Using only Lewis structures that obey the octet rule, determine the formal charge on each atom in (a) \(\mathrm{CH}_{3}^{+} ;\)(b) \(\mathrm{ClO}^{-} ;\)(c) \(\mathrm{CN}^{-}\)

Short Answer

Expert verified
Formal charges for (a) \(\mathrm{CH}_{3}^{+}\): Carbon = +1, Hydrogens = 0; (b) \(\mathrm{ClO}^{-}\): Chlorine = 0, Oxygen = -1; (c) \(\mathrm{CN}^{-}\): Carbon = 0, Nitrogen = -1.

Step by step solution

01

Drawing Lewis Structure for CH3+

Draw the Lewis structure of \(\mathrm{CH}_{3}^{+}\). Carbon (C) is the central atom and has three Hydrogen (H) atoms bonded to it. Since it is a cation with a positive charge, it has three electrons bonded to three H atoms and no lone pairs, having a total of three valence electrons instead of its usual four.
02

Calculating Formal Charge for Carbon in CH3+

Use the formula: \(\text{Formal Charge} = \text{Valence electrons} - \frac{1}{2} \times \text{Bonding electrons} - \text{Lone pair electrons}\). Carbon usually has four valence electrons, but in \(\mathrm{CH}_{3}^{+}\), it shares three (one with each hydrogen) and has none on its own. The formal charge on Carbon is \(4 - \frac{1}{2} \times 6 - 0 = +1\).
03

Calculating Formal Charge for Hydrogen in CH3+

Hydrogen always has one valence electron and is bonded to one electron when bonded to Carbon. The formal charge on each Hydrogen atom is \(1 - \frac{1}{2} \times 2 - 0 = 0\).
04

Drawing Lewis Structure for ClO-

Sketch the Lewis structure of \(\mathrm{ClO}^{-}\). Chlorine (Cl) is the central atom with 7 valence electrons, and Oxygen (O) has 6 valence electrons. They form a single bond, and there is one additional electron due to the negative charge.
05

Calculating Formal Charge for Chlorine in ClO-

From the Lewis structure, Chlorine has 6 nonbonding electrons and shares 2 bonding electrons. Using the formal charge formula: \(7 - \frac{1}{2} \times 2 - 6 = 0\), the formal charge on Chlorine is 0.
06

Calculating Formal Charge for Oxygen in ClO-

Oxygen has 4 nonbonding electrons and shares 2 bonding electrons with the Chlorine. Using the formal charge formula: \(6 - \frac{1}{2} \times 2 - 4 = -1\), the formal charge on Oxygen is -1.
07

Drawing Lewis Structure for CN-

Construct the Lewis structure for \(\mathrm{CN}^{-}\). Carbon and Nitrogen both can form three bonds and have 5 and 4 valence electrons, respectively. Together they form a triple bond with one extra pair of electrons on Nitrogen due to the negative charge.
08

Calculating Formal Charge for Carbon in CN-

Carbon in \(\mathrm{CN}^{-}\) has no nonbonding electrons and shares six bonding electrons. The formula gives us \(4 - \frac{1}{2} \times 6 - 0 = 0\); thus, the formal charge on Carbon is 0.
09

Calculating Formal Charge for Nitrogen in CN-

For Nitrogen, the lone pair counts as two nonbonding electrons and it has six bonding electrons. The calculation is \(5 - \frac{1}{2} \times 6 - 2 = -1\), giving a formal charge of -1 on Nitrogen.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
When it comes to understanding molecular geometry and reactivity, Lewis structures serve as a fundamental tool for students and chemists alike. These simple diagrams provide a visual representation of the valence electron arrangement in molecules.

To draw a Lewis structure, first, identify the total number of valence electrons available, considering any charges the molecule may have. The electrons are then distributed to give each atom, ideally, an octet — eight electrons to fulfill the 'octet rule'. Atoms form bonds by sharing pairs of electrons, and any remaining valence electrons are shown as 'lone pairs' on individual atoms.

For example, when constructing the Lewis structure for \(\mathrm{CH}_{3}^{+}\), we recognize that carbon is the central atom and is connected to three hydrogen atoms. Since the molecule carries a positive charge, carbon lacks one of its usual four electrons. This deficiency is visually represented in the Lewis structure through fewer electron pairs around the carbon atom.
Valence Electrons
Valence electrons play a critical role in chemical reactions, as they are the electrons located in the outermost electron shell of an atom and can be involved in forming chemical bonds. The number of valence electrons an atom has is determined by its position in the periodic table.

For instance, in group 1 elements, like hydrogen, there is a single valence electron. In group 14, elements like carbon have four valence electrons. These valence electrons are key to drawing Lewis structures, as they indicate how many bonds an atom can form to achieve a stable octet. It is important to count the valence electrons correctly to apply the formal charge formula effectively, as shown in the step-by-step solutions for the given exercises.
Bonding Electrons
Bonding electrons are those that are shared between atoms in a molecule, forming what we call chemical bonds. A single bond consists of one pair of shared electrons, illustrated by a single line in Lewis structures. Double and triple bonds, represented by two or three lines respectively, involve two or three pairs of shared electrons.

For example, in \(\mathrm{CN}^{-}\), carbon and nitrogen form a triple bond, sharing three pairs of electrons, which strongly influences the formal charge calculation. The bonding electrons are counted as belonging equally to both bonded atoms. So in the formal charge formula \(\text{Formal Charge} = \text{Valence electrons} - \frac{1}{2} \times \text{Bonding electrons} - \text{Lone pair electrons}\), bonding electrons are divided by two to fairly attribute them to both atoms involved in the bond.

Understanding these concepts is vital for grasping the formation and properties of chemical compounds, as well as for predicting the behavior of atoms during chemical reactions.

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