The U.S. trade deficit at the beginning of 2005 was \(\$ 475,000,000\) . If the wealthiest 1.00\(\%\) of the U.S. population \((297,000,000)\) contributed an equal amount of money to bring the trade deficit to \(\$ 0,\) how many dollars would each person contribute? If one of these people were to pay his or her share in nickels only, how many nickels are needed? Another person contribute? If one of these people were to pay his or her share in nickels only, how many nickels are needed? Another person living abroad at the time decides to pay in pounds sterling (f). How many pounds sterling does this person contribute (assume a conversion rate of \(1 \mathrm{f}=\$ 1.869\) )?

Short Answer

Expert verified
First, we calculate the number of wealthy contributors: \(Number\: of\: wealthy\: contributors = 297{,}000{,}000 * 1.00\% = 2{,}970{,}000 \) Next, we find the contribution of each wealthy person: \(Contribution\: per\: person = \frac{475{,}000{,}000}{2{,}970{,}000} \approx \$159{,}932.32 \) We then calculate the number of nickels needed for the contribution: \(Number\: of\: nickels = \frac{159{,}932.32}{0.05} = 3{,}198{,}646 \) Finally, we convert the contribution in dollars to pounds sterling: \(Pounds\: Sterling\: Contribution = \frac{159{,}932.32}{1.869} \approx 85{,}543.01 \) So, each person would contribute approximately $159,932.32, which is equivalent to 3,198,646 nickels or £85,543.01 pounds sterling.

Step by step solution

01

Determine the number of wealthy contributors to the trade deficit

First, we need to find out how many people constitute the wealthiest 1% of the 297,000,000 population. \(Number\: of\: wealthy\: contributors = 297{,}000{,}000 * 1.00\% \)
02

Calculate the contribution of each wealthy person

We need to find out how much each of the wealthiest 1% would need to contribute to cover the entire trade deficit. \(Contribution\: per\: person = \frac{\text{Total Deficit}}{\text{Number of Wealthy Contributors}}\)
03

Calculate the number of nickels needed for the contribution

Next, we need to find out how many nickels would be required for each person's contribution. Since one nickel is worth $0.05, we can divide the contribution per person by the value of a nickel. \(Number\: of\: nickels = \frac{\text{Contribution per person}}{Value\: of\: a\: nickel}\)
04

Convert the contribution in dollars to pounds sterling

Finally, we need to convert the contribution per person in dollars to pounds sterling using the given conversion rate of 1 f = $1.869. \(Pounds\: Sterling\: Contribution = \frac{\text{Contribution per person}}{\text{Conversion Rate}}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At room temperature the element bromine, \(\mathrm{Br}_{2},\) is a liquid with a density of 3.12 \(\mathrm{g} / \mathrm{cm}^{3} .\) Calculate the mass of 125 \(\mathrm{mL}\) of bromine. What volume does 85.0 \(\mathrm{g}\) of bromine occupy?

Is there a difference between a homogeneous mixture of hydrogen and oxygen in a 2;1 ratio and a sample of water vapor? Explain.

Perform the following mathematical operations, and express each result to the correct number of significant figures. a. \(\frac{0.102 \times 0.0821 \times 273}{1.01}\) b. \(0.14 \times 6.022 \times 10^{23}\) c. $4.0 \times 10^{4} \times 5.021 \times 10^{-3} \times 7.34993 \times 10^{2}$ d. \(\frac{2.00 \times 10^{6}}{3.00 \times 10^{-7}}\)

What data would you need to estimate the money you would spend on gasoline to drive your car from New York to Chicago? Provide estimates of values and a sample calculation.

You have two beakers, one filled to the 100-mL mark with sugar (the sugar has a mass of 180.0 g) and the other filled to the 100-mL mark with water (the water has a mass of 100.0 g). You pour all the sugar and all the water together in a bigger beaker and stir until the sugar is completely dissolved. a. Which of the following is true about the mass of the solution? Explain. i. It is much greater than 280.0 g. ii. It is somewhat greater than 280.0 g. iii. It is exactly 280.0 g. iv. It is somewhat less than 280.0 g. v. It is much less than 280.0 g. b. Which of the following is true about the volume of the solution? Explain. i. It is much greater than 200.0 mL. ii. It is somewhat greater than 200.0 mL. iii. It is exactly 200.0 mL. iv. It is somewhat less than 200.0 mL. v. It is much less than 200.0 mL.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free