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Chapter 1: Problem 74

At room temperature the element bromine, \(\mathrm{Br}_{2},\) is a liquid with a density of 3.12 \(\mathrm{g} / \mathrm{cm}^{3} .\) Calculate the mass of 125 \(\mathrm{mL}\) of bromine. What volume does 85.0 \(\mathrm{g}\) of bromine occupy?

Short Answer

Expert verified
The mass of 125 mL of bromine is 390 g, and the volume occupied by 85.0 g of bromine is approximately 27.2 cm³.

Step by step solution

01

Convert volume to an appropriate unit.

The given volume is in mL, but the units for density are g/cm³. So, the volume should also be in cm³. We can convert the volume to cm³ using the conversion factor 1 cm³ = 1 mL: \(V = 125\,\text{mL} \times \frac{1\,\text{cm}^{3}}{1\,\text{mL}} = 125\,\text{cm}^3\)
02

Calculate the mass of bromine.

Using the given density and volume, we can calculate the mass using the formula: Mass = Density × Volume \(m = 3.12\,\frac{\text{g}}{\text{cm}^3} \times 125\,\text{cm}^3\) \(m = 390\,\text{g}\) So, the mass of 125 mL of bromine is 390 g.
03

Calculate the volume of 85.0 g of bromine.

Using the given density and mass, we can calculate the volume using the formula: Volume = Mass / Density \(V = \frac{85.0\,\text{g}}{3.12\,\frac{\text{g}}{\text{cm}^{3}}}\) \(V \approx 27.2\,\text{cm}^{3}\) So, the volume occupied by 85.0 g of bromine is approximately 27.2 cm³.

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