Write the Lewis structure of (a) \(\mathrm{SCl}_{2} ;\) (b) \(\mathrm{AsH}_{3} ;\) (c) \(\mathrm{GeCl}_{4} ;\) (d) \(\mathrm{SnCl}_{2}\).

Short Answer

Expert verified
Lewis structures: (a) SCl2: central S with two single bonds to two Cl, and three lone pairs on S. (b) AsH3: central As with three single bonds to three H, and one lone pair on As. (c) GeCl4: central Ge with four single bonds to four Cl. (d) SnCl2: central Sn with two single bonds to two Cl, and one lone pair on Sn.

Step by step solution

01

Count Valence Electrons for SCl2

Sulfur (S) has 6 valence electrons, and each Chlorine (Cl) has 7 valence electrons. As there are two Cl atoms, the total for SCl2 is: 6 + 2(7) = 20 valence electrons.
02

Draw Skeleton Structure for SCl2

Put S in the center and arrange the two Cl atoms around it, each connected to S with a single bond.
03

Complete the Octets for SCl2

Place the remaining valence electrons around the Cl atoms to complete their octet, then place any leftover electrons on S to satisfy the duet or octet rule.
04

Count Valence Electrons for AsH3

Arsenic (As) has 5 valence electrons and Hydrogen (H) has 1 valence electron. As there are three H atoms, total for AsH3 is: 5 + 3(1) = 8 valence electrons.
05

Draw Skeleton Structure for AsH3

Put As in the center and arrange the three H atoms around it, each connected to As with a single bond.
06

Complete the Octets or Duet (for H) for AsH3

Hydrogen atoms are already satisfied with 2 electrons forming a duet, and As does not need to complete an octet as it is in period 4 and can have an expanded octet.
07

Count Valence Electrons for GeCl4

Germanium (Ge) has 4 valence electrons, and each Cl has 7 valence electrons. As there are four Cl atoms, the total for GeCl4 is: 4 + 4(7) = 32 valence electrons.
08

Draw Skeleton Structure for GeCl4

Put Ge in the center and arrange the four Cl atoms around it, each connected to Ge with a single bond.
09

Complete the Octets for GeCl4

Place the remaining valence electrons around the Cl atoms to complete their octet.
10

Count Valence Electrons for SnCl2

Tin (Sn) has 4 valence electrons, and each Cl has 7 valence electrons. As there are two Cl atoms, the total for SnCl2 is: 4 + 2(7) = 18 valence electrons.
11

Draw Skeleton Structure for SnCl2

Put Sn in the center and arrange the two Cl atoms around it, each connected to Sn with a single bond.
12

Complete the Octets for SnCl2

Place the remaining valence electrons around the Cl atoms to complete their octet, and then any leftover electrons on Sn to complete the octet or to show any lone pairs or possible double bonds if necessary.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the outermost electrons of an atom and are critical in determining how an element will react chemically with others. For instance, the sulfur atom in SCl2 possesses six valence electrons, which are available for bonding with other atoms. Similarly, chlorine has seven valence electrons readily available for making bonds. To visualize Lewis structures, it is essential to know the number of valence electrons as they govern the types of bonds that atoms form. The collective valence electrons are the ‘glue’ that holds atoms together in molecules.

For a clear understanding, counting the valence electrons is often the first step, as seen in the provided solution for SCl2, which is done by adding the valence electrons of each atom involved. This count forms the foundation for how the electrons are distributed throughout the molecule, leading to a skeletal structure that then gets refined to satisfy the specific bonding needs of each atom.
Octet Rule
The octet rule is a chemical rule of thumb that reflects the observation that atoms of main-group elements tend to bond in such a way that each atom has eight electrons in its valence shell, giving it the same electron configuration as a noble gas. Atoms will share, gain, or lose electrons to fulfill this rule. In structures like AsH3, this rule predicts the arrangement of electrons around the arsenic atom, guiding us that arsenic can ‘expand the octet’ due to its ability to access d-orbitals. This is a point of exercise improvement - highlighting exceptions to the octet rule, like in the case of elements beyond period 3 of the periodic table.

The provided solution takes this rule into account when adding electrons to the surrounding atoms in the Lewis structures. For instance, when completing the octets for SCl2 or GeCl4, electrons are placed around each chlorine until they all have a complete octet, showcasing how the rule directs the electron distribution.
Molecular Geometry
The arrangement of atoms within a molecule defines its molecular geometry. This arrangement is depicted through the Lewis structures and influenced by the valence shell electron pair repulsion (VSEPR) theory which states that electron pairs around a central atom will organize themselves to minimize repulsion between them. For GeCl4, with four chlorine atoms, the molecular geometry can be predicted as a tetrahedral arrangement based on VSEPR theory, assuming that all electron pairs (bonding and lone pairs) are positioned as far apart as possible from one another.

The exercise solution could further elaborate on this by offering insights into how the number of bonding and non-bonding electron pairs affects the shape of the molecule, which ultimately has profound effects on the physical and chemical properties of the molecule. In providing an educational platform, discussing the role of molecular geometry in determining such properties can be crucial for students to understand the practical importance of Lewis structures and VSEPR theory.

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