Predict whether each of the following equilibria will shift toward products or reactants with a temperature increase. (a) \(\mathrm{N}_{2} \mathrm{O}_{4}(g)=2 \mathrm{NO}_{2}(g), \Delta H^{\circ}=+57 \mathrm{~kJ}\) (b) \(\mathrm{X}_{2}(\mathrm{~g})=2 \mathrm{X}(\mathrm{g})\), where \(\mathrm{X}\) is a halogen (c) \(\mathrm{Ni}(\mathrm{s})+4 \mathrm{CO}(\mathrm{g})=\mathrm{Ni}(\mathrm{CO})_{4}(\mathrm{~g}), \Delta \mathrm{H}^{+}=-161 \mathrm{~kJ}\) (d) \(\mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{NH}_{3}(\mathrm{~g}) \rightleftharpoons \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}(\mathrm{~s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\), \(\Delta H^{\circ}=-90 \mathrm{~kJ}\)

Short Answer

Expert verified
(a) Shifts toward products. (b) Shifts toward products. (c) Shifts toward reactants. (d) Shifts toward reactants.

Step by step solution

01

Identify the Reaction Type

For each reaction, determine if it is endothermic or exothermic. Endothermic reactions absorb heat, so \( \Delta H \) is positive. Exothermic reactions release heat, so \( \Delta H \) is negative.
02

Apply Le Chatelier's Principle for Temperature Change

Le Chatelier's Principle states that if a system at equilibrium is disturbed, it will adjust itself to diminish the change. An increase in temperature adds heat to the system, shifting the equilibrium to favor the reaction that absorbs heat (endothermic) and vice versa.
03

Predict Equilibrium Shift for (a)

Since \( \Delta H^{\circ} \) is positive (+57 kJ), reaction (a) is endothermic. Increasing the temperature favors the formation of products.
04

Predict Equilibrium Shift for (b)

Without a \( \Delta H \) value provided, it is assumed that breaking an \( \text{X}_2 \) bond to form two \( \text{X} \) atoms is endothermic. Increasing temperature will shift the equilibrium toward the products.
05

Predict Equilibrium Shift for (c)

Since \( \Delta H^{+} \) is negative (-161 kJ), reaction (c) is exothermic. Increasing the temperature will favor the reactants to absorb the extra heat.
06

Predict Equilibrium Shift for (d)

Given that \( \Delta H^{\circ} \) is negative (-90 kJ), reaction (d) is exothermic. Increasing the temperature will favor the formation of reactants.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Understanding chemical equilibrium is critical for anyone studying chemistry. It refers to a state where the rate of the forward reaction equals the rate of the reverse reaction, resulting in no net change in the concentrations of reactants and products. This dynamic equilibrium is not a static situation; instead, reactions continue to occur, but with no overall effect on the concentrations.

For instance, consider the reaction \( N_2O_4(g) \leftrightarrow 2 NO_2(g) \) in our exercise. At equilibrium, the breakdown of \( N_2O_4 \) to form \( NO_2 \) molecules occurs at the same rate as the formation of \( N_2O_4 \) from \( NO_2 \) molecules. However, if we change the conditions, such as temperature, pressure, or concentrations, the equilibrium will shift to re-establish itself according to Le Chatelier's Principle.
Endothermic and Exothermic Reactions
Reactions can be categorized based on their energy changes as either endothermic or exothermic. Endothermic reactions absorb energy from their surroundings, typically in the form of heat, and are characterized by a positive enthalpy change (\(\Delta H > 0\)). On the other hand, exothermic reactions release energy into their surroundings, with a negative enthalpy change (\(\Delta H < 0\)).

When a reaction absorbs heat, like our example \( N_2O_4(g) \leftrightarrow 2 NO_2(g) \) with \(\Delta H^\circ = +57 \text{kJ}\), introducing additional heat (increasing temperature) will shift the equilibrium towards the products to consume this extra heat. Conversely, for an exothermic reaction such as \( Ni(s) + 4 CO(g) \leftrightarrow Ni(CO)_4(g) \) with \(\Delta H^+ = -161 \text{kJ}\), adding heat will shift the equilibrium towards the reactants.
Equilibrium Shifts and Temperature
Le Chatelier's Principle plays a key role when it comes to equilibrium shifts due to temperature changes. It essentially states that if an external condition (like temperature) is changed, the equilibrium will shift in a direction that tends to reduce that change.

When the temperature of an endothermic reaction is increased, the equilibrium shifts towards the products to absorb the added heat. Conversely, when the temperature of an exothermic reaction is increased, the equilibrium shifts towards the reactants to release the heat. This understanding helps us predict the behavior of a given reaction when it undergoes temperature changes, as showcased in the step by step solution for our exercise.
Thermochemistry
Thermochemistry is the study of energy and heat associated with chemical reactions and physical changes in matter. It is a branch of thermodynamics that focuses on the heat evolved or absorbed in chemical processes. The enthalpy change (\(\Delta H\)) of a reaction indicates whether the reaction is endothermic or exothermic, and it is a crucial concept in understanding reaction energetics.

For example, reaction (d) \( CO_2(g) + 2 NH_3(g) \leftrightarrows CO(NH_2)_2(s) + H_2O(g) \) with \(\Delta H^\circ = -90 \text{kJ}\) releases energy; hence it's exothermic. Thermochemistry allows us to quantify these energy changes and predict how changes in temperature will affect the equilibrium in terms of shifting towards reactants or products.

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Most popular questions from this chapter

Write the equilibrium expressions \(K_{c}\) for the following reactions. (a) \(\mathrm{CO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons \mathrm{COCl}(\mathrm{g})+\mathrm{Cl}(\mathrm{g})\) (b) \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{Br}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HBr}(\mathrm{g})\) (c) \(2 \mathrm{H}_{2} \mathrm{~S}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g})=2 \mathrm{SO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)

The equilibrium constant for the reaction \(2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})=2 \mathrm{SO}_{3}(\mathrm{~g})\) has the value \(K=2.5 \times 10^{10}\) at \(500 \mathrm{~K}\). Find the value of \(K\) for each of the following reactions at the same temperature. (a) \(\mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})=\mathrm{SO}_{3}(\mathrm{~g})\) (b) \(\mathrm{SO}_{3}(\mathrm{~g})=\mathrm{SO}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g})\) (c) \(3 \mathrm{SO}_{2}(\mathrm{~g})+\frac{3}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightleftharpoons 3 \mathrm{SO}_{3}(\mathrm{~g})\)

Given that \(K_{c}=61\) for the reaction \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})\) at \(500 \mathrm{~K}\), calculate whether more ammonia will tend to form when a mixture of composition \(2.23 \times 10^{-3} \mathrm{~mol} \cdot \mathrm{L}^{-1} \mathrm{~N}_{2}\), \(1.24 \times 10^{-3} \mathrm{~mol} \cdot \mathrm{L}^{-1} \mathrm{H}_{2}\), and \(1.12 \times 10^{-4} \mathrm{~mol} \cdot \mathrm{L}^{-1}\) \(\mathrm{NH}_{3}\) is present in a container at \(500 \mathrm{~K}\).

At \(1565 \mathrm{~K}\), the equilibrium constants for the reactions (1) \(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\) and \((2)\) \(2 \mathrm{CO}_{2}(\mathrm{~g})=2 \mathrm{CO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g})\) are \(1.6 \times 10^{-11}\) and \(1.3 \times 10^{-10}\), respectively. (a) What is the equilibrium constant for the reaction (3) \(\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})=\) \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})+\mathrm{CO}(\mathrm{g})\) at that temperature? (b) Show that the manner in which equilibrium constants are calculated is consistent with the manner in which the \(\Delta G_{1}^{\circ}\) values are calculated when combining two or more equarions by determining \(\Delta G_{e}{ }^{\circ}\) for \((1)\) and \((2)\) and using those values to calculare \(\Delta G,{ }^{\circ}\) and \(K_{3}\) for reaction (3).

Calculate the equilibrium constant ar \(25^{\circ} \mathrm{C}\) for cach of the following reactions from data available in Appendix 2A. (a) the combustion of hydrogen: \(2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\) (b) the oxidation of carbon monoxide: \(2 \mathrm{CO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{CO}_{2}(\mathrm{~g})\) (c) the decompostion of limestone: \(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightarrow \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\)

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