Chapter 2: Problem 79
On the basis of the expectod charges of the monatomic ions, give the chemical formula of each of the following compounds: (a) vanadium(V) oxide; (b) lead(IV) oxide; (c) thallium(III) oxide.
Short Answer
Expert verified
The chemical formulas are: (a) V2O5, (b) PbO2, (c) Tl2O3.
Step by step solution
01
Determine the Charge on Vanadium in Vanadium(V) Oxide
The Roman numeral (V) in vanadium(V) oxide indicates the oxidation state of vanadium, which is +5. Since oxygen typically has a charge of -2, we can use this information to balance the charges.
02
Write the Formula for Vanadium(V) Oxide
To neutralize the positive charge of vanadium(V), multiple oxide ions are needed. The formula unit must have a net charge of zero, so we need 5/2 = 2.5, which is not possible with whole numbers. To ensure whole numbers, multiply the charges by the smallest common multiple (2), leading to V2O5.
03
Determine the Charge on Lead in Lead(IV) Oxide
For lead(IV) oxide, the Roman numeral (IV) denotes the oxidation state of lead, which is +4. Oxygen has a -2 charge, so we balance it in the same manner.
04
Write the Formula for Lead(IV) Oxide
The required number of oxide ions to balance the charge of lead(IV) is 4/2 = 2, leading to the formula PbO2.
05
Determine the Charge on Thallium in Thallium(III) Oxide
The Roman numeral (III) in thallium(III) oxide indicates the charge of thallium, which is +3. Oxygen's charge is -2.
06
Write the Formula for Thallium(III) Oxide
The balancing of charges will be done as before. Multiplying the +3 charge of thallium and the -2 charge of oxygen by the smallest common multiple, which is 2, we get Tl2O3.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation States
Understanding oxidation states is vital to mastering the art of writing chemical formulas. An oxidation state, often referred to as oxidation number, is a figure that represents the total number of electrons an atom either gains or loses in order to form a chemical bond with another atom.
Take, for example, vanadium(V) oxide. The Roman numeral (V) signifies that vanadium has an oxidation state of +5. This means vanadium can be assumed to have 'lost' five electrons. On the other hand, oxygen typically has an oxidation state of -2, indicating that it 'gains' two electrons when forming compounds. Balancing these oxidation states is like solving a numeric puzzle: the total positive charge must counterbalance the total negative charge for the compound to be stable. Here, the balancing act leads to the formation of V2O5, which ensures the charges are neutralized.
Take, for example, vanadium(V) oxide. The Roman numeral (V) signifies that vanadium has an oxidation state of +5. This means vanadium can be assumed to have 'lost' five electrons. On the other hand, oxygen typically has an oxidation state of -2, indicating that it 'gains' two electrons when forming compounds. Balancing these oxidation states is like solving a numeric puzzle: the total positive charge must counterbalance the total negative charge for the compound to be stable. Here, the balancing act leads to the formation of V2O5, which ensures the charges are neutralized.
Step-by-Step Analysis
In our step-by-step solution for vanadium(V) oxide, we multiplied the oxidation states by the smallest common multiple to get whole numbers for the eventual chemical formula. For instances where a simple 1:1 ratio doesn't achieve a neutral compound, this method helps us find the most reduced whole number ratio that does.Ionic Charges
Closely related to oxidation states are ionic charges. Ionic charges are indicative of the potential an atom has to engage in ionic bonding by gaining or losing electrons. Compounds like lead(IV) oxide and thallium(III) oxide are made up of cations (positively charged ions) and anions (negatively charged ions) that combine in a way that their overall ionic charges add up to zero.
Students often struggle with understanding how these charges interact, but remembering that the end goal is to achieve a net zero charge can simplify the process. The charges must always balance out, much like how a scale must be balanced by equal weights on both sides.
Understanding Ionic Balances
For lead(IV) oxide, lead has a charge of +4, and oxygen has a charge of -2. When we combine them, two oxygen ions are needed to balance out the single lead ion, resulting in the formula PbO2. In the case of thallium(III) oxide, the thallium ion has a +3 charge, while oxygen remains consistent with a -2 charge. Here, we achieve a neutral compound with the formula Tl2O3, where two thallium ions balance three oxide ions.Students often struggle with understanding how these charges interact, but remembering that the end goal is to achieve a net zero charge can simplify the process. The charges must always balance out, much like how a scale must be balanced by equal weights on both sides.
Compound Nomenclature
The naming of compounds, otherwise known as compound nomenclature, is a standardized method of assigning names to chemical substances. In inorganic chemistry, the system of nomenclature can tell us a lot about the compound, including the elements present and their proportions or oxidation states.
The correct use of nomenclature not only helps in writing and understanding chemical formulas, but also facilitates communication within the scientific community, ensuring clarity and precision. For students to excel in nomenclature, practice in both writing and interpreting chemical names is essential for the application in exercises and exams.
Deciphering Compound Names
For example, the name vanadium(V) oxide contains the element names and, more importantly, the oxidation state of the metal as indicated by the Roman numeral. The (V) after vanadium tells us that vanadium has a +5 oxidation state in the compound. Similarly, lead(IV) oxide and thallium(III) oxide reveal that lead and thallium have +4 and +3 oxidation states, respectively.The correct use of nomenclature not only helps in writing and understanding chemical formulas, but also facilitates communication within the scientific community, ensuring clarity and precision. For students to excel in nomenclature, practice in both writing and interpreting chemical names is essential for the application in exercises and exams.