Identify the acid and the base in the following reactions: (a) \(\mathrm{CH}_{3} \mathrm{COOH}(\mathrm{aq})+\mathrm{NH}_{3}(\mathrm{aq}) \rightarrow\) \(\mathrm{NH}_{4}{ }^{+}(\mathrm{aq})+\mathrm{CH}_{3} \mathrm{CO}_{2}{ }^{-}(\mathrm{aq})\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq}) \rightarrow\) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{NH}^{+}(\mathrm{aq})+\mathrm{Cl}^{-}(\mathrm{aq})\) (c) \(\mathrm{O}^{2-}\) (aq) \(+\mathrm{H}_{2} \mathrm{O}\) (1) \(\rightarrow 2 \mathrm{OH}^{-}\)(aq)

Short Answer

Expert verified
For reaction (a), the acid is \(\mathrm{CH}_{3}\mathrm{COOH}\) and the base is \(\mathrm{NH}_{3}\). In reaction (b), the acid is \(\mathrm{HCl}\) and the base is \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{N}\). For reaction (c), the acid is \(\mathrm{H}_{2}\mathrm{O}\) and the base is \(\mathrm{O}^{2-}\).

Step by step solution

01

Identify Acid and Base in Reaction (a)

In reaction (a), according to the Brønsted-Lowry theory, an acid is defined as a proton (H+) donor and a base as a proton acceptor. Here, \(\mathrm{CH}_{3}\mathrm{COOH}\) donates a proton to \(\mathrm{NH}_{3}\) forming \(\mathrm{NH}_{4}^+\) and \(\mathrm{CH}_{3}\mathrm{COO}^-\). Hence, \(\mathrm{CH}_{3}\mathrm{COOH}\) is the acid and \(\mathrm{NH}_{3}\) is the base.
02

Identify Acid and Base in Reaction (b)

In reaction (b), the \(\mathrm{HCl}\) is the acid as it provides a proton to \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{N}\), which accepts the proton to form \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{NH}^{+}\) and releases a chloride ion (\(\mathrm{Cl}^-\)). Thus, \(\mathrm{HCl}\) is the acid and \(\left(\mathrm{CH}_{3}\right)_{3}\mathrm{N}\) is the base.
03

Identify Acid and Base in Reaction (c)

In reaction (c), the hydroxide ion (\(\mathrm{O}^{2-}\)) acts as a base because it accepts a proton from \(\mathrm{H}_{2}\mathrm{O}\), which acts as the acid, resulting in the formation of two \(\mathrm{OH}^-\) ions. Therefore, \(\mathrm{H}_{2}\mathrm{O}\) is the acid and \(\mathrm{O}^{2-}\) is the base in this reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reactions
Understanding acid-base reactions is crucial for students diving into the world of chemistry. These reactions are ubiquitous, occurring in anything from lemon juice to your own bloodstream. The Brønsted-Lowry acid-base theory defines an acid as a substance that can donate a proton (H+), while a base is seen as a substance capable of accepting a proton.

In an acid-base reaction, there is a transfer of one or more protons from the acid to the base. This transfer results in the creation of new substances, typically forming what is known as a conjugate base of the acid and a conjugate acid of the base.

For example, when vinegar (acetic acid) is mixed with baking soda (a base), they react, neutralizing each other and creating carbonic acid which then decomposes into water and carbon dioxide gas. This reaction is visually exciting because it produces fizzy bubbles, a hallmark of an acid-base reaction at work.
Proton (H+) Donors and Acceptors
In the realm of acids and bases, it's all about the movement of protons. A single hydrogen nucleus—devoid of its electron—becomes a proton, H+. A Brønsted-Lowry acid is generous with these protons; it doesn't hold onto them tightly, making it willing to pass them on to others.

A base, on the other hand, is ready with open arms to welcome these protons. Each proton transfer from an acid to a base creates a conjugate pair: the original acid forms its conjugate base, and the original base forms its conjugate acid. This transformation is central to understanding chemical reactions.

To illustrate, the acetic acid in vinegar (CH3COOH), acting as a proton donor, gives up a hydrogen to baking soda (sodium bicarbonate), which accepts it. In the process, each transforms: acetic acid becomes the acetate ion (a lesser acid), and bicarbonate becomes carbonic acid (a new, weaker acid) before it breaks down into water and carbon dioxide.
Chemical Reaction Identification
Identification of chemical reactions involves analyzing reactants and products to determine the process that has occurred. It's like being a detective in a laboratory, looking for clues in the form of molecules and ions. In the case of acid-base reactions, the clues are in the protons being exchanged.

When inspecting a reaction, first look for a substance that could give up a proton; this is your potential acid. Next, find the substance that seems primed to grab that proton; this is your potential base. The balance of loss and gain of protons will help to uncover what type of reaction took place.

In academic exercises, once the acid and base are identified, you can often predict the products as well. This makes it easier to balance chemical equations and understand reaction mechanisms. For instance, in the exercise example (a), acetic acid (CH3COOH) gives up a proton, and ammonia (NH3) accepts it, forming ammonium (NH4+) and acetate (CH3COO-). Through diligent practice, students gradually learn to identify various types of chemical reactions, a fundamental skill for aspiring chemists.

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