If a \(70-\mathrm{kg}\) male burns \(2000 \mathrm{~kJ}\) of energy while jogging for \(1.0 \mathrm{~h}\), what mass of fat would be consumed, given that the typical standard energy of combustion of fat is about \(38 \mathrm{~kJ} \cdot \mathrm{g}^{-1}\) ? How many hours would he need to jog if he wished to lose \(0.50 \mathrm{~kg}\) of fat?

Short Answer

Expert verified
He burns 52.63 grams of fat per hour. To lose 0.50 kg (500 grams) of fat, he would need to jog for approximately 9.5 hours.

Step by step solution

01

Calculate Mass of Fat Burned

To find the mass of fat burned during the jog, divide the energy burned by the energy released per gram of fat. Use the formula: mass of fat burned = energy burned / energy per gram of fat.
02

Calculate Time Required to Lose 0.50 kg of Fat

Find out how many grams of fat correspond to 0.50 kg because the energy value is given in grams. Then, calculate how many hours it will take to burn that mass of fat by dividing the mass of fat to be lost (in grams) by the mass of fat burned per hour.
03

Convert Energy Values

Both the energy burned jogging and the energy per gram of fat are given in kilojoules. There is no need for conversion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Caloric Energy Expenditure
Understanding caloric energy expenditure is essential when exploring how activities like exercise affect our body. Caloric energy expenditure refers to the amount of energy - measured in calories or kilojoules - that a person uses up to maintain their body's basic functions at rest, plus the energy used during physical activities.

Let's take a typical exercise scenario. If a 70-kg male burns 2000 kJ of energy while jogging for an hour, he's not just getting a good workout; he's also expending a significant amount of caloric energy. This energy comes from the breakdown of nutrients in the body - predominantly carbohydrates and fats. The body prefers to burn readily available carbohydrates first, but as exercise continues, particularly at a moderate to high intensity, the body begins to tap into its fat stores releasing the energy stored in those fat cells.

The mass of fat burned can be calculated using the energy expenditure during the exercise and the energy content per gram of fat. This is pivotal for individuals working towards weight-loss goals or those managing their energy balance.
Fat Metabolism
Diving into the world of fat metabolism unveils how our body processes and uses fat as an energy source. When we talk about fat metabolism during exercise, we are essentially talking about how our bodies break down fat stores and convert them into usable energy.

Fats, stored as triglycerides in fat cells, undergo a complex biochemical process where these triglycerides are broken down into glycerol and fatty acids through lipolysis. These fatty acids are then transported to the muscles, where they are oxidized or 'burned' for energy. The energy released per gram of fat during this metabolic conversion is significant, typically about 38 kJ/g.

During exercise, the intensity and duration will influence whether carbohydrates or fats are the primary source of fuel. As the exercise question above demonstrates, to determine the mass of fat consumed during exercise, we divide the total energy spent (2000 kJ) by the energy yield of fat combustion (38 kJ/g).
Exercise and Energy Consumption
The relationship between exercise and energy consumption is a topic of great interest for anyone concerned with physical fitness, weight management, and overall health. Exercise is one of the primary ways individuals can increase their energy expenditure to create a caloric deficit, which is necessary for weight loss.

During exercise, the body's demand for energy soars to meet the increased needs of muscle work. This energy can come from the anaerobic breakdown of glucose for quick, short bursts of movement, or from aerobic pathways that use oxygen to metabolically convert fat and carbohydrates into energy over longer periods.

The exercise scenario presented requires calculating the time required to lose a specific mass of fat by jogging. If, for instance, someone wishes to lose 0.50 kg of fat, and knowing that jogging for an hour burns the equivalent fat mass for 2000 kJ of energy, we can deduce the time needed for such weight loss. It's a matter of dividing the desired weight loss in grams by the number of grams of fat burned in one hour of jogging. This sort of calculation is fundamental for goal-setting and progress tracking in weight management plans.

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Most popular questions from this chapter

The heat capacity of a certain empty calorimeter is \(488.1 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1}\). When \(25.0 \mathrm{~mL}\) of \(0.700 \mathrm{M}\) \(\mathrm{NaOH}(\mathrm{aq})\) was mixed in that calorimeter with \(25.0 \mathrm{~mL}\) of \(0.700 \mathrm{M} \mathrm{HCl}\) (aq), both initially at \(20.00^{\circ} \mathrm{C}\), the temperature increased to \(21.34^{\circ} \mathrm{C}\). Calculate the enthalpy of neutralization in kilojoules per mole of HCI.

In the manufacture of nitric acid by the oxidation of ammonia, the first product is nitric oxide, which is then cxidized to nitrogen dioxide. From the standard reaction enthalpies $$ \begin{gathered} \mathrm{N}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}(\mathrm{g}) \\ \Delta H^{\circ}=+180.5 \mathrm{~kJ} \\ \mathrm{~N}_{2}(\mathrm{~g})+2 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{~g}) \\ \Delta H^{\circ}=+66.4 \mathrm{~kJ} \end{gathered} $$ calculate the standard reaction enthalpy for the oxidation of nitric oxide to nitrogen dioxide: $$ 2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{~g}) $$

Near room temperature, the specific heat capacity of benzene is \(1.05 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1} \mathrm{~g}^{-1}\). Calculate the heat nceded to raise the temperature of \(50.0 \mathrm{~g}\) of benzene from \(25.3^{\circ} \mathrm{C}\) to \(37.2^{\circ} \mathrm{C}\). (b) A \(1.0-\mathrm{kg}\) block of aluminum is supplied with \(490 \mathrm{~kJ}\) of heat. What is the temperature change of the aluminum? The specific heat capacity of aluminum is \(0.90 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1} \cdot \mathrm{g}^{-1}\).

(a) Near room temperature the specific heat capacity of ethanol is \(2.42 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1} \cdot \mathrm{g}^{-1}\). Calculate the heat that must be removed to reduce the temperature of \(150.0 \mathrm{~g}\) of \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}\) from \(50.0^{\circ} \mathrm{C}\) to \(16.6^{\circ} \mathrm{C}\). (b) What mass of copper can be heated from \(15^{\circ} \mathrm{C}\) to \(205^{\circ} \mathrm{C}\) when \(425 \mathrm{~kJ}\) of energy is available?

Calculate the amount of heat needed to raise the temperature of \(0.325 \mathrm{~mol}\) of a monatomic idcal gas from a temperature of \(-25^{\circ} \mathrm{C}\) to \(+50^{\circ} \mathrm{C}\) at (a) constant volume and (b) constant pressure. (c) Why is more heat needed to raise the temperature at constant pressure than at constant volume?

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