Bromomethane, \(\mathrm{CH}_{3} \mathrm{Br}\), and iodomethane, \(\mathrm{CH}_{3} \mathrm{I}\), form an ideal solution. The vapor pressure of bromomethane is 661 Torr and that of iodomethane is 140 Torr at \(0.0^{\circ} \mathrm{C}\). Calculate the vapor pressure of each of the following solutions and the mole fraction of each substance in the vapor phase above those solutions at \(0.0^{\circ} \mathrm{C}:\) (a) \(0.33 \mathrm{~mol}\) of bromomethane mixed with \(0.67 \mathrm{~mol}\) of iodomethane; (b) \(35.0 \mathrm{~g}\) of bromomethane mixed with \(35.0 \mathrm{~g}\) of iodomethane.

Short Answer

Expert verified
Solution (a): Calculate mole fractions, multiply by individual vapor pressures to get partial vapor pressures and sum them for total vapor pressure; divide each component's partial pressure by total vapor pressure for vapor phase mole fractions. Solution (b): Convert grams to moles, calculate mole fractions, follow similar steps as in solution (a).

Step by step solution

01

Use Raoult's Law

According to Raoult's Law, the vapor pressure of each component in an ideal solution is proportional to its mole fraction times its pure component vapor pressure. Given that the vapor pressure of bromomethane is 661 Torr and for iodomethane is 140 Torr, we can write for each component: For bromomethane: \( P_{\text{Br}} = X_{\text{Br}} \times P_{\text{Br}}^0 \)For iodomethane: \( P_{\text{I}} = X_{\text{I}} \times P_{\text{I}}^0 \)where \(P_{\text{Br}}^0\) and \(P_{\text{I}}^0\) are the vapor pressures of pure bromomethane and iodomethane, respectively, and \(X_{\text{Br}}\) and \(X_{\text{I}}\) are their mole fractions in the liquid phase.
02

Calculate Mole Fractions for Solution (a)

For solution (a), calculate the mole fractions of bromomethane and iodomethane:\( X_{\text{Br}} = \frac{\text{moles of Br}}{\text{total moles}} = \frac{0.33}{0.33 + 0.67} \)\( X_{\text{I}} = \frac{\text{moles of I}}{\text{total moles}} = \frac{0.67}{0.33 + 0.67} \)Substitute the given mol values to find the mole fractions for each component.
03

Calculate Partial Vapor Pressures for Solution (a)

Using the calculated mole fractions and the pure component vapor pressures, find the partial vapor pressures of bromomethane and iodomethane:\( P_{\text{Br}} = X_{\text{Br}} \times 661 \text{ Torr} \)\( P_{\text{I}} = X_{\text{I}} \times 140 \text{ Torr} \)Calculate these pressures using the values found in Step 2.
04

Calculate Total Vapor Pressure for Solution (a)

The total vapor pressure of the solution is the sum of the partial vapor pressures of each component:\( P_{\text{total}} = P_{\text{Br}} + P_{\text{I}} \)Add the partial pressures calculated in Step 3 to get the total vapor pressure for solution (a).
05

Find the Mole Fraction of Each Component in the Vapor Phase for Solution (a)

The mole fraction of each substance in the vapor phase is given by the ratio of its partial pressure to the total pressure:\( Y_{\text{Br}} = \frac{P_{\text{Br}}}{P_{\text{total}}} \)\( Y_{\text{I}} = \frac{P_{\text{I}}}{P_{\text{total}}} \)Calculate these mole fractions using the pressures found in Steps 3 and 4.
06

Convert Mass to Moles for Solution (b)

To calculate the vapor pressure of the mixture by mass, first convert the masses to moles using the molar mass of each substance:\( \text{Moles of Br} = \frac{35.0 \text{ g}}{\text{Molar mass of Br}} \)\( \text{Moles of I} = \frac{35.0 \text{ g}}{\text{Molar mass of I}} \)Use the molar masses \( \text{CH}_3\text{Br} = 94.94 \text{ g/mol} \) and \( \text{CH}_3\text{I} = 141.94 \text{ g/mol} \).
07

Calculate Mole Fractions for Solution (b)

After finding the moles of each component, calculate the mole fractions for bromomethane and iodomethane in solution (b) similarly to Step 2.
08

Calculate Partial Vapor Pressures for Solution (b)

With the mole fractions from Step 7, calculate the partial vapor pressures of bromomethane and iodomethane in solution (b), similar to the process in Step 3.
09

Calculate Total Vapor Pressure for Solution (b)

Add the partial pressures from Step 8 to get the total vapor pressure for solution (b), similar to Step 4.
10

Determine Mole Fractions in Vapor Phase for Solution (b)

Finally, calculate the mole fractions of bromomethane and iodomethane in the vapor phase for solution (b), using the method described in Step 5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vapor Pressure
When a liquid is at equilibrium with its vapor in a closed container, the pressure exerted by the vapor is known as vapor pressure. This pressure is a result of the molecules escaping from the liquid phase into the gas phase. Vapor pressure depends on the temperature and the nature of the liquid; it increases with temperature and varies depending on the substance's volatility. For instance, the vapor pressure of bromomethane at a certain temperature might differ notably from that of iodomethane, due to differences in their molecular structures and intermolecular forces. Understanding vapor pressure is crucial when studying mixtures, as it influences the behavior of solutions and the distribution of components between the liquid and vapor phases.
Mole Fraction
Mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the number of moles of a particular substance to the total number of moles of all the substances present in the mixture. Represented by the symbol \( X \), it is dimensionless and always ranges between 0 and 1. For example, if you have a container with bromomethane and iodomethane, the mole fraction of bromomethane \( X_{\text{Br}} \) would be calculated by dividing the moles of bromomethane by the total moles of both bromomethane and iodomethane. It's an essential concept in applying Raoult's Law since vapor pressures of individual components in a solution are proportional to their respective mole fractions.
Ideal Solution
An ideal solution is one where the components mix perfectly at the molecular level, behaving ideally in accordance to Raoult's Law. In such a solution, the interactions between different molecules (A-B) are equal to the interactions among the same kind of molecules (A-A or B-B). There is no change in enthalpy when an ideal solution is formed, implying that no heat is absorbed or released. These solutions also follow a linear mixture rule concerning properties like vapor pressure. In an ideal solution, each component contributes to the total vapor pressure in proportion to its mole fraction, reflecting the essence of Raoult's Law. Real solutions often deviate from ideal behavior due to various intermolecular forces at play, but substances with similar molecular sizes and intermolecular forces, like bromomethane and iodomethane, may closely approximate ideal solution behavior.
Partial Vapor Pressure
Partial vapor pressure refers to the pressure exerted by a single component of a mixture of liquids in the vapor phase when that component is in equilibrium with the liquid phase. According to Raoult's Law, the partial vapor pressure \( P_i \) of component \( i \) in a mixture is equal to the product of the mole fraction \( X_i \) of that component in the liquid phase and the vapor pressure \( P^0_i \) of the pure component at the same temperature: \( P_i = X_i \times P^0_i \). When regarding an ideal solution such as a bromomethane and iodomethane mixture, understanding the concept of partial vapor pressure is critical to determining the contribution each substance makes to the total vapor pressure of the solution. It indicates the tendency of each component to escape into the vapor phase and is pivotal in the calculation of total vapor pressures and mole fractions in the vapor phase above a solution.

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