For a certain reaction at constant pressure, \(\Delta H=-15 \mathrm{~kJ}\) and \(22 \mathrm{~kJ}\) of expansion work is done on the system. What is \(\Delta U\) for this process?

Short Answer

Expert verified
\(\Delta U = 7 \mathrm{~kJ}\)

Step by step solution

01

Understand the First Law of Thermodynamics

The First Law of Thermodynamics, also known as the law of energy conservation, can be expressed as \[\Delta U = \Delta Q - W\] where \(\Delta U\) is the change in internal energy, \(\Delta Q\) is the heat added to the system, and \(W\) is the work done by the system.
02

Relate Enthalpy Change to Heat at Constant Pressure

Under constant pressure, the heat added to the system (\(\Delta Q_p\)) is equal to the enthalpy change \(\Delta H\), so the equation becomes \[\Delta U = \Delta H - W\].
03

Insert Given Values into the Equation

In the problem, \(\Delta H = -15 \mathrm{~kJ}\) and the expansion work done on the system is \(22 \mathrm{~kJ}\). However, since work is done on the system, this value of work (\textbf{W}) should be negative when applied to the equation, thus \(W = -22 \mathrm{~kJ}\). The equation becomes \[\Delta U = (-15 \mathrm{~kJ}) - (-22 \mathrm{~kJ})\] which simplifies to \[\Delta U = -15 \mathrm{~kJ} + 22 \mathrm{~kJ}\].
04

Calculate the Change in Internal Energy

After inserting the values, solve for \(\Delta U\): \[\Delta U = -15 \mathrm{~kJ} + 22 \mathrm{~kJ} = 7 \mathrm{~kJ}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Enthalpy Change
Enthalpy change, denoted as \(\Delta H\), is a measure of the total heat content change in a system during a process, often a chemical reaction, at constant pressure. It's an important concept in thermodynamics because it gives us a quick way to calculate the energy change without needing to know all details about the system's internal energy states.

This value can be either positive or negative; a negative \(\Delta H\) indicates that heat is released by the system to the surroundings, known as an exothermic process, while a positive \(\Delta H\) means that heat is absorbed from the surroundings, or an endothermic process. In the given exercise, the negative \(\Delta H\) signifies that the reaction releases heat, hence why it is associated with a negative sign.
Internal Energy
Internal energy, represented as \(\Delta U\), is the total energy contained within a system. It encompasses all forms of energy, including kinetic and potential energy at the molecular level. In thermodynamics, the change in internal energy is what we often calculate or measure because we're interested in how energy moves in and out of systems.

The First Law of Thermodynamics states that energy can neither be created nor destroyed, only transformed from one form to another or transferred between systems. When dealing with \(\Delta U\), we see this law in action; any increase or decrease in a system's internal energy must be accounted for by energy transfers in the form of work or heat.
Constant Pressure
Carrying out a process at constant pressure is particularly relevant when discussing enthalpy change because it simplifies the relationship between heat added to the system and the work done by the system. At constant pressure, the work done \(W\) can be easily connected to the system's volume changes.

If, for example, a gas expands against a constant pressure, it does work on its surroundings, and the energy required to do that work comes from the internal energy of the gas. Hence, if we know the enthalpy change and the work done, we can deduce other properties of the system, as shown in our exercise.
Energy Conservation
Energy conservation is a fundamental principle stating that in an isolated system, the total energy remains constant over time. This is the essence of the First Law of Thermodynamics. In the context of our exercise, where we have quantified both the enthalpy change and the work done, energy conservation allows us to determine the change in internal energy of the system.

The crux of solving thermodynamics problems often lies in recognizing that we must account for all forms of energy transfer, such as heat and work, to honor the principle of energy conservation. Understanding this principle is critical for interpreting thermodynamic processes and predicting the behavior of systems under various conditions.

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Most popular questions from this chapter

(a) Near room temperature the specific heat capacity of ethanol is \(2.42 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1} \cdot \mathrm{g}^{-1}\). Calculate the heat that must be removed to reduce the temperature of \(150.0 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}\) from \(50.0^{\circ} \mathrm{C}\) to \(16.6^{\circ} \mathrm{C}\). (b) What mass of copper can be heated from \(15^{\circ} \mathrm{C}\) to \(205^{\circ} \mathrm{C}\) when \(425 \mathrm{~kJ}\) of energy is available?

A piece of metal of mass \(20.0 \mathrm{~g}\) at \(100.0^{\circ} \mathrm{C}\) is placed in a calorimeter containing \(50.7 \mathrm{~g}\) of watcr at \(22.0^{\circ} \mathrm{C}\). The final temperature of the mixture is \(25.7^{\circ} \mathrm{C}\) What is the specific heat capacity of the mctal? Assume that all the energy lost by the metal is gained by the water.

A gas in a cylinder was placed in a heater and gained \(7000 \mathrm{~kJ}\) of heat. If the cylinder increased in volume from \(700 \mathrm{~mL}\) to \(1450 \mathrm{~mL}\) against an atmospheric pressure of 750 Torr during this process, what is the change in internal energy of the gas in the cylinder?

For a certain reaction at constant pressure, \(\Delta U=-95 \mathrm{~kJ}\) and \(56 \mathrm{~kJ}\) of expansion work is done by the system. What is \(\Delta H\) for this process?

Determine the reaction enthalpy for the hydrogenation of ethyne to ethane, \(\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{~g})+\) \(2 \mathrm{H}_{2}(\mathrm{~g}) \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g})\), from the following data: enthalpy of combustion of ethyne, \(-1300 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\); enthalpy of combustion of ethane, \(-1560 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\); enthalpy of combustion of hydrogen, \(-286 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\).

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