What physical propertics are used for the separation of the components of a mixture by (a) filrration; (b) chromatography; (c) distillation?

Short Answer

Expert verified
Filtration uses particle size, chromatography relies on adsorption, solubility, and diffusion rates, and distillation hinges on the difference in boiling points of the mixture's components.

Step by step solution

01

Identifying the Basis of Filtration

Filtration is a method used to separate solids from liquids or gases by passing the mixture through a porous barrier. The physical property utilized in filtration is the particle size. Larger solid particles are unable to pass through the pores of the filter, while the fluid and any dissolved substances can pass through.
02

Understanding the Principle of Chromatography

Chromatography is a technique that separates the different components of a mixture based on how each interacts with a stationary phase (such as paper or gel) versus a mobile phase (such as a solvent). The physical properties used in chromatography are adsorption, solubility, and diffusion rates of each component in the mixture.
03

Exploring the Mechanism of Distillation

Distillation is used to separate mixtures based on differences in the volatility or boiling points of the components. The component with the lower boiling point vaporizes first and is collected, while the component with the higher boiling point remains in the liquid state and is separated later.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Filtration
Imagine a kitchen strainer separating noodles from water; this is akin to filtration in chemistry. Filtration is a technique that relies on the size of particles in a mixture. When a heterogeneous mixture is poured onto a filter, materials larger than the filter's pores are trapped while smaller components, including liquids and dissolved substances, pass through. This simple yet effective method is crucial in scientific labs and even in the water purification process.

Understanding that different substances have varying particle sizes is key to successful filtration. Students often overlook the importance of selecting the right filter pore size, which is as critical as the procedure itself for achieving a proper separation.
Chromatography
Chromatography is like a race where different substances move at different speeds. It is an advanced separation method based on how particles adsorb to a surface (stationary phase) or dissolve in a solvent (mobile phase).

Adsorption and Solubility

Those with a higher affinity for the stationary phase will travel slowly, while those preferring the solvent will move faster.

Diffusion Rates

The different diffusion rates also affect how quickly components spread out within the mobile phase.

Students must realize that chromatography is not about speed but interaction differences. Each component's unique properties dictate its behavior and ultimate position on the chromatographic substrate, allowing for precise separations that are used in everything from forensics to food safety.
Distillation
Distillation is the scientific equivalent of boiling away your troubles. In this process, a mixture's components are separated based on their volatility or, in simpler terms, their boiling points.

When a mixture is heated, the most volatile component, the one with the lowest boiling point, vaporizes first. This vapor is then cooled in a condenser, turning it back into a liquid that is collected separately, leaving behind components with higher boiling points. This technique is pivotal in creating distilled spirits and also widely used in the pharmaceutical industry. While students may see this as boiling water to get salt, it's also the principle behind producing essential oils and fuels.
Particle Size
Particle size might sound trivial, but in the world of chemical separations, it is a determining factor. The size of particles in a mixture dictates whether they can be filtered, how they settle in centrifugation, or even how they scatter light in solutions.

Grasping the concept of particle size helps students understand why certain substances can be separated through filtration or why some suspensions may need to be shaken before use. It's the reason why sand settles at the bottom of a water jug and why flour can be sifted to remove lumps.
Adsorption
Adsorption is the process where atoms, ions, or molecules adhere to a surface.

Think of it as a micro-scale stickiness that helps in separating mixes in chromatography. The specificity of adsorption allows chemists to isolate desired components from complex mixtures. A student might wonder why certain gases are better at scrubbing pollution from the air - adsorption is the answer. By understanding the properties that affect adsorption, such as surface area and polarity, students can better grasp how different materials interact.
Solubility
Solubility is a measure of how well a substance can dissolve in a solvent. It is central not just in separation techniques like chromatography but also in everyday life, from making lemonade to pharmaceutical drug design. Substances with high solubility will mix well and dissolve, while those with low solubility will separate out, forming precipitates or layers.

Students should understand solubility rules to predict and explain the outcomes of reactions and separations. It's an essential concept that crosses over into cooking, medicine, and environmental science.
Diffusion Rates
Diffusion rates tell us how fast different substances spread through a medium. In chromatography, for instance, the components of a mixture will spread out and move at different rates depending on how they interact with the stationary and mobile phases.

Recognizing that molecules move and spread out at varying speeds due to their size, shape, and interactions with surrounding molecules can aid students in understanding gas exchange in lungs or the distribution of nutrients and wastes in cells.
Volatility
Volatility indicates how readily a substance vaporizes at a given temperature and pressure. In layman's terms, how easily it turns into a gas. This quality is used in distillation to separate components in a chemical mixture. Highly volatile substances will vaporize at lower temperatures; thus, they are separated first.

By understanding volatility, students can appreciate the challenges in storing and transporting volatile substances like gasoline and the importance of controlling conditions in distillation processes.
Boiling Point
The boiling point is the temperature at which a liquid turns into vapor. It plays a central role in distillation, where mixtures are separated based on the differing boiling points of their individual components. Boiling point is influenced by the molecular structure and atmospheric pressure.

Students often grasp the concept of boiling water but may not consider how boiling points can vary under different conditions or why antifreeze is needed in cars. Understanding how boiling points change with pressure leads to a deeper comprehension of not just distillation, but also natural phenomena like how water boils at lower temperatures on high mountains.

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Most popular questions from this chapter

(a) A 12.56-mL sample of \(1.345 \mathrm{M} \mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq})\) is diluted to \(250.0 \mathrm{~mL}\). What is the molar concentration of \(\mathrm{K}_{2} \mathrm{SO}_{4}\) in the diluted solution? (b) A \(25.00-\mathrm{mL}\) sample of \(0.366 \mathrm{M} \mathrm{HCl}(\mathrm{aq})\) is drawn from a reagent bottle with a pipet. The sample is transferred to a \(125.00-\mathrm{mL}\) volumetric flask and diluted to the mark with water. What is the molar concentration of the dilute hydrochloric acid solution?

In a laboratory exercise, a student mixes \(2.5 .0 \mathrm{~g}\) of cthanol, \(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}\), with \(150 \mathrm{~g}\) of water. (a) What is the mole fraction of ethanol in the solution? (b) What is the molality of cthanol in the solution?

(a) Determine the mass of anhydrous copper(II) sulfate that must be used to prepare \(250 \mathrm{~mL}\) of a \(0.20 \mathrm{M} \mathrm{CuSO}_{4}(\mathrm{aq})\) solution. (b) Determine the mass of \(\mathrm{CuSO}_{4}-5 \mathrm{H}_{2} \mathrm{O}\) that must be used to prepare \(250 \mathrm{ml}\). of a \(0.20 \mathrm{M} \mathrm{CuSO}_{4}(\mathrm{aq})\) solution.

(a) A chemist prepared a solution by dissolving \(1.230 \mathrm{~g}\) of \(\mathrm{KCl}\) in enough water to make \(150.0 \mathrm{~mL}\) of solution. What molar concentration of potassium chloride should appear on the label? (b) If the chemist had mistakenly used a 500 -mL. volumetric flask instead of the 150.0-mL flask in (a), what molar concentration of potassium chloride has the chemist actually prepared?

A student investigating the propertics of solutions containing carbonate ions prepared a solution containing \(7.112 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) in a \(250.0-\mathrm{mL}\) volumetric flask. Some of the solution was transferred to a burer. What volume of solution should be dispensed from the buret to provide (a) \(5.112 \times 10^{-3} \mathrm{~mol} \mathrm{Na}_{2} \mathrm{CO}_{3}\); (b) \(3.451 \times 10^{-3} \mathrm{~mol} \mathrm{CO}_{3}^{2-}\) ?

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