Using your knowledge of Lewis structures, predict which of the following molecules of a set will have the longest indicated bond length: (a) \(\mathrm{N}-\mathrm{O}\) bond in \(\mathrm{NO}, \mathrm{NO}_{2}\), or \(\mathrm{NO}_{3}{ }^{-}\); (b) \(\mathrm{C}-\mathrm{C}\) bond in \(\mathrm{C}_{2} \mathrm{H}_{2}, \mathrm{C}_{2} \mathrm{H}_{4}\), or \(\mathrm{C}_{2} \mathrm{H}_{6}\) (c) \(\mathrm{C}-\mathrm{O}\) bond in \(\mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{2} \mathrm{O}\), or \(\mathrm{CH}_{3} \mathrm{OCH}_{3}\).

Short Answer

Expert verified
The longest bond lengths for each set are: (a) N-O bond in NO3-, (b) C-C bond in C2H6, (c) C-O bond in CH3OCH3.

Step by step solution

01

Assessing the N-O Bond Lengths

To compare bond lengths for the N-O bonds in NO, NO2, and NO3-, we first assess the bond order for each. The bond order is inversely related to bond length, with higher bond orders corresponding to shorter bonds. For NO, there's a double bond with a bond order of 2. NO2 has one N=O double bond and one N-O single bond, so the average bond order is between 1 and 2. In NO3-, each oxygen is equivalent and the bond order is 1.33 (since the formal charge on N is +1 and there are 3 equivalent resonance structures, each with one N=O double bond and two N-O single bonds). Thus, NO3- has the longest N-O bond due to the lowest average bond order.
02

Comparing C-C Bond Lengths

C-C bond lengths are determined by the number of bonds between the two carbon atoms. In C2H2 (acetylene), there's a triple bond between the carbons (bond order 3). In C2H4 (ethylene), there's a double bond (bond order 2). In C2H6 (ethane), there's a single bond (bond order 1). Hence, the longest C-C bond is found in C2H6, which has the single bond with the lowest bond order.
03

Determining the C-O Bond Lengths

For the C-O bond lengths, we need to consider the hybridization of carbon and the oxygen it's bonded to. In CH3OH, C is sp3 hybridized and forms a single bond with O. In CH2O, C is sp2 hybridized and forms a double bond with O. CH3OCH3 has two methyl groups (CH3) attached to an oxygen, meaning the C-O bond is in an ether linkage with sp3 hybridization. Therefore, since double bonds (as in CH2O) are shorter than single bonds, the longest C-O bond will be in the compounds with single bonds—CH3OH or CH3OCH3. Since CH3OH has hydrogen bonding which might slightly alter the bond lengths, the longest C-O bond would then be found in CH3OCH3 due to less electronegative draw from the adjacent atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis Structures
Lewis structures are a way to visually represent the valence electrons of atoms within a molecule, helping us to understand how atoms bond and form compounds. These diagrams show the distribution of electrons around atoms and the location of bonds between atoms.

When drawing Lewis structures, we represent valence electrons as dots, and chemical bonds as lines connecting atom pairs. Each atom aims to complete its octet, meaning it seeks to have eight electrons in its valence shell, which is typically achieved through sharing electrons. Knowing this, we can predict and explain the stability of molecules, the types of bonds present (single, double, or triple), and their implications on properties like bond length and molecular geometry. For example, in a nitrogen oxide species, the Lewis structure can show differing N-O bond situations, which directly influence the bond lengths within the molecule.
Bond Order
Bond order is a concept that explains the strength and length of a bond between two atoms. It's defined as the number of bonding pairs of electrons between two atoms. The higher the bond order, the more electrons hold the atoms together, resulting in stronger and shorter bonds. Conversely, a lower bond order indicates fewer shared electrons, leading to longer and weaker bonds.

In the context of the exercise, we can use bond orders to compare the lengths of similar types of bonds across different molecules. For instance, the N-O bond in different nitrogen oxide species varies in bond order, which in turn affects the bond's length. In simple terms, the bond order serves as an excellent predictor for bond length - a higher bond order means a shorter bond.
Molecular Geometry
Molecular geometry refers to the three-dimensional shape of a molecule, determined by the spatial arrangement of atoms. This geometry is crucial as it influences the molecule's physical and chemical properties, including reactivity, polarity, and intermolecular interactions.

The geometry is often predicted using the Valence Shell Electron Pair Repulsion (VSEPR) theory, which states that electron pairs around a central atom will arrange themselves to minimize repulsion. As in the exercise examples, molecular geometry can impact the bond lengths; for instance, linear arrangements as found in diatomic nitrogen (N≡N) typically result in shorter bond lengths compared to more angular geometries.
sp3 Hybridization
Hybridization is the concept of mixing atomic orbitals to generate new hybrid orbitals that can form bonded structures conforming to the molecular geometry. sp3 hybridization occurs when one s orbital mixes with three p orbitals, which results in four hybrid orbitals arranged in a tetrahedral shape.

This kind of hybridization typically leads to single bonds, as in methane (CH4) or ethane (C2H6). Each sp3 hybridized orbital can form a sigma bond, and these single bonds are generally longer than double or triple bonds present in molecules where carbon is sp2 or sp hybridized.
Resonance Structures
Resonance structures are a way to represent molecules where the electron distribution can be shown in multiple valid Lewis structures. These structures depict the same arrangement of atoms but differ in the location of electrons.

Resonance is important as it accounts for the actual electron delocalization in molecules, which cannot be accurately shown with a single Lewis structure. For instance, resonance in the nitrate ion (NO3-) causes a distribution of electron density over the three N-O bonds, making them equivalent and resulting in an intermediate bond length and order. This concept emphasizes that the actual molecule is a hybrid of multiple resonance forms, which helps explain why certain bonds have varying lengths compared to what might be expected from their individual Lewis structures.

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