Explain why the following equilibria are heterogencous and write the reaction quoticnt \(Q\) for each one. (a) \(\mathrm{NH}_{4} \mathrm{Cl}(\mathrm{s})=\mathrm{NH}_{3}(\mathrm{~g})+\mathrm{HCl}(\mathrm{g})\) (b) \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot \mathrm{OH}_{2} \mathrm{O}\) (s) \(\rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{~s})+10 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (c) \(2 \mathrm{KCO}_{3}\) (s) \(\Rightarrow 2 \mathrm{KCl}\) (s) \(+3 \mathrm{O}_{2}\) (g)

Short Answer

Expert verified
The equilibria are heterogeneous because they involve reactants and products in different phases. (a) Q: \(\left[\mathrm{NH}_3\right]\left[\mathrm{HCl}\right]\). (b) Q: \(\left[\mathrm{H}_2\mathrm{O}\right]^{10}\). (c) Q: \(\left[\mathrm{O}_2\right]^3\).

Step by step solution

01

Identify Heterogeneous Equilibria

A heterogeneous equilibrium involves reactants and products that are in different phases. In case (a), both products are gases while the reactant is a solid. In case (b), the reactants and products are in different states: solid to solid and gas. In case (c), the reactants are solids and the product is a gas.
02

Write the Reaction Quotient Q for (a)

For the reaction \(\mathrm{NH}_{4}\mathrm{Cl}(\mathrm{s})=\mathrm{NH}_{3}(\mathrm{~g})+\mathrm{HCl}(\mathrm{g})\), the reaction quotient Q is given by \(Q = \frac{ \left[ \mathrm{NH}_{3} \right] \left[ \mathrm{HCl} \right] }{1}\), since the concentration of a pure solid is not included in the expression for Q.
03

Write the Reaction Quotient Q for (b)

For the reaction \(\mathrm{Na}_{2} \mathrm{CO}_{3} \cdot 10\mathrm{H}_{2} \mathrm{O}(\mathrm{s}) \rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{~s})+10 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\), Q is expressed as \(Q = \frac{\left[\mathrm{H}_{2}\mathrm{O}\right]^{10}}{1}\) since the concentrations of pure solids are not included in Q.
04

Write the Reaction Quotient Q for (c)

For the reaction \(2\mathrm{KCO}_{3}(\mathrm{s}) \Rightarrow 2\mathrm{KCl}(\mathrm{s}) + 3\mathrm{O}_{2}(\mathrm{g})\), the reaction quotient Q is \(Q = \frac{\left[\mathrm{O}_{2}\right]^3}{1}\), as only the gaseous components are included in the expression for Q.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Quotient Q
Understanding the reaction quotient, Q, is a critical aspect of studying chemical reactions, especially when they don't exist exclusively in one phase state, known as heterogeneous equilibria. In these reactions, the substances involved can exist as solids, liquids, or gases.

Imagine a snapshot of a reaction in-progress, where reactants and products are present in various amounts. This snapshot is described quantitatively by the reaction quotient, Q, which is expressed similarly to the equilibrium constant, Keq, but is applicable at any moment before equilibrium is reached.

The formula for Q is composed of the concentrations of the gaseous and aqueous species raised to the power of their coefficients in the balanced chemical equation. Solid and liquid pure substances are not included as their concentrations are considered constant and do not affect the ratio.

For example, in the reaction \(NH_4Cl(s) \rightarrow NH_3(g) + HCl(g)\), Q is expressed by the equation \(Q = \frac{[NH_3][HCl]}{1}\). This formula takes into account both gaseous ammonia and hydrogen chloride. It's important to monitor Q because it indicates the direction in which the reaction is likely to proceed to reach equilibrium.
Chemical Equilibrium
Chemical equilibrium represents a state in a chemical reaction where the rates of the forward and reverse reactions are equal, leading to no net change in the concentrations of reactants and products over time. It's a dynamic process where the reactants form products at the same rate as products revert to reactants.

At equilibrium, the reaction quotient Q equals the equilibrium constant Keq. This equality does not mean that the amounts of reactants and products are equal, but rather that their ratios remain constant. When Q and Keq are compared, if Q < Keq, the reaction will proceed forward, and if Q > Keq, the reaction will proceed in reverse to achieve equilibrium.

Understanding the concept of equilibrium is key to predict the behavior of a system under given conditions and to determine the optimal conditions for a reaction to proceed, which can be pivotal in industrial applications and in understanding biological systems.
Phase States in Reactions
The presence of different phase states in a reaction is characteristic of heterogeneous equilibria. All reactions involve various intermolecular forces and energy changes, which are significantly influenced by the phase states of the reacting species.

For example, in the dehydration of hydrated sodium carbonate, \(Na_2CO_3\cdot10H_2O(s) \rightleftharpoons Na_2CO_3(s) + 10H_2O(g)\), the reactant is a solid, and it decomposes into another solid and a gas when heated. The phase change introduces complexity to the reaction kinetics and thermodynamics.

Phase states are crucial in determining the form of the equilibrium expression for a reaction. Solids and liquids, due to their constant densities, do not appear in the equilibrium expression. Only the concentrations (or partial pressures) of gases and the molar concentrations of solutes in solution are included. In short, phase states have significant implications on the chemical properties and behaviors of substances in a reaction.

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Most popular questions from this chapter

Explain why the following cquilibria are heterogeneous and write the reaction quotient \(Q\) for each one. (a) \(2 \mathrm{Fe}(\mathrm{s})+3 \mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{FcCl}_{3}(\mathrm{~s})\) (b) \(\mathrm{NH}_{4}\left(\mathrm{NH}_{2} \mathrm{CO}_{2}\right)(\mathrm{s}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})+\mathrm{CO}_{2}(\mathrm{~g})\) (c) \(2 \mathrm{KNO}_{3}\) (s) \(\rightleftharpoons 2 \mathrm{KNO}_{2}\) (s) \(+\mathrm{O}_{2}\) (g)

Write the equilibrium expressions \(K_{c}\) for the following reactions. (a) \(\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})\) (b) \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{Br}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HBr}(\mathrm{g})\) (c) \(2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g})=2 \mathrm{SO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)

Predict whether each of the following equilibria will shift toward products or reactants with a temperature increase. (a) \(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{~g})\), \(\Delta H^{\circ}=+206 \mathrm{~kJ}\) (b) \(\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})=\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\), \(\Delta H^{2}=-41 \mathrm{~kJ}\) (c) \(2 \mathrm{SO}_{2}\) (g) \(+\mathrm{O}_{2}\) (g) \(=2 \mathrm{SO}_{3}\) (g), \(\Delta H^{\circ}=-198 \mathrm{~kJ}\)

Calculate the standard reaction frec cnergy for each of the following reactions: (a) \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g}) \neq 2 \mathrm{HI}(\mathrm{g}), K=160\) at \(500 \mathrm{~K}\) (b) \(\mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NO}_{2}(\mathrm{~g}), K=47.9\) at \(400 \mathrm{~K}\)

Write the reaction quotients \(Q_{c}\) for (a) \(\mathrm{Cu}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightarrow \mathrm{CuCl}_{2}(\mathrm{~s})\) (b) \(\mathrm{NH}_{4} \mathrm{NO}_{2}\) (s) \(\rightarrow \mathrm{N}_{2} \mathrm{O}\) (g) \(+2 \mathrm{H}_{2} \mathrm{O}\) (g) (c) \(\mathrm{MgCO}_{3}(\mathrm{~s}) \rightarrow \mathrm{MgO}\) (s) \(+\mathrm{CO}_{2}\) (g)

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