During a very cold winter, the temperature may remain below freezing for extended periods. However, fallen snow can still disappear, even though it cannot melt. This is possible because a solid can vaporize directly, without passing through the liquid state. Is this process (sublimation) a physical or a chemical change?

Short Answer

Expert verified
Sublimation is a process in which a solid substance transitions directly into a gas phase without going through a liquid phase. During the sublimation process, the substance does not undergo any changes in its chemical composition. The water molecules in the solid phase (ice) transition directly to the gas phase (water vapor), but the H2O molecules remain unchanged. Since sublimation does not cause any changes in the chemical composition of the substance (snow), it can be classified as a physical change. In this process, only the state of the substance changes from the solid phase to the gas phase, while the chemical composition remains the same.

Step by step solution

01

Define physical changes

A physical change is a change in the state or properties of a substance without altering its composition. Examples of physical changes include a change of state (solid, liquid, gas, or plasma), shape, size, or color. However, the substance's chemical composition remains the same. #Step 2: Define chemical changes#
02

Define chemical changes

A chemical change, also known as a chemical reaction, is a process in which one or more substances are transformed into new substances with different properties and composition. Examples of chemical changes include burning, rusting, and oxidation. During a chemical change, the chemical composition of the substance(s) is altered. #Step 3: Understand sublimation process#
03

Understand sublimation process

Sublimation is a process in which a solid substance transitions directly into a gas phase without going through a liquid phase. This occurs when the temperature and pressure conditions allow the molecules in the solid phase to gain enough energy to move directly into the gas phase. An example of sublimation is the disappearance of snow or frost without melting under certain conditions. #Step 4: Analyze the change in composition during sublimation#
04

Analyze the change in composition during sublimation

During the sublimation process, the substance (in this case, snow) does not undergo any changes in its chemical composition. The water molecules in the solid phase (ice) transition directly to the gas phase (water vapor), but the H2O molecules remain unchanged. #Step 5: Determine if sublimation is a physical or chemical change#
05

Determine if sublimation is a physical or chemical change

Since sublimation does not cause any changes in the chemical composition of the substance (snow), it can be classified as a physical change. In this process, only the state of the substance changes from the solid phase to the gas phase, while the chemical composition remains the same.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You have two beakers, one filled to the 100-mL mark with sugar (the sugar has a mass of 180.0 g) and the other filled to the 100-mL mark with water (the water has a mass of 100.0 g). You pour all the sugar and all the water together in a bigger beaker and stir until the sugar is completely dissolved. a. Which of the following is true about the mass of the solution? Explain. i. It is much greater than 280.0 g. ii. It is somewhat greater than 280.0 g. iii. It is exactly 280.0 g. iv. It is somewhat less than 280.0 g. v. It is much less than 280.0 g. b. Which of the following is true about the volume of the solution? Explain. i. It is much greater than 200.0 mL. ii. It is somewhat greater than 200.0 mL. iii. It is exactly 200.0 mL. iv. It is somewhat less than 200.0 mL. v. It is much less than 200.0 mL.

You go to a convenience store to buy candy and find the owner to be rather odd. He allows you to buy pieces in multiples of four, and to buy four, you need $0.23. He only allows you to do this by using 3 pennies and 2 dimes. You have a bunch of pennies and dimes, and instead of counting them, you decide to weigh them. You have 636.3 g of pennies, and each penny weighs 3.03 g. Each dime weighs 2.29 g. Each piece of candy weighs 10.23 g. a. How many pennies do you have? b. How many dimes do you need to buy as much candy as possible? c. How much should all these dimes weigh? d. How many pieces of candy could you buy? (number of dimes from part b) e. How much would this candy weigh? f. How many pieces of candy could you buy with twice as many dimes?

Round off each of the following numbers to the indicated number of significant digits, and write the answer in standard scientific notation. a. 0.00034159 to three digits b. \(103.351 \times 10^{2}\) to four digits c. 17.9915 to five digits d. \(3.365 \times 10^{5}\) to three digits

Which of the following are exact numbers? a. There are 100 cm in 1 m. b. One meter equals 1.094 yards. c. We can use the equation $$^\circ \mathrm{F}=\frac{9}{5}^{\circ} \mathrm{C}+32$$ to convert from Celsius to Fahrenheit temperature. Are the numbers \(\frac{9}{5}\) and 32 exact or inexact? d. \(\pi=3.1415927\)

True or false? For mathematical operation performed on two measurements, the number of significant figures in the answer is the same as the least number of significant figures in either of the measurements. Explain your answer.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free