A rectangular block has dimensions 2.9 $\mathrm{cm} \times 3.5 \mathrm{cm} \times\( 10.0 \)\mathrm{cm} .\( The mass of the block is 615.0 \)\mathrm{g} .$ What are the volume and density of the block?

Short Answer

Expert verified
The volume of the rectangular block is \(101.5 cm^3\), and its density is \(6.06 \frac{g}{cm^3}\).

Step by step solution

01

Find the volume of the block

To find the volume of the block, we can use the formula for the volume of a rectangular prism, which is: \( Volume = Length × Width × Height\) We are given the dimensions of the block as 2.9 cm × 3.5 cm × 10.0 cm. By substituting these values into the formula, we can calculate the volume: \( Volume = 2.9 cm × 3.5 cm × 10.0 cm\)
02

Calculate the volume

Now, we can calculate the volume by multiplying all the given dimensions: \( Volume = 2.9 cm × 3.5 cm × 10.0 cm = 101.5 cm^3\) So, the block has a volume of 101.5 cm³.
03

Find the density of the block

As we know, the formula to find the density is: \( Density = \frac{Mass}{Volume}\) We are given the mass of the block as 615.0 g, and we just calculated the volume to be 101.5 cm³. By substituting these values into the formula, we can calculate the density: \( Density = \frac{615.0 g}{101.5 cm^3}\)
04

Calculate the density

Now, we can calculate the density of the block by dividing the mass by the volume: \( Density = \frac{615.0 g}{101.5 cm^3} = 6.06 \frac{g}{cm^3}\) So, the block has a density of 6.06 g/cm³. In conclusion, the volume of the block is 101.5 cm³, and its density is 6.06 g/cm³.

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