Chapter 2: Problem 59
Identify the Lewis acid and the Lewis base, and then write the product (a complex) for the following Lewis acid-base reactions: (a) \(\mathrm{PF}_{5}+\mathbf{F}^{-} \rightarrow\) ? (b) \(\mathrm{SO}_{2}+\mathrm{Cl}^{-} \rightarrow\) ?
Short Answer
Expert verified
The products of the Lewis acid-base reactions are: (a) \(\textrm{PF}_{6}^-\) and (b) \(\textrm{SO}_{2Cl}^{-}\).
Step by step solution
01
Identify the Lewis Acid in Reaction (a)
A Lewis acid is a species that accepts an electron pair. In the given reaction \((\mathrm{PF}_{5}+\mathbf{F}^{-} \rightarrow \) ?), \(\textrm{PF}_{5}\) is the molecule that accepts an electron pair because it can expand its valence shell to accommodate more than eight electrons. Thus, \(\textrm{PF}_{5}\) is the Lewis acid.
02
Identify the Lewis Base in Reaction (a)
A Lewis base is a species that donates an electron pair. In the reaction \((\mathrm{PF}_{5}+\mathbf{F}^{-} \rightarrow \) ?), the \(\textrm{F}^{-}\) ion is the donor of an electron pair. Therefore, \(\textrm{F}^{-}\) is the Lewis base.
03
Write the Product for Reaction (a)
The electron pair from the Lewis base \(\textrm{F}^{-}\) is donated to the Lewis acid \(\textrm{PF}_{5}\), forming a complex where an additional F atom is added to \(\textrm{PF}_{5}\). Thus, the product is \(\textrm{PF}_{6}^-\).
04
Identify the Lewis Acid in Reaction (b)
For the reaction \((\mathrm{SO}_{2}+\mathrm{Cl}^{-} \rightarrow \) ?), \(\textrm{SO}_{2}\) is the species that accepts an electron pair, which makes it the Lewis acid.
05
Identify the Lewis Base in Reaction (b)
In the reaction \((\mathrm{SO}_{2}+\mathrm{Cl}^{-} \rightarrow \) ?), the \(\textrm{Cl}^{-}\) is the species that donates an electron pair, therefore it acts as the Lewis base.
06
Write the Product for Reaction (b)
The electron pair from the Lewis base \(\textrm{Cl}^{-}\) is donated to the Lewis acid \(\textrm{SO}_{2}\), creating a complex. The product of the reaction is a chloride complex of \(\textrm{SO}_{2}\), often written as \(\textrm{SO}_{2Cl}^{-}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Lewis Acid Identification
When identifying Lewis acids in chemical reactions, we look for species that can accept an electron pair. These are typically molecules or ions that have incomplete octets, vacant d orbitals, or positive charges. For instance, in the reaction
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow ?\),
\(\mathrm{PF}_{5}\) is able to expand its valence shell beyond eight electrons, which makes it an ideal candidate to be a Lewis acid. Its structure has a phosphorus atom that can form more bonds, accepting an electron pair from a Lewis base to fill its expanded octet. Thus, understanding the electronic structure and the nature of atoms involved can assist in identifying Lewis acids in various reactions.
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow ?\),
\(\mathrm{PF}_{5}\) is able to expand its valence shell beyond eight electrons, which makes it an ideal candidate to be a Lewis acid. Its structure has a phosphorus atom that can form more bonds, accepting an electron pair from a Lewis base to fill its expanded octet. Thus, understanding the electronic structure and the nature of atoms involved can assist in identifying Lewis acids in various reactions.
Lewis Base Identification
Lewis bases are the opposite of acids in this type of reaction; they are species ready to donate an electron pair. A classic indicator of a Lewis base is a negative charge, suggesting an excess of electrons. This is evident in the reaction
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow ?\),
where the \(\mathbf{F}^{-}\) ion, having an extra electron, acts as the Lewis base. Not exclusively ions, molecules with lone pairs of electrons, such as ammonia (NH3), water (H2O), or alcohols (R-OH), are also typical Lewis bases. In identifying a Lewis base, look for atoms with lone pairs that are not involved in bonding, as these are often the donors in Lewis acid-base reactions.
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow ?\),
where the \(\mathbf{F}^{-}\) ion, having an extra electron, acts as the Lewis base. Not exclusively ions, molecules with lone pairs of electrons, such as ammonia (NH3), water (H2O), or alcohols (R-OH), are also typical Lewis bases. In identifying a Lewis base, look for atoms with lone pairs that are not involved in bonding, as these are often the donors in Lewis acid-base reactions.
Complex Ion Formation
Complex ion formation is a central feature of Lewis acid-base reactions. A complex ion is a species consisting of a central metal ion bonded to one or more ligands, which are molecules or ions that donate an electron pair to the metal, forming coordinate covalent bonds. From the reactions provided, for example,
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow \textrm{PF}_{6}^{-}\),
the result is a complex ion where \(\textrm{F}^{-}\) becomes a ligand to the \(\textrm{PF}_{5}\) Lewis acid. Such complex ions are often found in transition metal chemistry where the metals act as Lewis acids, forming intricate structures with various ligands.
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow \textrm{PF}_{6}^{-}\),
the result is a complex ion where \(\textrm{F}^{-}\) becomes a ligand to the \(\textrm{PF}_{5}\) Lewis acid. Such complex ions are often found in transition metal chemistry where the metals act as Lewis acids, forming intricate structures with various ligands.
Electron Pair Donation
At the heart of a Lewis acid-base reaction is electron pair donation. The Lewis base provides a pair of electrons, while the Lewis acid accepts this pair, leading to the formation of a coordinate covalent bond. In the given examples,
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow \textrm{PF}_{6}^{-}\) and \(\mathrm{SO}_{2} + \mathrm{Cl}^{-} \rightarrow \textrm{SO}_{2Cl}^{-}\),
we see this donation clearly. The fluoride ion (\textbf{F}-) donates an electron pair to \(\textrm{PF}_{5}\), and the chloride ion (\textbf{Cl}-) to \(\textrm{SO}_{2}\). The ability to donate an electron pair is a key quality of a Lewis base, which enables the formation of new chemical species, enriched by the bonds formed during these interactions.
\(\mathrm{PF}_{5} + \mathbf{F}^{-} \rightarrow \textrm{PF}_{6}^{-}\) and \(\mathrm{SO}_{2} + \mathrm{Cl}^{-} \rightarrow \textrm{SO}_{2Cl}^{-}\),
we see this donation clearly. The fluoride ion (\textbf{F}-) donates an electron pair to \(\textrm{PF}_{5}\), and the chloride ion (\textbf{Cl}-) to \(\textrm{SO}_{2}\). The ability to donate an electron pair is a key quality of a Lewis base, which enables the formation of new chemical species, enriched by the bonds formed during these interactions.