Acid-base reactions are fundamental chemical interactions where an acid and a base react to form water and a salt.

An acidic substance is one that is capable of donating a proton (\text{H}^+), according to the Bronsted-Lowry definition. An example is hydrochloric acid (\text{HCl}). Bases, on the other hand, are substances that can accept protons, such as sodium hydroxide (\text{NaOH}).

When these substances are in aqueous solution, they react according to the equation: \[ \text{Acid} + \text{Base} \rightarrow \text{Water} + \text{Salt} \]
For example, the reaction of hydrochloric acid with sodium hydroxide can be written as:\[ \text{HCl} + \text{NaOH} \rightarrow \text{H}_2\text{O} + \text{NaCl} \]
It's critical to remember that the strength of an acid or base varies. Strong acids and bases dissociate completely in solution, whereas weak acids and bases do not. When writing reaction equations, strong acids and bases are written as ions, while weak ones are left in their molecular form.
Complete Ionic Equation
Diving into the realm of the complete ionic equation, it's important to differentiate it from a simple balanced chemical equation.

A complete ionic equation shows all of the ions present in the solution before and after the chemical reaction. To write a complete ionic equation, one must consider the dissociation of soluble ionic compounds into their respective ions.

For the reaction between \text{HCl} and \text{NaOH}, the complete ionic equation would look like this:\[ \text{H}^+_{(aq)} + \text{Cl}^-_{(aq)} + \text{Na}^+_{(aq)} + \text{OH}^-_{(aq)} \rightarrow \text{H}_2\text{O}_{(l)} + \text{Na}^+_{(aq)} + \text{Cl}^-_{(aq)} \]
Each soluble strong electrolyte is written separately as ions. However, insoluble salts, weak acids, or bases as well as liquids, solids, and gases are shown in their complete form. Understanding this distinction is crucial for accuracy in representing chemical reactions.
Spectator Ions
Now, let's turn the spotlight to spectator ions, an interesting component in the chemical drama of reactions.

Spectator ions are like the bystanders of a reaction—present but not directly involved in the chemical change. These are ions that remain unchanged on both the reactant and the product side of a complete ionic equation.

In the context of our example with \text{HCl} and \text{NaOH}, the sodium (\text{Na}^+) and chloride (\text{Cl}^-) ions do not participate in the reaction that forms water. They start and finish in the same form, merely observing the reaction take place. Thus, when we write the net ionic equation, we leave these spectator ions out and focus on the truly reactive species:\[ \text{H}^+_{(aq)} + \text{OH}^-_{(aq)} \rightarrow \text{H}_2\text{O}_{(l)} \]
Identifying and omitting spectator ions simplifies the equation and allows us to see the actual chemical change occurring, known as the net ionic reaction. This is an essential step for understanding reactions at the ionic level.

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Most popular questions from this chapter

Identify the acid and the base in the following reactions: (a) \(\mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq})+\mathrm{NH}_{3}(\mathrm{aq}) \rightarrow\) \(\mathrm{NH}_{4}{ }^{+}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2}{ }^{-}(\mathrm{aq})\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq}) \rightarrow\) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) (c) \(\mathrm{O}^{2-}\) (aq) \(+\mathrm{H}_{2} \mathrm{O}\) (1) \(\rightarrow 2 \mathrm{OH}^{-}\)(aq)

Use the periodic table to determine which oxides form acidic solutions in water and which form basic solutions: (a) \(\mathrm{CaO}\); (b) \(\mathrm{SO}_{3}\); (c) \(\mathrm{N}_{2} \mathrm{O}_{3}\); (d) \(\mathrm{Tl}_{2} \mathrm{O}\).

Identify the acid and the base in the following reactions: (a) \(\mathrm{CH}_{3} \mathrm{NH}_{2}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq}) \rightarrow\) \(\mathrm{CH}_{3} \mathrm{NH}_{3}{ }^{*}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) (b) \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{NH}_{2}\) (aq) \(+\mathrm{HCl}\) (aq) \(\rightarrow\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3}{ }^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) (c) \(\mathrm{CaO}\) (s) \(+2 \mathrm{HI}(\mathrm{aq}) \rightarrow \mathrm{CaI}_{2}\) (aq) \(+\mathrm{H}_{2} \mathrm{O}\) (l)

Use the periodic rable to determine which oxides form acidic solutions in water and which form basic solutions: (a) \(\mathrm{P}_{4} \mathrm{O}_{105}\) (b) \(\mathrm{Na}_{2} \mathrm{O}\); (c) \(\mathrm{CO}_{2}\); (d) \(\mathrm{MgO}\).

Select an acid and a base for a neutralization reaction that results in the formation of (a) potassium bromide; (b) zinc nitrite; (c) calcium cyanide, \(\mathrm{Ca}(\mathrm{CN})_{2}\); (d) potassium phosphate. Write the overall and net ionic equations for each reaction.

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