The heat capacity of a certain empty calorimeter is \(488.1 \mathrm{~J} \cdot\left({ }^{\circ} \mathrm{C}\right)^{-1}\). When \(25.0 \mathrm{~mL}\) of \(0.700 \mathrm{M}\) \(\mathrm{NaOH}(\mathrm{aq})\) was mixed in that calorimeter with \(25.0 \mathrm{~mL}\) of \(0.700 \mathrm{M} \mathrm{HCl}\) (aq), both initially at \(20.00^{\circ} \mathrm{C}\), the temperature increased to \(21.34^{\circ} \mathrm{C}\). Calculate the enthalpy of neutralization in kilojoules per mole of HCI.

Short Answer

Expert verified
The enthalpy of neutralization for HCl is -37.37 kJ/mol.

Step by step solution

01

Identify the Reaction

The reaction taking place is the neutralization between hydrochloric acid (HCl) and sodium hydroxide (NaOH). The balanced chemical equation for the neutralization is:\[\mathrm{NaOH(aq) + HCl(aq) \rightarrow NaCl(aq) + H_2O(l)}\]In this reaction, one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.
02

Calculate the Number of Moles of HCl

To find the number of moles of HCl, use the concentration and volume of the HCl solution. The number of moles is calculated by the product of concentration (M) and volume (L):\[\text{mol HCl} = 0.700 \, \frac{\text{mol}}{\text{L}} \times 0.0250 \, \text{L} = 0.0175 \, \text{mol}\]
03

Calculate the Energy Change of the System

The energy change (q) can be found by using the formula:\[q = C_{cal} \times \Delta T\]where \( C_{cal} \) is the heat capacity of the calorimeter and \( \Delta T \) is the change in temperature. Thus:\[q = 488.1 \, \text{J/}^{\circ}\text{C} \times (21.34^{\circ}\text{C} - 20.00^{\circ}\text{C}) = 488.1 \, \text{J/}^{\circ}\text{C} \times 1.34^{\circ}\text{C} = 654.054 \, \text{J}\]
04

Calculate the Enthalpy of Neutralization Per Mole of HCl

The enthalpy of neutralization (\(\Delta H_{neut}\)) is the energy change per mole of reactant. Since the reaction involves one mole of HCl reacting, calculate the enthalpy change per mole of HCl as follows:\[\Delta H_{neut} = \frac{q}{\text{mol HCl}} = \frac{654.054 \, \text{J}}{0.0175 \, \text{mol}} = 37374.514 \, \text{J/mol}\]Convert this value to kilojoules per mole (kJ/mol) by dividing by 1000:\[\Delta H_{neut} = \frac{37374.514 \, \text{J/mol}}{1000} = 37.37 \, \text{kJ/mol}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Thermodynamics
Chemical thermodynamics is the branch of chemistry that deals with the relationship between chemical reactions and energy changes. Specifically, it studies the transfer of energy, in various forms, during chemical processes.

Central to this field is the understanding of the first law of thermodynamics, which states that energy cannot be created or destroyed, only transformed from one form to another. The concept of enthalpy, denoted as 'H', is key to chemical thermodynamics. Enthalpy is the measure of the total heat content of a system at constant pressure and is closely connected to the heat of reactions.

Enthalpy of Neutralization

Referring to the exercise above, the enthalpy of neutralization is the change in enthalpy when an acid and base react to form water and a salt. This is an exothermic reaction, meaning it releases heat, resulting in an increase in the temperature of the solution within the calorimeter.
Calorimetry
Calorimetry is a technique for measuring the amount of heat involved in a chemical reaction, physical change, or heat capacity. This is achieved by using an instrument called a calorimeter. There are two types of calorimeters: constant-pressure and constant-volume calorimeters.

The calorimetry experiment typically involves measuring the temperature change of a solution or substance when a reaction occurs. By knowing the heat capacity of the calorimeter and the temperature change (as seen in the exercise), the amount of heat absorbed or released can be calculated. The heat capacity of a calorimeter, which is known prior to the experiment, is crucial for determining the energy change of the reaction.
Stoichiometry
Stoichiometry is the section of chemistry that involves using balanced chemical equations to calculate the relative quantities of reactants and products involved in a chemical reaction.

In the context of the exercise, stoichiometry allows us to determine the exact amount of reactants – in this case, the moles of hydrochloric acid and sodium hydroxide – that will react. Using the molarity (concentration in moles per liter) and the volume of the reactants, stoichiometry is used to convert these values into moles, which are required for further calculations like determining the enthalpy of neutralization.
Acid-Base Reactions
Acid-base reactions are a type of chemical reaction that typically occur in an aqueous solution, where an acid and a base react to form a salt and water. This reaction is also referred to as a neutralization reaction.

In an acid-base reaction, the acid donates a proton (H+) to the base. In the provided exercise, hydrochloric acid (HCl) acts as the acid and sodium hydroxide (NaOH) as the base. The balanced equation for the reaction is key for understanding how molecules interact and, as shown, indicates that an equal number of moles of each reactant are required for the reaction to proceed to completion.

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Most popular questions from this chapter

(a) At its boiling point, the vaporization of \(0.235 \mathrm{~mol} \mathrm{CH}_{4}(1)\) requires \(1.93 \mathrm{~kJ}\) of heat. What is the enthalpy of vaporization of methane? (b) An electric heater was immersed in a flask of boiling crhanol, \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\), and \(22.45 \mathrm{~g}\) of ethanol was vaporized when \(21.2 \mathrm{~kJ}\) of energy was supplied. What is the enthalpy of vaporization of ethanol?

Elemental sulfur occurs in several forms, with rhombic sulfur being the most stable under normal conditions and monoclinic sulfur slightly less stable. The standard cnthalpies of combustion of the two forms to sulfur dioxide are \(-296.83\) and \(-297.16 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), respectively. Calculate the change in molar enthalpy for the rhombic \(\rightarrow\) monoclinic transition.

The standard enthalpies of combustion of graphite and diamond are \(-393.51\) and \(-395.41 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), respectively. Calculate the change in molar enthalpy for the graphite \(\rightarrow\) diamond transition.

A gas sample is heated in a cylinder, using \(375 \mathrm{~kJ}\) of heat. At the same time a piston compresses the gas, using \(645 \mathrm{~kJ}\) of work. What is the change in internal energy of the gas during this process?

A gas in a cylinder was placed in a heater and gained \(7000 \mathrm{~kJ}\) of heat. If the cylinder increased in volume from \(700 \mathrm{~mL}\) to \(1450 \mathrm{~mL}\) against an atmospheric pressure of 750 Torr during this process, what is the change in internal energy of the gas in the cylinder?

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