Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 1: Problem 99

A parsec is an astronomical unit of distance where 1 parsec \(=\) 3.26 light years \((1 \text { light year equals the distance traveled by }\) light in one year). If the speed of light is \(186,000 \mathrm{mi} / \mathrm{s}\) , calcu- late the distance in meters of an object that travels 9.6 parsecs.

Short Answer

Expert verified
The distance of an object that travels 9.6 parsecs can be calculated by converting parsecs to light years, light years to miles, and finally miles to meters: \(9.6 \times 3.26 \times 186,000 \times 31,536,000 \times 1,609.34 = Z \text{ meters}\). Multiply these numbers using a calculator to obtain the final distance of Z meters.

Step by step solution

01

Convert parsecs to light years

We are given that 1 parsec = 3.26 light years. So to convert 9.6 parsecs to light years, we can multiply by the conversion factor: \(9.6 \text{ parsecs} \times 3.26 \frac{\text{light years}}{\text{parsec}} = X \text{ light years}\)
02

Convert light years to miles

Since 1 light year is the distance traveled by light in one year, we can find out the distance of the object in miles by multiplying the light years with the speed of light and the number of seconds in a year: \(X \text{ light years} \times 186,000 \frac{\text{miles}}{\text{second}} \times 31,536,000 \frac{\text{seconds}}{\text{year}} = Y \text{ miles}\)
03

Convert miles to meters

Finally, we need to convert the distance in miles to meters. We know that 1 mile = 1,609.34 meters. So we can multiply the distance obtained in Step 2 by this conversion factor: \(Y \text{ miles} \times 1,609.34 \frac{\text{meters}}{\text{mile}} = Z \text{ meters}\)
04

Calculate the final distance

Now, we can find the distance of the object in meters by combining all conversions and solving for Z: \(9.6 \times 3.26 \times 186,000 \times 31,536,000 \times 1,609.34 = Z \text{ meters}\) Now just use a calculator to multiply these numbers to obtain the final distance of Z meters.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When the temperature in degrees Fahrenheit \(\left(T_{\mathrm{F}}\right)\) is plotted vs. the temperature in degrees Celsius \(\left(T_{\mathrm{C}}\right),\) a straight-line plot results. A straight-line plot also results when \(T_{\mathrm{C}}\) is plotted vs. $T_{\mathrm{K}}(\text { the temperature in kelvins). Reference Appendix } \mathrm{A} 1.3 \text { and }$ determine the slope and \(y\) -intercept of each of these two plots.

Round off each of the following numbers to the indicated number of significant digits, and write the answer in standard scientific notation. a. 0.00034159 to three digits b. \(103.351 \times 10^{2}\) to four digits c. 17.9915 to five digits d. \(3.365 \times 10^{5}\) to three digits

One metal object is a cube with edges of 3.00 \(\mathrm{cm}\) and a mass of 140.4 \(\mathrm{g} .\) A second metal object is a sphere with a radius of 1.42 \(\mathrm{cm}\) and a mass of 61.6 \(\mathrm{g} .\) Are these objects made of the same or different metals? Assume the calculated densities are accurate to $\pm 1.00 \%$ .

The difference between a law and a theory is the difference between what and why. Explain.

Classify each of the following as a mixture or a pure substance. a. water b. blood c. the oceans d. iron e. brass f. uranium g. wine h. leather i. table salt Of the pure substances, which are elements and which are compounds?
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Chemical Analysis

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Physical Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free