Chapter 3: Problem 2
Liquid A decomposes by first-order kinetics, and in a batch reactor \(50 \%\) of \(A\) is converted in a 5 -minute run. How much longer would it take to reach 75\% conversion?
Short Answer
Expert verified
The rate constant \(k\) calculated from 50% conversion is \(\frac{\ln(2)}{5}\). For 75% conversion, the total time is \(\frac{\ln(4)}{\ln(2)/5}\) minutes. The extra time needed is the difference between this total time and the initial 5 minutes.
Step by step solution
01
Understand First-Order Kinetics
First-order kinetics implies that the rate of reaction is directly proportional to the concentration of the reactant. The rate law is given by the equation \( -\frac{d[A]}{dt} = k[A] \) where \( [A] \) is the concentration of reactant A, \(t\) is time, and \(k\) is the rate constant.
02
Apply the Integrated Rate Law for First-Order Reactions
For first-order reactions, the integrated rate law is expressed as \( \ln\left(\frac{[A]_0}{[A]}\right) = kt \) where \( [A]_0 \) is the initial concentration of A, \( [A] \) is the concentration of A at time \(t\), and \(k\) is the rate constant.
03
Calculate the Reaction Time for 50% Conversion
Using the equation from Step 2, calculate the time required to reach 50% conversion. Here, \( \frac{[A]}{[A]_0} = \frac{50}{100} \) because 50% of A is converted, thus \( \ln\left(2\right) = kt \).
04
Solve for the Rate Constant \(k\)
Substitute the known values into the equation from Step 3 to find the rate constant \(k\). We have \(t = 5\) minutes when 50% is converted, so \(k = \frac{\ln(2)}{5}\) min\(^{-1}\).
05
Calculate the Reaction Time for 75% Conversion
For 75% conversion, \( \frac{[A]}{[A]_0} = \frac{25}{100} = \frac{1}{4} \), thus \( \ln\left(4\right) = kt \).
06
Solve for \(t\) at 75% Conversion
Using the rate constant \(k\) from Step 4, substitute into the equation from Step 5 to find the time \(t\) required for 75% conversion. Solve the equation \(t = \frac{\ln(4)}{k}\) for \(t\).
07
Determine the Extra Time Required
To find out how much longer it takes to reach 75% conversion compared to 50% conversion, subtract the time for 50% conversion (5 minutes) from the total time calculated for 75% conversion.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Reaction Engineering
Chemical Reaction Engineering is a core branch of chemical engineering that focuses on the design and optimization of chemical reactors. It's concerned with understanding and utilizing the principles of chemical kinetics and thermodynamics to predict the outcomes of chemical reactions and to design the equipment where these reactions take place. To achieve a designed reaction performance, engineers must balance factors such as concentration, temperature, and pressure, all while ensuring safety and cost-effectiveness.
First-order kinetics is an essential concept within this field. In reactions governed by first-order kinetics, the rate at which a reactant is consumed is directly proportional to its concentration at that instant. This fundamental principle allows engineers to make accurate predictions regarding reaction rates and the time required to complete a reaction under specific conditions, which is crucial for reactor design and scaling up processes from the laboratory to the industrial scale.
First-order kinetics is an essential concept within this field. In reactions governed by first-order kinetics, the rate at which a reactant is consumed is directly proportional to its concentration at that instant. This fundamental principle allows engineers to make accurate predictions regarding reaction rates and the time required to complete a reaction under specific conditions, which is crucial for reactor design and scaling up processes from the laboratory to the industrial scale.
Integrated Rate Law
The Integrated Rate Law is a mathematical expression that relates the concentrations of reactants to time in a chemical reaction. For first-order kinetics, the integrated rate law is a powerful tool that helps us understand how concentrations change over time. The law is given by the equation \( \ln(\frac{[A]_0}{[A]}) = kt \), where \( [A]_0 \) is the initial concentration of the reactant, \( [A] \) is the concentration at time \( t \), and \( k \) is the first-order rate constant.
In practice, the integrated rate law allows us to calculate the time needed for a reactant to reach a particular concentration, providing insights into the kinetics of the system. Manipulating this equation gives us a direct link between the measurable quantity of concentration and the rate at which that quantity changes—an invaluable relationship for predicting the course of a chemical reaction in a given time frame.
In practice, the integrated rate law allows us to calculate the time needed for a reactant to reach a particular concentration, providing insights into the kinetics of the system. Manipulating this equation gives us a direct link between the measurable quantity of concentration and the rate at which that quantity changes—an invaluable relationship for predicting the course of a chemical reaction in a given time frame.