(a) Describe three ways in which you could increase the internal energy of an open system. (b) Which of these methods could you use to increase the internal energy of a closed system? (c) Which, if any, of these methods could you use to increase the internal energy of an isolated system?

Short Answer

Expert verified
To increase the internal energy of an open system, add heat, do work on it, or allow mass with higher internal energy to flow in. For a closed system, add heat, or do work on it. An isolated system's internal energy cannot be increased by external means.

Step by step solution

01

Identifying Methods to Increase Internal Energy for an Open System

The internal energy of an open system can be increased through the following three methods: 1) Adding heat to the system (heat transfer), 2) Doing work on the system, and 3) Mass flow into the system with higher internal energy.
02

Methods Applicable to a Closed System

For a closed system, where mass exchange with the environment is not possible, internal energy can be increased by the first two methods: 1) Adding heat to the system and 2) Doing work on the system.
03

Methods for an Isolated System

An isolated system does not allow transfer of heat, work, or mass with its surroundings. Therefore, theoretically, no method can be used to increase the internal energy of an isolated system from the outside.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Open System Thermodynamics
An open system is a basic concept in thermodynamics where matter and energy can be exchanged with the surroundings. For instance, a boiling pot of water with a lid off is an open system as it allows steam to escape, transferring mass and energy to the environment.

In terms of increasing internal energy, open systems offer several mechanisms. By introducing mass with a higher internal energy, such as hot gas or liquid, the system's temperature can rise. Heat transfer through conduction, convection, or radiation can also raise the system's energy. Finally, performing work on the system, like stirring the water in the pot, can increase its internal energy.
Closed System Thermodynamics
A closed system permits the transfer of energy but not mass across its boundaries. Imagine a pot of water with a sealed lid; energy can leave or enter through the lid, but the water and steam cannot.

To increase the internal energy within a closed system, you could apply heat, which raises the temperature and potentially changes the phase of substances within the system. Another method is to perform work on the system. This could be mechanical work, such as compressing a piston in a cylinder, which increases the internal energy by raising the temperature and pressure.
Isolated System Thermodynamics
An isolated system is one step further removed from external influence than a closed system. It neither exchanges energy nor matter with its surroundings. A perfect example, although hypothetical, is an insulated thermos flask that is perfectly sealed.

Since neither heat transfer nor work is possible from the outside, and mass flow is impossible, the internal energy of a truly isolated system cannot be increased by external means. In reality, perfectly isolated systems don't exist, but the concept helps us understand the limits of energy transfer in theoretical thermodynamics.
Heat Transfer
Heat transfer is crucial to thermodynamics and involves the movement of thermal energy from one place to another. It occurs through three primary mechanisms: conduction, convection, and radiation. Conduction happens when heat moves through solid materials, like a metal rod being heated at one end. Convection circulates heat by the movement of fluids, such as boiling water. Radiation transmits heat through electromagnetic waves, like the warmth you feel from sunlight.

All these modes of heat transfer can raise a system's internal energy. They are especially relevant in open and closed systems but are not applicable for energy increase in isolated systems.
Work in Thermodynamics
Work is another way to alter a system's internal energy in thermodynamics. It refers to the effort exerted on a system that causes a displacement against a force. For example, compressing a gas within a piston does work on the gas and increases its internal energy.

In open and closed systems, doing work can input energy into the system. This is characterized by processes like stirring, compressing, or expanding. However, in an isolated system, no work can be done to increase internal energy, as it is closed off from any external energy.
Mass flow
Mass flow is the movement of substances into or out of a system, which can alter the system's internal energy based on the energy state of the substance being transferred. For example, pumping hot water into a heating system brings in internal energy through the increased temperature and enthalpy of the incoming water.

In an open system, mass flow is a direct way to modify the system's internal energy. Mass entering the system with higher internal energy, such as greater temperature or chemical potential, elevates the system's energy. Conversely, mass flow does not apply to closed and isolated systems, as they do not allow mass transfer with their surroundings.

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Most popular questions from this chapter

(a) At its boiling point, the vaporization of \(0.235 \mathrm{~mol} \mathrm{CH}_{4}(1)\) requires \(1.93 \mathrm{~kJ}\) of heat. What is the enthalpy of vaporization of methane? (b) An electric heater was immersed in a flask of boiling crhanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), and \(22.45 \mathrm{~g}\) of ethanol was vaporized when \(21.2 \mathrm{~kJ}\) of energy was supplied. What is the enthalpy of vaporization of ethanol?

Calculate the reaction enthalpy for the formation of anhydrous aluminum chloride, \(2 \mathrm{Al}(\mathrm{s})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{AlCl}_{3}(\mathrm{~s})\), from the following data: $$ \begin{array}{ll} 2 \mathrm{Al}(\mathrm{s})+6 \mathrm{HCl}(\mathrm{aq}) \longrightarrow 2 \mathrm{AlCl}_{3}(\mathrm{aq})+3 \mathrm{H}_{2}(\mathrm{~g}) \\ & \Delta H^{\circ}=-1049 \mathrm{~kJ} \\ \mathrm{HCl}(\mathrm{g}) \longrightarrow \mathrm{HCl}(\mathrm{aq}) & \Delta H^{\circ}=-74.8 \mathrm{~kJ} \\ \mathrm{H}_{2}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{HCl}(\mathrm{g}) & \Delta H^{\circ}=-185 \mathrm{~kJ} \\ \mathrm{AlCl}_{3}(\mathrm{~s}) \longrightarrow \mathrm{AlCl}_{3}(\mathrm{aq}) & \Delta H^{\circ}=-323 \mathrm{~kJ} \end{array} $$

Determine the reaction enthalpy for the hydrogenation of ethyne to ethane, \(\mathrm{C}_{2} \mathrm{H}_{2}(\mathrm{~g})+\) \(2 \mathrm{H}_{2}(\mathrm{~g}) \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}(\mathrm{~g})\), from the following data: enthalpy of combustion of ethyne, \(-1300 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\); enthalpy of combustion of ethane, \(-1560 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\); enthalpy of combustion of hydrogen, \(-286 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\).

Write the thermochemical equations that give the values of the standard enthalpies of formation for (a) \(\mathrm{KClO}_{3}\) (s), potassium chlorate; (b) \(\mathrm{H}_{2} \mathrm{NCH}_{2} \mathrm{COOH}\) (s), glycine(s); (c) \(\mathrm{Al}_{2} \mathrm{O}_{3}(\mathrm{~s})\), alumina.

Use the enthalpies of formation in Appendix \(2 \mathrm{~A}\) to calculate the standard enthalpy of the following reactions: (a) the replacement of deuterium by ordinary hydrogen in heavy water: \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{D}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{D}_{2}(\mathrm{~g})\) (b) the removal of sulfur from the hydrogen sulfide and sulfur dioxide in natural gas: \(2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g})+\mathrm{SO}_{2}(\mathrm{~g}) \rightarrow 3 \mathrm{~S}(\mathrm{~s})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) (c) the oxidation of ammonia: \(4 \mathrm{NH}_{3}(\mathrm{~g})+5 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 4 \mathrm{NO}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)

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