2.14 For each of the following ground-state ions, predict the type of orbital \((1 s, 2 p, 3 d, 4 f\), and so on) from which an electron will need to be removed to form the ions of one greater positive charge: (a) \(\mathrm{Ti}^{2+}\); (b) \(\ln ^{+} ;\)(c) \(\mathrm{Te}^{2-} ;\) (d) \(\mathrm{Ag}^{+} .\)

Short Answer

Expert verified
The type of orbital from which an electron will need to be removed to form the specified ions of one greater positive charge: (a) Ti2+ from 3d, (b) In+ from 5s, (c) Te2- from 5p, (d) Ag+ from 4d.

Step by step solution

01

Identify the Electron Configuration of Each Neutral Atom

Before predicting the type of orbital from which an electron will be removed, we need to know the electron configuration of the neutral atom. We use the periodic table to determine the electron configurations of titanium (Ti), indium (In), tellurium (Te), and silver (Ag).
02

Adjust for Ion Charge

For positive ions (cations), electrons are removed from the neutral atom. For negative ions (anions), electrons are added to the neutral atom. Starting with the neutral atom configuration, remove or add electrons according to the ion's charge.
03

Determine the Orbital for Electron Removal

To increase the positive charge by one, remove an electron from the outermost occupied orbital. This is typically the orbital with the highest n value, or if n is the same, the highest l value (s Springer Nature Group. All rights reserved.
04

Predict Orbital for Ti2+

For Ti2+, the neutral titanium atom has the electron configuration [Ar] 3d2 4s2. Removing two electrons for the Ti2+ ion would leave us with [Ar] 3d2. To form Ti3+, remove one more electron from the 3d orbital.
05

Predict Orbital for In+

For In+, the neutral indium atom has the electron configuration [Kr] 4d10 5s2 5p1. Removing one electron for the In+ ion leaves us with [Kr] 4d10 5s2. To form In2+, remove one more electron from the 5s orbital.
06

Predict Orbital for Te2-

For Te2-, the neutral tellurium atom has the electron configuration [Kr] 4d10 5s2 5p4. Adding two electrons for the Te2- ion gives us [Kr] 4d10 5s2 5p6. To form Te1-, remove one electron from the 5p orbital.
07

Predict Orbital for Ag+

For Ag+, the neutral silver atom has the electron configuration [Kr] 4d10 5s1. Removing one electron for the Ag+ ion would leave us with [Kr] 4d10. To form Ag2+, remove one more electron from the 4d orbital.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Configuration
Understanding electron configuration is essential for predicting how electrons are arranged around an atom and determining which orbital an electron will be removed from or added to. The configuration follows a standard sequence based on the increasing energy levels and sublevels, typically notated in a format like '1s2 2s2 2p6'.

Electrons fill the orbitals from lower to higher energy states. The order is defined by the Aufbau principle, which suggests that electrons occupy the lowest energy orbitals available. As a helpful mnemonic, many students use the 'diagonal rule' to remember the order of filling: 1s, 2s, 2p, 3s, 3p, 4s, 3d, and so on.

Knowing this order is crucial when dealing with chemical reactions or the formation of ions, as it allows you to predict which electrons will be involved based on their energy levels and the overall stability of the atom or ion after electron removal or addition.
Ion Charge Adjustment
When an atom gains or loses electrons, it becomes an ion. The charge of an ion is adjusted by the differential number of electrons compared to its neutral state. Cations, or positive ions, are formed when atoms lose electrons, resulting in a net positive charge. Anions, on the other hand, result from the gain of electrons and have a net negative charge.

For instance, to transition from a neutral atom to a cation with a greater positive charge, we remove the electron(s) from the outermost orbital as per Hund's rule, which indicates the filling order of electrons within the same subshell. The reverse is true for anions: we add electrons to the last energy level following the 'octet rule', which suggests that atoms are generally most stable when they have eight electrons in their valence shell.
Periodic Table
The periodic table is a fundamental tool in chemistry, providing a wealth of information at a glance about the elements—including electron configurations. Elements are arranged in order of increasing atomic number and are grouped based on similar properties. The table itself is divided into blocks (s, p, d, f), corresponding to the sublevel that is being filled with electrons for elements in that block.

Following periodic trends, such as electron affinities, ionization energies, and atomic radius, is helpful for predicting behavior during ion formation. For instance, elements in the same group (vertical columns) typically form ions with similar charges, which can be seen in their similar valence electron configurations. This systematic setup aids in quickly determining the base electron configuration of an element, which is the starting point for figuring out from which orbital an electron will be removed.
Quantum Numbers
Quantum numbers are vital in pinpointing the location and energy of electrons within an atom. These include the principal quantum number (\( n \)), the angular momentum quantum number (\( l \)), the magnetic quantum number (\( m_l \)), and the spin quantum number (\( m_s \)).

\( n \) determines the energy level or shell of an electron, and as this number increases, so does the energy of the electron. \( l \) indicates the subshell or shape of the orbital, with \( l = 0 \) for 's', \( l = 1 \) for 'p', \( l = 2 \) for 'd', and \( l = 3 \) for 'f'. The magnetic quantum number defines the orbital's orientation in space, and finally, the spin quantum number designates the direction of the electron's spin within the orbital. By understanding these quantum numbers, we explain why electrons are removed from the highest-energy orbital (\( n \) and \( l \) values) during ion formation, as these electrons are less firmly held by the nucleus and therefore easier to remove.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free