Predict whether each of the following equilibria will shift toward products or reactants with a temperature increase. (a) \(\mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{~g})\), \(\Delta H^{\circ}=+206 \mathrm{~kJ}\) (b) \(\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})=\mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2}(\mathrm{~g})\), \(\Delta H^{2}=-41 \mathrm{~kJ}\) (c) \(2 \mathrm{SO}_{2}\) (g) \(+\mathrm{O}_{2}\) (g) \(=2 \mathrm{SO}_{3}\) (g), \(\Delta H^{\circ}=-198 \mathrm{~kJ}\)

Short Answer

Expert verified
For reaction (a), the equilibrium will shift toward the products. For reactions (b) and (c), which are exothermic, the equilibrium will shift toward the reactants with an increase in temperature.

Step by step solution

01

Understanding Le Chatelier's Principle

Le Chatelier's Principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change. In the context of temperature, if heat is added to the system, the equilibrium will shift in the direction that absorbs heat (endothermic reaction), and if heat is removed, it will shift to the direction that releases heat (exothermic reaction).
02

Analyzing Reaction (a)

For the reaction \(\mathrm{CH}_{4}(\mathrm{g})+\mathrm{H}_{2}O(\mathrm{g}) \rightleftharpoons \mathrm{CO}(\mathrm{g})+3\mathrm{H}_{2}(\mathrm{g})\), with \(\Delta H^{\circ}=+206\ \mathrm{kJ}\), the forward reaction is endothermic. According to Le Chatelier's Principle, increasing the temperature will shift the equilibrium toward the products which absorb the added heat.
03

Analyzing Reaction (b)

For the reaction \(\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}O(\mathrm{g}) \rightleftharpoons \mathrm{CO}_{2}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g})\), with \(\Delta H^{\circ}=-41\ \mathrm{kJ}\), the forward reaction is exothermic. Increasing the temperature will cause the equilibrium to shift toward the reactants, as the system tries to absorb the added heat by favoring the endothermic reverse reaction.
04

Analyzing Reaction (c)

For the reaction \(2 \mathrm{SO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{SO}_{3}(\mathrm{g})\), with \(\Delta H^{\circ}=-198\ \mathrm{kJ}\), the forward reaction is exothermic. As with reaction (b), increasing the temperature will shift the equilibrium toward the reactants because the system will absorb the heat through the endothermic backward reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
Chemical equilibrium occurs in a reversible chemical reaction when the rates of the forward and reverse reactions are equal, resulting in no net change in the concentrations of reactants and products over time. This dynamic state can be visualized as a balance; although the reaction continues at a molecular level, the macroscopic quantities of reactants and products remain constant.

The position of equilibrium is not static and can be affected by changes in temperature, pressure, or concentration. This adaptability is described by Le Chatelier's Principle, which predicts how the equilibrium position will shift in response to such changes. Understanding this principle helps us to control product formation in industrial chemical processes and anticipate the behavior of natural systems under stress.
Endothermic Reactions
Endothermic reactions are chemical processes that absorb energy from the surroundings, typically in the form of heat. The absorbed energy is a critical factor for the reaction to proceed. These reactions result in a cooling effect, with common examples including photosynthesis and the dissolving of salts.

According to Le Chatelier's Principle, an increase in temperature supplies additional energy to the system, thus favoring the endothermic forward reaction. This causes a shift in the equilibrium to the right, toward the formation of products, in an attempt to offset the added heat. In the classroom or laboratory, recognizing a reaction as endothermic allows students to predict and understand the implications of temperature changes on the position of equilibrium.
Exothermic Reactions
Exothermic reactions are the opposite of endothermic reactions; they release energy into the surroundings, again often in the form of heat. When exothermic reactions occur, they typically raise the temperature of the environment. Burning fuels, combustion, and the setting of cement are all examples of exothermic reactions.

If the temperature of an exothermic reaction's system is increased, Le Chatelier's Principle indicates that the equilibrium will shift towards the reactants to absorb the excess heat. Consequently, the formation of products is suppressed as the system accommodates the change by favoring the reverse reaction. This concept is vitally important for safety and productivity in industrial chemical processes that are exothermic in nature.
Equilibrium Shift
The equilibrium shift refers to the change in the position of equilibrium in response to an external stress, as predicted by Le Chatelier's Principle. External stresses can include modifications in concentration, pressure, and temperature. When these changes occur, the system reacts in such a way as to minimize the imposed stress and reestablish a state of balance.

An increased concentration of reactants pushes equilibrium toward product formation, whereas an increase in the concentration of products shifts it back toward reactants. Similarly, altering the pressure in a system of gaseous reactants and products will drive the equilibrium to the side with fewer gas molecules if pressure is increased, or to the side with more gas molecules if the pressure is decreased. Temperature changes induce a shift toward the endothermic direction when increased and exothermic when decreased. This understanding is essential to manage the yield of reactions in real-world applications from industrial synthesis to pharmacological drug design.
Reaction Enthalpy
Reaction enthalpy, denoted as \( \Delta H \), quantifies the overall heat change during a chemical reaction. It is one of the primary indicators of whether a chemical reaction is endothermic or exothermic. A positive \( \Delta H \) indicates an endothermic reaction where heat is absorbed from the surroundings. In contrast, a negative \( \Delta H \) is characteristic of exothermic reactions where heat is released into the surroundings.

The value of \( \Delta H \) also informs predictions on how changes in temperature will affect chemical equilibrium according to Le Chatelier's Principle. A high positive \( \Delta H \) value suggests that raising the temperature will significantly shift the equilibrium toward the products, while a high negative value indicates a substantial shift toward the reactants when the temperature is increased. This concept links the abstract idea of energy changes to tangible shifts in chemical systems, enabling a deeper comprehension of chemical reactions and their manipulation under different conditions.

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Most popular questions from this chapter

\( \mathrm{~A} 3.00-\mathrm{L}\) reaction vessel is filled with \(0.150 \mathrm{~mol}\) \(\mathrm{CO}, 0.0900 \mathrm{~mol} \mathrm{H}_{2}\), and \(0.180 \mathrm{~mol} \mathrm{CH}_{3} \mathrm{OH}\). Equilibrium is reached in the presence of a zinc oxidechromium(III) oxide catalyst; and at \(300^{\circ} \mathrm{C}, K_{c}=\) \(1.1 \times 10^{-2}\) for the reaction, \(\mathrm{CO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons\) \(\mathrm{CH}_{3} \mathrm{OH}(\mathrm{g})\). (a) As the reaction approaches equilibrium, will the molar concentration of \(\mathrm{CH}_{3} \mathrm{OH}\) increase, decrease, or remain unchanged? (b) What is the equilibrium composition of the mixture?

If \(Q=1.0 \times 10^{50}\) for the reaction \(\mathrm{C}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g})\) at \(25^{\circ} \mathrm{C}\), will the reaction have a tendency to form products or reactants, or will it be at equilibrium?

A \(0.10-\mathrm{mol}\) sample of pure czone, \(\mathrm{O}_{3}\), is placed in a sealed \(1.0\) - L container and the reaction \(2 \mathrm{O}_{3}(\mathrm{~g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{~g})\) is allowed to reach equilihrium. A \(0.50-\mathrm{mol}\) sample of pure ozone is placed in a second 1.0-L container at the same temperature and allowed to reach equilibrium. Without doing any calculations, predict which of the following will be different in the two containers at equilibrium. Which will be the same? Explain each of your answers: (a) amount of \(\mathrm{O}_{2}\); (b) concentration of \(\mathrm{O}_{2}\); (c) the ratio \(\left[\mathrm{O}_{2}\right] /\left[\mathrm{O}_{3}\right]\); (d) the ratio \(\left.\left[\mathrm{O}_{2}\right]^{3} / \mathrm{O}_{3}\right]^{2} ;\) (e) the ratio \(\left|\mathrm{O}_{3}\right|^{2} /\left[\mathrm{O}_{2}\right]^{3}\).

If \(Q=1.0\) for the reaction \(N_{2}(g)+O_{2}(g) \rightarrow\) \(2 \mathrm{NO}(\mathrm{g})\) at \(25^{\circ} \mathrm{C}\), will the reaction have a tendency to form products or reactants, or will it be at equilibrium?

\( \mathrm{~A} 25.0 \mathrm{~g}\) sample of ammonium carbamate, \(\mathrm{NH}_{4}\left(\mathrm{NH}_{2} \mathrm{CO}_{2}\right)\), was placed in an evacuated \(0.250-\mathrm{L}\). flask and kept at \(25^{\circ} \mathrm{C}\). At equilibrium, the flask contained \(17.4 \mathrm{mg}\) of \(\mathrm{CO}_{2}\). What is the value of \(K_{c}\) for the decomposition of ammonium carbamate into ammonia and carbon dioxide? The reaction is \(\mathrm{NH}_{4}\left(\mathrm{NH}_{2} \mathrm{CO}_{2}\right)(\mathrm{s})=2 \mathrm{NH}_{3}(\mathrm{~g})+\mathrm{CO}_{2}(\mathrm{~g}) .\)

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